Subject: Mathematics | Level: GCSE | Exam Board: Edexcel
Geometry and Measures is a fundamental GCSE Mathematics topic covering everything from basic shape properties to advanced trigonometry, circle theorems, and vector calculus. Mastering this topic is essential for unlocking top grades, as examiners frequently use it to test multi-step problem-solving and logical reasoning skills.
Revision Notes & Key Concepts
Key Terms & Definitions
- Hypotenuse
- The longest side of a right-angled triangle, always situated opposite the right angle.
- Tangent (to a circle)
- A straight line that touches the circumference of a circle at exactly one point.
- Similar Shapes
- Shapes that have the exact same angles and proportional side lengths; one is an enlargement of the other.
- Congruent Shapes
- Shapes that are exactly the same size and shape. All corresponding angles and side lengths are equal.
- Vector
- A quantity that has both magnitude (size) and direction.
- Bearing
- An angle measured clockwise from North, always written using three digits (e.g., 045°).
Worked Examples
Worked Example
Question: Calculate the volume of a cylinder with a diameter of 12 cm and a height of 15 cm. Give your answer to 3 significant figures. (3 marks)
Solution: Step 1: Identify the radius. The diameter is 12 cm, so the radius $r = 12 \div 2 = 6$ cm. Step 2: State the formula for the volume of a cylinder: $V = \pi r^2 h$. Step 3: Substitute the values into the formula: $V = \pi \times 6^2 \times 15 = \pi \times 36 \times 15 = 540\pi$. Step 4: Calculate the decimal value: $540\pi \approx 1696.460...$ Final answer: 1700 cm³ (to 3 s.f.)
Worked Example
Question: In triangle ABC, AB = 7cm, BC = 10cm, and angle ABC = 42°. Calculate the length of AC. Give your answer to 1 decimal place. (3 marks)
Solution: Step 1: Identify the correct rule. We have two sides and the included angle, and we want the opposite side. We must use the Cosine Rule: $a^2 = b^2 + c^2 - 2bc \cos A$. Step 2: Substitute the known values. Let $AC = b$. So, $b^2 = 7^2 + 10^2 - 2(7)(10)\cos(42°)$. Step 3: Calculate the right-hand side. $b^2 = 49 + 100 - 140\cos(42°) = 149 - 104.040... = 44.959...$ Step 4: Square root to find $b$. $b = \sqrt{44.959...} = 6.705...$ Final answer: 6.7 cm
Worked Example
Question: A, B, C and D are points on the circumference of a circle, centre O. Angle AOC = 130°. Calculate the size of angle ABC. Give a reason for your answer. (2 marks)
Solution: Step 1: Identify the relevant circle theorem. We have an angle at the centre (AOC) and an angle at the circumference (ABC) subtended by the same arc AC. Step 2: Apply the theorem. The angle at the circumference is half the angle at the centre. Angle ABC = $130° \div 2 = 65°$. Step 3: State the reason clearly. Final answer: Angle ABC = 65°. Reason: The angle at the centre is twice the angle at the circumference.
Practice Questions
Question: A solid cylinder has a radius of 4 cm and a height of 10 cm. Calculate the total surface area of the cylinder. Give your answer in terms of π. (4 marks)
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Question: Triangle ABC has sides AB = 8cm, BC = 12cm, and AC = 15cm. Calculate the size of the largest angle in the triangle. Give your answer to 1 decimal place. (4 marks)
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Question: A regular polygon has an exterior angle of 24°. Calculate the number of sides the polygon has. (2 marks)
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Question: $\mathbf{a} = \begin{pmatrix} 3 \\ -2 \end{pmatrix}$ and $\mathbf{b} = \begin{pmatrix} -1 \\ 4 \end{pmatrix}$. Calculate the vector $2\mathbf{a} - 3\mathbf{b}$. (2 marks)
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Question: A ship sails 40km on a bearing of 060°, then 30km on a bearing of 150°. Calculate the distance of the ship from its starting point. (4 marks)
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