Subject: Mathematics | Level: GCSE | Exam Board: OCR
Mastering Fractions, Decimals, and Percentages is the foundation of GCSE Mathematics. This topic unlocks marks across the entire specification, from simple conversions to complex multi-step problem solving with multipliers.
Revision Notes & Key Concepts
Key Terms & Definitions
- Integer
- A whole number. It can be positive, negative, or zero.
- Numerator
- The top number in a fraction, representing how many parts you have.
- Denominator
- The bottom number in a fraction, representing the total number of equal parts the whole is divided into.
- Reciprocal
- The reciprocal of a number is 1 divided by that number. For a fraction, it means flipping the numerator and denominator.
- Percentage Multiplier
- A decimal used to calculate a percentage of an amount or a percentage change in a single multiplication step.
- Recurring Decimal
- A decimal number that has a digit or group of digits that repeats infinitely.
Worked Examples
Worked Example
Question: Calculate $2\frac{1}{3} + 1\frac{3}{4}$. Give your answer as a mixed number in its simplest form.
Solution: Step 1: Convert mixed numbers to improper fractions. $2\frac{1}{3} = \frac{7}{3}$ $1\frac{3}{4} = \frac{7}{4}$ Step 2: Find a common denominator for 3 and 4, which is 12. $\frac{7}{3} = \frac{28}{12}$ $\frac{7}{4} = \frac{21}{12}$ Step 3: Add the numerators. $\frac{28}{12} + \frac{21}{12} = \frac{49}{12}$ Step 4: Convert back to a mixed number. $49 \div 12 = 4$ remainder $1$. Final answer: $4\frac{1}{12}$
Worked Example
Question: A shop has a sale with $20\%$ off all items. A jacket costs £52 in the sale. Calculate the original price of the jacket.
Solution: Step 1: Identify the multiplier for a $20\%$ decrease. Multiplier $= 1 - 0.20 = 0.80$. Step 2: Set up the equation. $\text{Original Price} \times 0.80 = \text{Sale Price}$ $\text{Original Price} \times 0.80 = 52$ Step 3: Rearrange to solve for the Original Price. $\text{Original Price} = 52 \div 0.80$ Step 4: Calculate the final answer. $52 \div 0.8 = 520 \div 8 = 65$. Final answer: £65
Worked Example
Question: Prove algebraically that the recurring decimal $0.2\dot{7}$ can be written as the fraction $\frac{5}{18}$.
Solution: Step 1: Set $x$ equal to the recurring decimal. Let $x = 0.2777...$ Step 2: Multiply by 10 to move the non-recurring part past the decimal point. $10x = 2.777...$ Step 3: Multiply by 100 to move one full repeating block past the decimal point. $100x = 27.777...$ Step 4: Subtract the equation in Step 2 from the equation in Step 3. $100x - 10x = 27.777... - 2.777...$ $90x = 25$ Step 5: Solve for $x$ and simplify. $x = \frac{25}{90}$ Divide numerator and denominator by 5: $x = \frac{5}{18}$
Practice Questions
Question: Convert $0.35$ to a fraction in its simplest form.
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Question: Calculate $45\%$ of £80.
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Question: A population of bacteria increases by $15\%$ every hour. If the initial population is 4000, calculate the population after 3 hours. Give your answer to the nearest whole number.
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Question: Work out $\frac{4}{5} \div \frac{2}{3}$. Give your answer as a mixed number.
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Question: In a sale, normal prices are reduced by $18\%$. The sale price of a computer is £451. Work out the normal price.
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