Subject: Mathematics | Level: GCSE | Exam Board: OCR
Mastering fractions, decimals, and percentages is the key to unlocking higher grades in GCSE Mathematics. This topic is heavily examined across all boards and forms the foundation for solving complex multi-step problems in finance, geometry, and probability.
Revision Notes & Key Concepts
Key Terms & Definitions
- Numerator
- The top number in a fraction, representing how many parts we have.
- Denominator
- The bottom number in a fraction, representing the total number of equal parts.
- Multiplier
- A decimal number used to calculate a percentage change in a single multiplication step.
- Compound Interest
- Interest calculated on the initial principal and also on the accumulated interest of previous periods.
- Depreciation
- The decrease in value of an asset over time.
- Recurring Decimal
- A decimal in which one or more digits repeat infinitely.
Worked Examples
Worked Example
Question: A car was bought for £18,000. Its value depreciates by 15% in the first year and then by 10% in each subsequent year. Calculate the value of the car after 3 years. Give your answer to the nearest pound.
Solution: Step 1: Identify the initial amount and the multipliers. Initial amount = £18,000 Year 1 multiplier (15% decrease) = 1 - 0.15 = 0.85 Years 2 and 3 multiplier (10% decrease) = 1 - 0.10 = 0.90 Step 2: Set up the calculation using compound multipliers. Value after 3 years = 18,000 × 0.85 × (0.90)^2 Step 3: Calculate the result. 18,000 × 0.85 = 15,300 (Value after Year 1) 15,300 × 0.90^2 = 15,300 × 0.81 = 12,393 Final answer: £12,393
Worked Example
Question: In a sale, normal prices are reduced by 20%. The sale price of a coat is £52. Calculate the normal price of the coat.
Solution: Step 1: Recognise this is a reverse percentage question. The £52 represents the price AFTER the 20% reduction. Step 2: Identify the multiplier for a 20% reduction. Multiplier = 1 - 0.20 = 0.80 Step 3: Set up the equation. Original Price × 0.80 = £52 Step 4: Solve for the Original Price. Original Price = 52 ÷ 0.80 Original Price = £65 Final answer: £65
Worked Example
Question: Write 0.45̇ as a fraction in its simplest form.
Solution: Step 1: Let x equal the recurring decimal. x = 0.454545... Step 2: Multiply x by a power of 10 to shift the decimal point past the repeating block. Since two digits repeat, multiply by 100. 100x = 45.454545... Step 3: Subtract the original equation (x) from the new equation (100x) to eliminate the recurring decimal part. 100x = 45.454545... -x = 0.454545... ------------------- 99x = 45 Step 4: Solve for x and simplify the fraction. x = 45 / 99 Divide numerator and denominator by 9: x = 5 / 11 Final answer: 5/11
Practice Questions
Question: Convert 0.08 to a fraction in its simplest form.
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Question: A shop has a sale. Everything is reduced by 15%. The normal price of a TV is £340. Work out the sale price of the TV.
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Question: Katie invests £2000 in a savings account for 4 years. The account pays compound interest at a rate of 2.5% per annum. Calculate the total amount in the account at the end of 4 years.
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Question: The price of a train ticket increases by 8% to £135. Work out the price of the ticket before the increase.
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Question: Prove algebraically that the recurring decimal 0.27̇ (where the 7 is recurring) can be written as 5/18.
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