Subject: Mathematics | Level: GCSE | Exam Board: Pearson
Sequences are the heartbeat of algebraic patterns, testing your ability to spot relationships and express them mathematically. Mastering term-to-term and position-to-term rules is essential for unlocking high marks in your GCSE Mathematics exam.
Revision Notes & Key Concepts
Key Terms & Definitions
- Sequence
- An ordered list of numbers that follow a specific mathematical rule.
- Term
- A single number or item within a sequence.
- Term-to-term rule
- A rule that describes how to calculate the next term in a sequence using the previous term.
- Position-to-term rule (nth term)
- An algebraic formula that calculates the value of any term based on its position (n) in the sequence.
- Common difference
- The constant amount added or subtracted to get from one term to the next in a linear sequence.
- Fibonacci sequence
- A sequence where each term is the sum of the two preceding terms.
Worked Examples
Worked Example
Question: Find the nth term of the sequence: 8, 13, 18, 23, 28 (2 marks)
Solution: Step 1: Find the common difference. 8 to 13 is +5. 13 to 18 is +5. The sequence goes up by 5, so the rule starts with 5n. Step 2: Compare the 5n sequence with the original sequence. 5n sequence: 5, 10, 15, 20... Original sequence: 8, 13, 18, 23... Step 3: Find the adjustment. To get from 5 to 8, we add 3. Final answer: 5n + 3
Worked Example
Question: The nth term of a sequence is 3n^2 - 1. Is 107 a term in this sequence? You must show your working. (3 marks)
Solution: Step 1: Set the nth term equal to 107. 3n^2 - 1 = 107 Step 2: Solve for n. 3n^2 = 108 n^2 = 36 n = 6 (or -6, but n must be positive) Final answer: Yes, 107 is the 6th term in the sequence because n is a positive integer.
Worked Example
Question: [Higher Tier] Find the nth term of the quadratic sequence: 2, 9, 20, 35, 54 (4 marks)
Solution: Step 1: Find first differences. 9 - 2 = 7 20 - 9 = 11 35 - 20 = 15 54 - 35 = 19 First differences: 7, 11, 15, 19 Step 2: Find second differences. 11 - 7 = 4 15 - 11 = 4 19 - 15 = 4 Second difference is 4. Therefore, the sequence contains 2n^2 (because 4 ÷ 2 = 2). Step 3: Subtract 2n^2 from the original sequence. Original: 2, 9, 20, 35 2n^2: 2, 8, 18, 32 Difference: 0, 1, 2, 3 Step 4: Find the nth term of the difference sequence (0, 1, 2, 3). It goes up by 1, so it starts with 1n (or n). The zero term (term before the first) is 0 - 1 = -1. So the linear part is n - 1. Final answer: 2n^2 + n - 1
Practice Questions
Question: Here are the first four terms of a number sequence: 4, 11, 18, 25. Write down the next two terms.
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Question: Find an expression, in terms of n, for the nth term of this sequence: 6, 10, 14, 18
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Question: The nth term of a sequence is 5n - 2. Work out the 20th term.
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Question: A sequence has the nth term n^2 + 3. Is 85 a term in this sequence? Explain your answer.
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Question: [Higher Tier] Here are the first five terms of a quadratic sequence: 1, 6, 15, 28, 45. Find an expression, in terms of n, for the nth term.
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