AQA · A-Level · Chemistry
Course version: 7405 · Version from Sept 2016
Alcohols
Master the production, classification, and reactions of alcohols. This topic is a heavy hitter for marks in organic chemistry, testing your ability to link reaction conditions to specific products.
- 6 min read
- 3 worked examples
- 5 practice questions
- 4 key terms
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The start of the Alcohols lesson, made from checked teaching notes for this specification point.
Have a go first
In the elimination of water from ethanol, which type of species removes a hydrogen ion from the intermediate?
Listen
Dehydration runs in three arrow-drawing steps. A lone pair on the alcohol's oxygen attacks H⁺ from the acid, giving a protonated alcohol; this turns the poor leaving group, OH⁻, into a good one, water. Next, the C–O bond breaks heterolytically, the arrow running from that bond to the oxygen, so a water molecule leaves and a carbocation remains. Finally a base, water or the hydrogensulfate ion, removes a hydrogen from a carbon adjacent to the positive carbon; the arrow runs from that C–H bond into the C–C bond, making the π bond of the alkene, and the H⁺ is handed back so the catalyst is regenerated. Choosing which adjacent hydrogen to remove decides which alkene you draw. A strong answer earns marks for these points. the arrow from a lone pair on the alcohol oxygen to H⁺. the arrow from the C–O bond to the oxygen, showing water leaving. the arrow from the correct C–H bond into the correct C–C bond. naming the mechanism as elimination. Exam tip: Draw the carbocation as a separate intermediate with the charge clearly on one carbon.
See it
Put it in order
Put these steps in the order they happen.
- 1. H⁺ handed back, regenerating the catalyst
- 2. Arrow from the C–H bond into the C–C bond makes the π bond of the alkene
- 3. C–O bond breaks heterolytically: arrow from C–O bond to oxygen
- 4. Base removes a hydrogen from a carbon adjacent to the positive carbon
- 5. Alcohol: lone pair on oxygen attacks H⁺ from the acid
- 6. Protonated alcohol formed: OH⁻ becomes water, a good leaving group
- 7. Water molecule leaves; carbocation remains
Key words
Say what each word means before you turn the card.
protonation of the alcohol
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water as the leaving group
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carbocation intermediate
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loss of H⁺ forming the π bond
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See every definition
- protonation of the alcohol
- A lone pair on the alcohol's oxygen attacks H⁺ from the acid, giving a protonated alcohol.
- water as the leaving group
- Protonation turns the poor leaving group, OH⁻, into a good one, water.
- carbocation intermediate
- The C–O bond breaks heterolytically, the arrow running from that bond to the oxygen, so a water molecule leaves and a carbocation remains.
- loss of H⁺ forming the π bond
- A base removes a hydrogen from a carbon adjacent to the positive carbon, the arrow running from that C–H bond into the C–C bond, making the π bond of the alkene.
Label the diagram
Some boxes have lost their names. Pick the right name for each number.
1Box 1
2Box 2
3Box 3
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Study Notes
Overview

Alcohols are a crucial homologous series in organic chemistry, characterised by the presence of the hydroxyl (–OH) functional group. This topic bridges the gap between basic hydrocarbons and more complex organic molecules like aldehydes, ketones, and carboxylic acids. Examiners frequently test this area because it requires candidates to recall specific reaction conditions and apply their knowledge of mechanisms.
Understanding alcohols is not just about memorising equations; it's about recognising how the structure of the alcohol dictates its chemical behaviour. You will need to confidently classify alcohols as primary, secondary, or tertiary, and predict their oxidation products. This topic also introduces the debate around biofuels, testing your ability to evaluate the environmental impact of chemical processes. Expect a mix of short-answer recall questions, mechanism drawing, and longer evaluation questions comparing production methods.
Key Concepts
Concept 1: Production of Alcohols
Alcohols, specifically ethanol, can be produced via two main routes: the industrial hydration of alkenes and the biological fermentation of glucose. Examiners expect you to know the exact conditions for both and to be able to compare them.
Hydration of Alkenes involves reacting ethene with steam. This is an addition reaction where water is added across the carbon-carbon double bond.
- Conditions: High temperature (approx. 300°C), high pressure (60-70 atm), and a solid phosphoric acid catalyst.
- Why it works: The high pressure forces the gases together, increasing the collision frequency, while the catalyst provides an alternative pathway with a lower activation energy. It produces pure ethanol continuously but relies on non-renewable crude oil.
Fermentation of Glucose uses yeast to break down sugars anaerobically (without oxygen).
- Conditions: Yeast, warm temperature (30-40°C), and anaerobic conditions.
- Why it works: The enzymes in yeast catalyse the breakdown of glucose. If it's too cold, the reaction is too slow; if it's too hot, the enzymes denature. Anaerobic conditions are vital because in the presence of oxygen, yeast respires aerobically, producing carbon dioxide and water instead of ethanol.
Concept 2: Classification of Alcohols

Alcohols are classified based on the number of carbon atoms attached to the carbon atom that bears the –OH group. This classification is the key to predicting how an alcohol will behave when oxidised.
- Primary (1°) Alcohols: The –OH group is on a carbon attached to only ONE other carbon (or none, in the case of methanol). Example: Propan-1-ol.
- Secondary (2°) Alcohols: The –OH group is on a carbon attached to TWO other carbons. Example: Propan-2-ol.
- Tertiary (3°) Alcohols: The –OH group is on a carbon attached to THREE other carbons. Example: 2-methylpropan-2-ol.
Concept 3: Oxidation of Alcohols

This is where candidates often lose marks. The standard oxidising agent is acidified potassium dichromate(VI) (K₂Cr₂O₇/H₂SO₄). The dichromate(VI) ion (Cr₂O₇²⁻) is orange and is reduced to the green chromium(III) ion (Cr³⁺) during the reaction.
Primary Alcohols can be oxidised twice:
- Partial Oxidation to an Aldehyde: Use a limited amount of oxidising agent and distil the product as it forms to prevent further oxidation.
- Complete Oxidation to a Carboxylic Acid: Use an excess of oxidising agent and heat under reflux.
Secondary Alcohols are oxidised to ketones. Heating under reflux is used to ensure completion. They cannot be easily oxidised further.
Tertiary Alcohols cannot be easily oxidised because there is no hydrogen atom on the carbon bearing the –OH group to be removed. The solution remains orange.
Concept 4: Distinguishing Aldehydes and Ketones
Because primary alcohols form aldehydes and secondary alcohols form ketones, examiners will test your ability to tell them apart chemically. Aldehydes can be further oxidised (they are reducing agents); ketones cannot.
- Tollens' Reagent (Ammoniacal Silver Nitrate): When warmed with an aldehyde, a silver mirror forms on the inside of the test tube. Ketones show no visible change.
- Fehling's Solution: When warmed with an aldehyde, the blue solution forms a brick-red precipitate of copper(I) oxide. Ketones show no visible change.
Concept 5: Dehydration of Alcohols
Alcohols can undergo an elimination reaction to form alkenes by losing a molecule of water. This is called dehydration.
- Conditions: Heat with a concentrated acid catalyst (e.g., concentrated phosphoric acid or concentrated sulfuric acid).
- Why it works: The acid protonates the –OH group, making it a better leaving group (water). A proton is then removed from an adjacent carbon, forming the C=C double bond.
Mathematical/Scientific Relationships
- General Formula for Alcohols: CₙH₂ₙ₊₁OH
- General Formula for Aldehydes: RCHO
- General Formula for Ketones: RCOR'
- General Formula for Carboxylic Acids: RCOOH
(Note: 'R' represents an alkyl group)
Practical Applications
- Biofuels: Ethanol produced by fermentation is used as a fuel, often blended with petrol (e.g., E10 fuel). The debate around its carbon neutrality is a common exam topic.
- Solvents: Ethanol and methanol are widely used industrial solvents for cosmetics, perfumes, and inks because they can dissolve both polar and non-polar substances.
- Chemical Feedstock: Alcohols are starting materials for synthesising other organic compounds, such as esters (used in flavourings and fragrances).
Worked Examples
3 worked examples — open one to explore the question and available guidance.
Practice Questions
Try the question, then reveal an answer plan or example response
Compare the industrial production of ethanol by hydration of ethene with its production by fermentation of glucose. Consider raw materials, rate of reaction, and purity of the product. (6 marks)
Hint: Create a mental table comparing the two methods across the three specific points asked for in the question.
State the reagent and conditions needed to dehydrate ethanol to form ethene. (2 marks)
Hint: What chemical is good at removing water? What condition is needed to make the reaction happen?
An unknown alcohol X is heated with acidified potassium dichromate(VI) under reflux. The solution turns green. The organic product Y does not react with Tollens' reagent. Deduce the classification of alcohol X and the functional group present in product Y. (2 marks)
Hint: If it turns green, oxidation happened. If the product doesn't react with Tollens', it's not an aldehyde.
Write an equation for the oxidation of ethanol to ethanoic acid. Use [O] to represent the oxidising agent. (1 mark)
Hint: Balance the oxygen atoms. You need to add oxygen and remove hydrogen to form water.
Explain why tertiary alcohols cannot be easily oxidised by acidified potassium dichromate(VI). (2 marks)
Hint: Look at the structure of a tertiary alcohol. What is missing on the central carbon that is present in primary and secondary alcohols?
Exam technique
How to turn what you know into marks
How to approach the question
Always check the classification of the alcohol first before predicting products. Highlight whether the question asks for conditions for an aldehyde or a carboxylic acid.
How to structure your answer
For 'compare' questions (e.g., fermentation vs hydration), use a table or clear comparative sentences (e.g., 'Fermentation uses renewable resources, whereas hydration uses non-renewable crude oil').
Timing
Approximately 1 minute per mark. A 4-mark mechanism should take 4 minutes.
Common pitfalls
- Saying tertiary alcohols are oxidised to carboxylic acids. They do not oxidise.
- Forgetting the word 'acidified' when mentioning potassium dichromate(VI).
- Confusing the conditions for fermentation (needs anaerobic) with aerobic respiration.
What the command words want
- Explain
- Give a chemical reason - e.g., 'Tertiary alcohols do not oxidise because there is no hydrogen atom on the central carbon'.
- Describe
- Detail the procedure or observations - e.g., 'Heat under reflux'.
- Evaluate
- Give pros and cons, then a final judgement based on the evidence provided.
- State/Give
- Brief factual answer - e.g., 'orange to green'.
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