AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    Changes in energy: Eₑ = ½ke²

    This equation gives the elastic potential energy stored in a stretched or compressed spring, provided the spring obeys Hooke’s law.

    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This equation gives the elastic potential energy stored in a stretched or compressed spring, provided the spring obeys Hooke’s law. Eₑ is the energy in joules (J), k is the spring constant in newtons per metre (N/m), and e is the extension or compression in metres (m). The extension e is the change in length from the natural length, not the total length. Because e is squared, doubling the extension quadruples the stored energy. For example, a spring with k = 200 N/m stretched by e = 0.10 m stores Eₑ = ½ × 200 × (0.10)² = 1.0 J. The factor ½ arises because the force increases linearly from zero to ke, so the average force is ½ke. Always convert centimetres to metres and grams to kilograms where needed before substituting.

    What earns the marks

    • State that Eₑ is the elastic potential energy stored in the spring, measured in joules (J).
    • Identify k as the spring constant in N/m and e as the extension or compression in metres, measured from the natural length.
    • Substitute values correctly into Eₑ = ½ke², including squaring the extension before multiplying by ½ and k.
    • Convert units where necessary, for example cm to m or N/cm to N/m, before calculating.
    • Interpret a calculated energy as the energy transferred to the spring during stretching, or released when it returns to its natural length.

    Common mistakes and how to put them right

    • Using the total length of the spring instead of the extension.

      Put it right by subtracting the natural length to find e.

    • Forgetting to square the extension.

      Put it right by applying the exponent to e before multiplying by ½ and k.

    • Mixing units, such as using extension in cm with k in N/m.

      Put it right by converting all lengths to metres and k to N/m.

    Exam tips

    • Write the equation, then substitute numbers with units before calculating to reduce unit errors.
    • Check whether the question gives extension or total length; if total length, subtract the natural length first.
    • For 'show that' questions, give the substituted values and the calculated result to at least two significant figures.

    Try the lesson

    The start of the Changes in energy: Eₑ = ½ke² lesson, made from checked teaching notes for this specification point.

    Have a go first

    A spring has a spring constant k of 200 N/m. It is stretched by 0.1 m. Using Eₑ = ½ke², what is the elastic potential energy stored in the spring?

    Listen

    This equation gives the elastic potential energy stored in a stretched or compressed spring, provided the spring obeys Hooke’s law. Eₑ is the energy in joules (J), k is the spring constant in newtons per metre (N/m), and e is the extension or compression in metres (m). The extension e is the change in length from the natural length, not the total length. Because e is squared, doubling the extension quadruples the stored energy. For example, a spring with k = 200 N/m stretched by e = 0.10 m stores Eₑ = ½ × 200 × (0.10)² = 1.0 J. The factor ½ arises because the force increases linearly from zero to ke, so the average force is ½ke. Always convert centimetres to metres and grams to kilograms where needed before substituting. A strong answer earns marks for these points. State that Eₑ is the elastic potential energy stored in the spring, measured in joules (J). Identify k as the spring constant in N/m and e as the extension or compression in metres, measured from the natural length. Substitute values correctly into Eₑ = ½ke², including squaring the extension before multiplying by ½ and k. Convert units where necessary, for example cm to m or N/cm to N/m, before calculating. A common slip: Using the total length of the spring instead of the extension. Instead, subtracting the natural length to find e. Exam tip: Write the equation, then substitute numbers with units before calculating to reduce unit errors.

    Key words

    Say what each word means before you turn the card.

    Elastic potential energy

    Try answering aloud or in your head before turning the card.

    Spring constant

    Try answering aloud or in your head before turning the card.

    Extension

    Try answering aloud or in your head before turning the card.

    See every definition
    Elastic potential energy
    The energy stored in a stretched or compressed spring, measured in joules (J).
    Spring constant
    A quantity in newtons per metre (N/m), represented by k in the equation.
    Extension
    The change in length from the natural length, not the total length, measured in metres (m).

    There is more to this lesson

    The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.

    Carry on with the full lesson

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge

    Test your understanding of Changes in energy: Eₑ = ½ke²

    Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.

    Take topic quiz

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge