AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    Collision theory and activation energy: predict and explain the effects of changes in the size of pieces of a reacting solid in terms of surface area to volume ratio

    For a solid reactant, only particles at the exposed surface can collide with particles of the other reactant, so the rate depends on how much surface is available.

      Study notes

      From the checked teaching notes for this specification point.

      The idea

      For a solid reactant, only particles at the exposed surface can collide with particles of the other reactant, so the rate depends on how much surface is available. Breaking a solid into smaller pieces increases its total surface area without changing its mass or volume, so the surface area to volume ratio rises. A greater ratio means more solid particles are exposed to collisions per unit of volume, so collisions occur more frequently and the rate of reaction increases. For example, 10 g of marble chips in excess acid reacts slowly, but the same 10 g powdered exposes far more surface and fizzes faster, although the same total volume of gas is eventually produced. The ratio is calculated by dividing surface area by volume, so halving particle size roughly doubles the ratio for similarly shaped pieces.

      What earns the marks

      • Only particles at the surface of a solid can collide with particles of the other reactant, so reaction occurs at the surface.
      • Breaking a solid into smaller pieces increases its total surface area while mass and volume stay the same, so the surface area to volume ratio increases.
      • A higher surface area to volume ratio exposes more solid particles to collisions per unit volume, increasing collision frequency.
      • More frequent collisions between reactant particles increase the rate of reaction, so the reaction finishes sooner.
      • The total amount of product formed eventually is unchanged because the same mass of solid reacts; only the rate changes.
      • Comparing equal masses of large chips and powder in the same volume of reactant solution allows a fair test of the effect.

      Common mistakes and how to put them right

      • Thinking that powder has more mass or reacts to give more product.

        Put it right: The mass is unchanged, so the same total volume of gas or amount of product forms, but faster.

      • Saying smaller pieces have more surface area without linking it to volume.

        Put it right: The key idea is the surface area to volume ratio, which increases as pieces get smaller.

      • Believing smaller pieces are more reactive because their particles have more energy.

        Put it right: Particle energy and activation energy are unchanged; the increase is in collision frequency at the exposed surface.

      Exam tips

      • Name the variable you change (size of pieces) and the variable you measure (rate, for example gas volume per unit time or loss in mass per unit time).
      • Use the phrase surface area to volume ratio and explain that it increases when a solid is broken into smaller pieces.
      • Link the ratio to collision frequency and then to rate, and state that the total product is unchanged for the same mass of solid.

      Try the lesson

      The start of the Collision theory and activation energy: predict and explain the effects of changes in the size of pieces of a reacting solid in terms of surface area to volume ratio lesson, made from checked teaching notes for this specification point.

      Have a go first

      A lump of calcium carbonate is broken into smaller pieces before it is added to dilute hydrochloric acid. What happens to the rate of the reaction?

      Listen

      For a solid reactant, only particles at the exposed surface can collide with particles of the other reactant, so the rate depends on how much surface is available. Breaking a solid into smaller pieces increases its total surface area without changing its mass or volume, so the surface area to volume ratio rises. A greater ratio means more solid particles are exposed to collisions per unit of volume, so collisions occur more frequently and the rate of reaction increases. For example, 10 g of marble chips in excess acid reacts slowly, but the same 10 g powdered exposes far more surface and fizzes faster, although the same total volume of gas is eventually produced. The ratio is calculated by dividing surface area by volume, so halving particle size roughly doubles the ratio for similarly shaped pieces. A strong answer earns marks for these points. Only particles at the surface of a solid can collide with particles of the other reactant, so reaction occurs at the surface. Breaking a solid into smaller pieces increases its total surface area while mass and volume stay the same, so the surface area to volume ratio increases. A higher surface area to volume ratio exposes more solid particles to collisions per unit volume, increasing collision frequency. More frequent collisions between reactant particles increase the rate of reaction, so the reaction finishes sooner. Exam tip: Name the variable you change (size of pieces) and the variable you measure (rate, for example gas volume per unit time or loss in mass per unit time).

      There is more to this lesson

      The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.

      Carry on with the full lesson

      A week of Premium from your first lesson · Then the free plan continues · No card, no charge

      Test your understanding of Collision theory and activation energy: predict and explain the effects of changes in the size of pieces of a reacting solid in terms of surface area to volume ratio

      Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.

      Take topic quiz

      A week of Premium from your first lesson · Then the free plan continues · No card, no charge