AQA · GCSE · Combined Science
Course version: 8464 · Version from Sept 2018
Neutralisation of acids and salt production: The particular salt produced in any reaction between an acid and a base or alkali depends on:
The salt formed in a neutralisation reaction has two parts: the metal or ammonium ion from the base or alkali, and the anion from the acid.
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
The salt formed in a neutralisation reaction has two parts: the metal or ammonium ion from the base or alkali, and the anion from the acid. The acid determines the anion: hydrochloric acid produces chloride salts, nitric acid produces nitrate salts, and sulfuric acid produces sulfate salts. The base or alkali determines the metal or ammonium ion: sodium hydroxide gives sodium salts, copper(II) oxide gives copper(II) salts, and ammonia gives ammonium salts. For example, sulfuric acid with copper(II) oxide gives copper(II) sulfate and water: H₂SO₄(aq) + CuO(s) → CuSO₄(aq) + H₂O(l). Note that ammonia reacts with acids to form only an ammonium salt, without producing water. The name must show the metal or ammonium ion and the acid-derived anion, and the formula must balance charges, such as Cu²⁺ with SO₄²⁻ giving CuSO₄.
What earns the marks
- The acid used determines the anion in the salt: hydrochloric acid → chloride, nitric acid → nitrate, sulfuric acid → sulfate.
- The base or alkali used determines the metal or ammonium ion in the salt: sodium hydroxide → sodium salts, potassium hydroxide → potassium salts, copper(II) oxide → copper(II) salts, ammonia → ammonium salts.
- Salt names combine the metal or ammonium ion with the acid anion, for example sodium nitrate from sodium hydroxide and nitric acid.
- Formulae must have balanced charges: for example, Mg²⁺ with Cl⁻ gives MgCl₂, and Al³⁺ with SO₄²⁻ gives Al₂(SO₄)₃.
- Roman numerals in names such as copper(II) oxide show the charge on the metal ion and must be reflected in the salt formula.
- Word equations and balanced symbol equations should show the salt and water as products for acid + metal oxide/hydroxide reactions, but only the salt for ammonia + acid reactions.
Common mistakes and how to put them right
Naming the salt from the base only and ignoring the acid.
Put it right by combining the metal or ammonium ion with the anion from the acid.
Writing sulfate as SO₄ without the 2⁻ charge or using S₂O₄.
Put it right by using the sulfate ion SO₄²⁻.
Including water as a product when ammonia reacts with an acid.
Put it right by remembering that ammonia + acid → ammonium salt only.
Balancing formulae incorrectly, such as NaCl₂.
Put it right by balancing charges so that Na⁺ and Cl⁻ give NaCl.
Exam tips
- Identify the acid first to fix the anion, then identify the base or alkali to fix the metal or ammonium ion, and combine them to name the salt.
- Check the charge on each ion and use the lowest whole-number ratio when writing a formula, for example Ca²⁺ and NO₃⁻ give Ca(NO₃)₂.
- If a question gives a salt name, work backwards to identify the acid and base that could produce it.
- Include state symbols only when they are requested or when they help show that a solid base has reacted with an aqueous acid.
Try the lesson
The start of the Neutralisation of acids and salt production: The particular salt produced in any reaction between an acid and a base or alkali depends on: lesson, made from checked teaching notes for this specification point.
Have a go first
Hydrochloric acid reacts with sodium hydroxide. Which salt is produced?
Listen
The salt formed in a neutralisation reaction has two parts: the metal or ammonium ion from the base or alkali, and the anion from the acid. The acid determines the anion: hydrochloric acid produces chloride salts, nitric acid produces nitrate salts, and sulfuric acid produces sulfate salts. The base or alkali determines the metal or ammonium ion: sodium hydroxide gives sodium salts, copper(II) oxide gives copper(II) salts, and ammonia gives ammonium salts. For example, sulfuric acid with copper(II) oxide gives copper(II) sulfate and water: H₂SO₄(aq) + CuO(s) → CuSO₄(aq) + H₂O(l). Note that ammonia reacts with acids to form only an ammonium salt, without producing water. The name must show the metal or ammonium ion and the acid-derived anion, and the formula must balance charges, such as Cu²⁺ with SO₄²⁻ giving CuSO₄. A strong answer earns marks for these points. The acid used determines the anion in the salt: hydrochloric acid → chloride, nitric acid → nitrate, sulfuric acid → sulfate. The base or alkali used determines the metal or ammonium ion in the salt: sodium hydroxide → sodium salts, potassium hydroxide → potassium salts, copper(II) oxide → copper(II) salts, ammonia → ammonium salts. Salt names combine the metal or ammonium ion with the acid anion, for example sodium nitrate from sodium hydroxide and nitric acid. Formulae must have balanced charges: for example, Mg²⁺ with Cl⁻ gives MgCl₂, and Al³⁺ with SO₄²⁻ gives Al₂(SO₄)₃. A common slip: Naming the salt from the base only and ignoring the acid. Instead, combining the metal or ammonium ion with the anion from the acid. Exam tip: Identify the acid first to fix the anion, then identify the base or alkali to fix the metal or ammonium ion, and combine them to name the salt.
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Key words
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Acid anions
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Metal and ammonium ions
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Salt naming from acids and bases
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Ionic formulae and charge balance
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See every definition
- Acid anions
- The acid used determines the anion in the salt: hydrochloric acid gives chloride, nitric acid gives nitrate, and sulfuric acid gives sulfate.
- Metal and ammonium ions
- The base or alkali used determines the metal or ammonium ion in the salt, such as sodium hydroxide giving sodium salts and ammonia giving ammonium salts.
- Salt naming from acids and bases
- Salt names combine the metal or ammonium ion with the acid anion, for example sodium nitrate from sodium hydroxide and nitric acid.
- Ionic formulae and charge balance
- Formulae must have balanced charges, using the lowest whole-number ratio, such as Mg²⁺ with Cl⁻ giving MgCl₂.
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