AQA · GCSE · Combined Science

    Course version: 8464 · Version from Sept 2018

    Series and parallel circuits: solve problems for circuits which include resistors in series using the concept of equivalent resistance.

    Equivalent resistance is the single resistance that would replace a group of resistors without changing the current drawn from the supply.

    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Equivalent resistance is the single resistance that would replace a group of resistors without changing the current drawn from the supply. For resistors in series, the equivalent resistance is the sum of the individual resistances: R_eq = R₁ + R₂ + R₃. Once R_eq is known, the circuit behaves as one resistor, so I = V_supply ÷ R_eq gives the current through every component.

    For example: A 12 V supply with 3.0 Ω, 4.0 Ω and 5.0 Ω in series has R_eq = 12 Ω, so I = 12 V ÷ 12 Ω = 1.0 A. The equivalent resistance is always larger than the largest individual resistance in the series group, which is a useful check on the answer.

    What earns the marks

    • Defines equivalent resistance as the single resistance that replaces a series group while drawing the same current from the supply.
    • Calculates R_eq by adding the individual resistances, including correct unit conversion for kilohms and milliohms.
    • Uses I = V_supply ÷ R_eq to find the current through the whole series circuit after finding the equivalent resistance.
    • Uses the equivalent resistance with V = I × R to find the potential difference across a chosen part of the circuit.
    • Recognises that the equivalent resistance of a series group is greater than any single resistance in that group and uses this as a check.
    • Solves multi-step problems by finding R_eq first, then the current, then any required potential difference or resistance.

    Common mistakes and how to put them right

    • Adding the reciprocals of the resistances for a series group.

      Put it right: Add the resistances directly for series; reciprocal addition applies to parallel resistors.

    • Dividing the supply potential difference by one resistor instead of by the equivalent resistance.

      Put it right: Use R_eq for the whole series group to find the current.

    • Mixing units, such as adding 470 Ω to 1.5 kΩ without converting.

      Put it right: Convert all resistances to ohms before adding.

    • Assuming the equivalent resistance is smaller than the smallest resistor.

      Put it right: In series, R_eq is larger than the largest individual resistance.

    Exam tips

    • State the equivalent resistance before calculating the current so each step of the method is clear.
    • Convert all resistances to ohms at the start and keep units with every substituted value.
    • Check that R_eq is greater than the largest individual resistance before using it.
    • For multi-step questions, label each stage, for example R_eq, then I, then V across one resistor.

    Try the lesson

    The start of the Series and parallel circuits: solve problems for circuits which include resistors in series using the concept of equivalent resistance. lesson, made from checked teaching notes for this specification point.

    Have a go first

    Two resistors are connected in series in a circuit. Their resistances are 4 Ω and 6 Ω. What is the equivalent resistance of the two resistors?

    Key words

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    Equivalent resistance

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    Series resistance addition

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    Using R_eq with V = I × R

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    Multi-step problem solving in dc circuits

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    See every definition
    Equivalent resistance
    The single resistance that would replace a group of resistors without changing the current drawn from the supply.
    Series resistance addition
    For resistors in series, the equivalent resistance is the sum of the individual resistances: R_eq = R₁ + R₂ + R₃.
    Using R_eq with V = I × R
    Once R_eq is known, the circuit behaves as one resistor, so I = V_supply ÷ R_eq gives the current through every component.
    Multi-step problem solving in dc circuits
    Solving multi-step problems by finding R_eq first, then the current, then any required potential difference or resistance.

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