Discrete Mathematics

    Master the Simplex Algorithm for GCSE Further Mathematics with this comprehensive guide. Learn how to systematically solve complex linear programming problems using algebraic tableaus, identify optimal solutions, and secure maximum marks with examiner-approved techniques.

    4
    Min Read
    3
    Examples
    5
    Questions
    6
    Key Terms
    🎙 Podcast Episode
    Discrete Mathematics
    0:00-0:00

    Study Notes

    Overview

    Header image for The Simplex Algorithm

    The Simplex Algorithm is a powerful algebraic method used to solve linear programming problems. While you may have used the graphical method for problems with two variables, the Simplex Algorithm allows you to solve complex problems with three or more variables by moving systematically along the edges of a feasible region to find the optimal solution.

    In GCSE Further Mathematics, examiners test your ability to translate a real-world problem into standard form, construct an initial simplex tableau, and accurately perform row operations. This topic connects deeply with algebra, inequalities, and optimisation. Exam questions typically range from 4 to 8 marks, rewarding methodical working and precise arithmetic.

    Listen to the companion podcast for an in-depth walkthrough of the core concepts and common exam pitfalls:
    Maths Mastery Podcast: The Simplex Algorithm

    Key Concepts

    Concept 1: Standard Form and Slack Variables

    Before applying the algorithm, you must convert inequalities into equations. This is done by adding slack variables (s_1, s_2, \dots). A slack variable represents the unused capacity of a constraint. For example, if a constraint is 2x + y \le 10, we rewrite it as 2x + y + s_1 = 10. The objective function must also be rearranged so all terms are on one side, typically Z - cx - dy = 0.

    Example: Maximise Z = 3x + 2y subject to x + y \le 5.
    Standard form: Z - 3x - 2y = 0 and x + y + s_1 = 5.

    Concept 2: The Initial Tableau

    The initial simplex tableau is a matrix representing the standard form equations. The columns represent the variables (x, y, s_1, Z) and the Right-Hand Side (RHS). The basic variables (initially the slack variables) form an identity matrix within the tableau.

    Simplex Tableau Structure

    Concept 3: Identifying Pivot Column and Row

    To improve the objective function, we must choose an entering variable and a leaving variable.

    • Pivot Column (Entering Variable): The column with the most negative value in the objective row (Z row). This variable will increase Z the most.
    • Pivot Row (Leaving Variable): Perform the ratio test by dividing the RHS by the positive values in the pivot column. The row with the smallest non-negative ratio is the pivot row.

    Concept 4: Row Operations

    Once the pivot element (intersection of pivot row and column) is identified, use row operations to make the pivot element 1 and all other elements in the pivot column 0. This algebraically moves you to an adjacent, superior vertex on the feasible region.

    Feasible Region and Optimal Vertex

    Concept 5: Identifying the Optimal Solution

    The algorithm terminates when there are no negative values remaining in the objective row. At this point, the optimal solution is found. The values of the basic variables are read from the RHS column, and all non-basic variables are 0.

    Mathematical Relationships

    • Objective Function: Z = ax_1 + bx_2 + \dots (The function to be maximised)
    • Constraints: a_{11}x_1 + a_{12}x_2 \le b_1 (Resource limitations)
    • Standard Form: a_{11}x_1 + a_{12}x_2 + s_1 = b_1 (Where s_1 \ge 0)
    • Ratio Test: \text{Ratio} = \frac{\text{RHS}}{\text{Pivot Column Value}} (Only calculate for values > 0)

    Practical Applications

    The Simplex Algorithm is widely used in logistics, manufacturing, and finance to optimise resources. For example, an airline might use it to minimise fuel costs while meeting passenger demand and flight schedule constraints.

    Visual Resources

    2 diagrams and illustrations

    Simplex Tableau Structure
    Simplex Tableau Structure
    Feasible Region and Optimal Vertex
    Feasible Region and Optimal Vertex

    Interactive Diagrams

    2 interactive diagrams to visualise key concepts

    Conceptual Flow Outline

    Start: Set up initial tableau
    Check Z row for negatives
    Check Z row for negatives
    Any negatives?
    Any negatives?
    "No"Optimal solution found!
    "Yes"Identify Pivot Column (most negative)
    Identify Pivot Column (most negative)
    Calculate Ratios (RHS / Pivot Col)
    Calculate Ratios (RHS / Pivot Col)
    Identify Pivot Row (smallest positive ratio)
    Identify Pivot Row (smallest positive ratio)
    Perform Row Operations
    Perform Row Operations
    Check Z row for negatives

    Flowchart of the Simplex Algorithm iterative process.

    Conceptual Flow Outline

    Inequality: 2x + y <= 10
    Add Slack Variable s1
    Add Slack Variable s1
    Equation: 2x + y + s1 = 10
    Equation: 2x + y + s1 = 10
    Initial Basic Variable: s1 = 10, x = 0, y = 0

    Process of converting an inequality to standard form.

    Worked Examples

    3 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    Convert the following linear programming problem into standard form: Maximise Z = 5x + 3y, subject to 2x + y \le 8 and x + 2y \le 6.

    2 marks
    foundation

    Hint: Remember to move all terms in the objective function to the left-hand side.

    Q2

    In a simplex tableau, the objective row is P = [-4, -6, 0, 0, 0]. The RHS values for the constraints are 12 and 15. The column for y (the most negative in P) has values 2 and 5 respectively. Determine the pivot row.

    3 marks
    standard

    Hint: Calculate the ratio of RHS to the pivot column value for each row.

    Q3

    A final simplex tableau has basic variables x = 10, s_2 = 4, and P = 120. Variables y and s_1 are non-basic. State the full optimal solution.

    2 marks
    foundation

    Hint: What value do non-basic variables take?

    Q4

    During a ratio test, the values in the pivot column are 4, 0, and -2. The corresponding RHS values are 20, 10, and 8. Which row should be chosen as the pivot row and why?

    2 marks
    standard

    Hint: What are the rules for valid ratios?

    Q5

    Perform one iteration of the simplex algorithm on the following initial tableau to find the next tableau. [6 marks]

    BVxys1s2RHS
    s1121014
    s2310115
    P-4-5000
    6 marks
    challenging

    Hint: Identify pivot column, calculate ratios, find pivot row. Then use row operations to make the pivot element 1 and other entries in that column 0.

    Key Terms

    Essential vocabulary to know