Algebraic Fractions Revision Notes
Subject: Further Mathematics | Level: GCSE | Exam Board: OCR
Master OCR GCSE Further Maths Algebraic Fractions (2.1) with this comprehensive study guide. Learn to simplify complex expressions, solve equations, and avoid common exam pitfalls through expert-written content, worked examples, and engaging multi-modal resources designed to secure top marks.
Revision Notes & Key Concepts
Key Terms & Definitions
- Rational Expression
- An algebraic expression that can be written as a fraction where both the numerator and the denominator are polynomials.
- Factor
- An algebraic expression that divides another expression exactly, without leaving a remainder. Factors are multiplied together.
- Term
- A single mathematical expression. It may be a single number, a single variable, or several variables multiplied together. Terms are separated by + or - signs.
- Lowest Common Multiple (LCM)
- The smallest polynomial that is a multiple of two or more other polynomials. For algebraic fractions, it's the expression needed to form a common denominator.
- Extraneous Solution
- A solution to a derived equation that is not a solution to the original equation. It arises when a mathematical operation (like multiplying by a variable) introduces a new solution that is invalid in the original context.
- Non-monic Quadratic
- A quadratic expression of the form ax² + bx + c where the coefficient 'a' is not equal to 1.
Worked Examples
Worked Example
Question: Simplify fully: (3x² - 13x - 10) / (x² - 25)
Solution: Step 1: Factorize the numerator. We need two numbers that multiply to 3 * -10 = -30 and add to -13. These are -15 and 2. So, 3x² - 15x + 2x - 10 = 3x(x - 5) + 2(x - 5) = (3x + 2)(x - 5). Step 2: Factorize the denominator. This is a difference of two squares: x² - 25 = (x - 5)(x + 5). Step 3: Rewrite the fraction with the factorized expressions: [(3x + 2)(x - 5)] / [(x - 5)(x + 5)]. Step 4: Cancel the common factor (x - 5) from the numerator and denominator. Final answer: (3x + 2) / (x + 5)
Worked Example
Question: Express as a single fraction in its simplest form: 3 / (x + 4) - (2x - 1) / (x² + 3x - 4)
Solution: Step 1: Factorize all denominators to find the LCM. The denominator of the second fraction is x² + 3x - 4 = (x + 4)(x - 1). The LCM is therefore (x + 4)(x - 1). Step 2: Rewrite the first fraction over the LCM. We need to multiply its numerator and denominator by (x - 1): [3(x - 1)] / [(x + 4)(x - 1)]. Step 3: The second fraction already has the LCM as its denominator. So the expression is [3(x - 1)] / [(x + 4)(x - 1)] - (2x - 1) / [(x + 4)(x - 1)]. Step 4: Combine the numerators over the single denominator. Crucially, use brackets for the second numerator: [3(x - 1) - (2x - 1)] / [(x + 4)(x - 1)]. Step 5: Expand and simplify the numerator: (3x - 3 - 2x + 1) = x - 2. Final answer: (x - 2) / [(x + 4)(x - 1)]
Worked Example
Question: Solve the equation: 5 / (x - 3) = 2 + 3 / (x + 1)
Solution: Step 1: Identify the LCM of the denominators, which is (x - 3)(x + 1). Step 2: Multiply every term in the equation by the LCM to eliminate the fractions: (x - 3)(x + 1) * [5 / (x - 3)] = (x - 3)(x + 1) * [2] + (x - 3)(x + 1) * [3 / (x + 1)]. Step 3: Simplify the equation after cancellation: 5(x + 1) = 2(x - 3)(x + 1) + 3(x - 3). Step 4: Expand all brackets: 5x + 5 = 2(x² - 2x - 3) + 3x - 9. 5x + 5 = 2x² - 4x - 6 + 3x - 9. Step 5: Rearrange into a standard quadratic equation (ax² + bx + c = 0): 2x² - 6x - 20 = 0. Step 6: Simplify the quadratic by dividing by 2: x² - 3x - 10 = 0. Step 7: Factorize and solve the quadratic: (x - 5)(x + 2) = 0. So, x = 5 or x = -2. Step 8: Check for invalid solutions. Neither x=5 nor x=-2 makes the original denominators zero, so both are valid. Final answer: x = 5, x = -2
Practice Questions
Question: Simplify fully: (x² + x - 12) / (2x² - 7x + 3)
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Question: Express as a single fraction: 4 / (x - 2) - 5 / (x + 3)
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Question: Show that (4x² - 1) / (2x² + 5x - 3) simplifies to (2x + 1) / (x + 3).
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Question: Solve: 7 / (x + 2) + 1 / (x - 1) = 3
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Question: A rectangle has a length of (x+5)/(x-3) cm and a width of (x-3)/(2) cm. Its area is 10 cm². Show that x satisfies the equation x² - 4x - 25 = 0.
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