Iteration Revision Notes

    Subject: Further Mathematics | Level: GCSE | Exam Board: OCR

    Iteration is a powerful numerical method that allows you to find approximate solutions to equations that cannot be solved algebraically. By repeatedly applying an iterative formula of the form x_{n+1} = g(x_n), you systematically converge on roots to a specified degree of accuracy. This topic is essential for OCR GCSE Further Mathematics and typically appears as structured 4-6 mark questions testing both algebraic manipulation and precise calculator technique.

    Revision Notes & Key Concepts

    ![Header image for Iteration in GCSE Further Mathematics](https://xnnrgnazirrqvdgfhvou.supabase.co/storage/v1/object/public/study-guide-assets/guide_8268753c-dac5-4047-87b4-2f519408a764/header_image.png) ## Overview Iteration represents one of the most elegant and practical numerical methods in GCSE Further Mathematics. When faced with equations such as x³ - x - 1 = 0 that resist traditional algebraic techniques like factorisation or the quadratic formula, iteration provides a systematic pathway to approximate solutions with remarkable precision. The method transforms an equation f(x) = 0 into an iterative formula x_{n+1} = g(x_n), which when applied repeatedly from a starting value x₀, generates a sequence of values that converge toward the true root. OCR assesses this topic rigorously, expecting candidates to demonstrate both algebraic fluency in deriving iterative formulas and technical precision in executing calculations using the 'Ans' function on scientific calculators. Iteration questions typically appear as 4-6 mark structured problems, often bridging algebraic manipulation with graphical interpretation. The topic connects deeply with functions, graphs, and solving equations across the specification, making it a synoptic skill that rewards methodical working and attention to detail. Understanding iteration not only secures valuable exam marks but also provides insight into how computers and calculators solve complex equations behind the scenes. ## Key Concepts ### Concept 1: The Iterative Formula x_{n+1} = g(x_n) The foundation of iteration lies in transforming an equation from the form f(x) = 0 into an iterative formula x_{n+1} = g(x_n). This transformation requires algebraic manipulation to isolate x on one side of the equation. The subscript notation is crucial: x_n represents the current value in the sequence, while x_{n+1} represents the next value. Think of this as a function machine where you input one value and receive the next approximation as output. The beauty of this approach is that it converts a static equation into a dynamic process. For example, if we start with x³ = x + 1, we can rearrange to x = ∛(x + 1), giving us the iterative formula x_{n+1} = ∛(x_n + 1). This formula becomes our recipe for generating successive approximations. **Example**: Given x² - 3x - 5 = 0, rearrange to x² = 3x + 5, then x = √(3x + 5). The iterative formula is x_{n+1} = √(3x_n + 5). ### Concept 2: Convergence and the Starting Value x₀ Convergence describes the behaviour of an iterative sequence as it approaches the true root. When a sequence converges, successive values get progressively closer together, eventually stabilising to the required degree of accuracy. The starting value x₀ plays a crucial role in this process. A good starting value, often estimated from a graph or chosen based on the context of the problem, helps the sequence converge more quickly. However, even a rough estimate will typically lead to convergence if the iterative formula is correctly constructed. Examiners often provide x₀ explicitly, such as "use x₀ = 2", removing the need for estimation. The convergence process is visual: imagine a spiral or staircase on a graph, with each iteration bringing you closer to the point where the curve intersects the solution. **Example**: For x_{n+1} = ∛(x_n + 1) with x₀ = 1, the sequence begins: x₁ = ∛2 ≈ 1.26000, x₂ ≈ 1.31244, x₃ ≈ 1.32207, x₄ ≈ 1.32417. Notice the values stabilising around 1.324. ![Numerical convergence visualised: cobweb diagram showing iteration steps x₀ → x₁ → x₂ → x₃ converging to the root](https://xnnrgnazirrqvdgfhvou.supabase.co/storage/v1/object/public/study-guide-assets/guide_8268753c-dac5-4047-87b4-2f519408a764/convergence_visual.png) ### Concept 3: Precision and the 'Ans' Key Technique Maintaining full precision throughout the iteration process is non-negotiable. Rounding intermediate values introduces cumulative errors that prevent convergence to the correct answer. The 'Ans' key on your calculator is your most powerful tool here. After calculating x₁, immediately input your formula using 'Ans' as the variable and press equals repeatedly. This technique ensures that the calculator uses the full stored precision (typically 10-12 digits) rather than the rounded display value. Candidates must write down intermediate values to at least five decimal places to demonstrate to examiners that the process is being followed correctly, even though the calculator is storing more digits internally. The final answer is then stated to the required accuracy, such as three significant figures or two decimal places. **Example**: Using a calculator for x_{n+1} = ∛(Ans + 1) starting with 1: Press 1, =, then type ∛(Ans+1), =, =, =, =. Each press generates the next iteration with full precision. ### Concept 4: Algebraic Rearrangement and 'Show That' Questions OCR frequently asks candidates to "show that" an equation f(x) = 0 can be rearranged to a given iterative form. This requires explicit algebraic working showing every step of the manipulation. Candidates must start with the original equation, clearly indicate each operation (adding, subtracting, dividing, taking roots), and arrive at the target form. Working backwards from the answer or skipping steps will lose method marks even if the final form is correct. Common rearrangement techniques include isolating x², taking square roots, isolating x³ and taking cube roots, or rearranging linear terms. Be particularly careful with negative signs and division by variables, as these are frequent sources of error. **Example**: Show that x³ - x - 1 = 0 can be rearranged to x = ∛(x + 1). Solution: - Start: x³ - x - 1 = 0 - Add x and 1 to both sides: x³ = x + 1 - Take cube root of both sides: x = ∛(x + 1) ✓ ![The iteration process: from equation f(x)=0 to converged root](https://xnnrgnazirrqvdgfhvou.supabase.co/storage/v1/object/public/study-guide-assets/guide_8268753c-dac5-4047-87b4-2f519408a764/iteration_process_diagram.png) ### Concept 5: Determining Roots to a Specified Accuracy The final stage of an iteration question requires stating the root to a specified degree of accuracy, such as "correct to 3 significant figures" or "to 2 decimal places". To achieve this, candidates must continue iterating until consecutive values agree to at least one more digit than required. For example, if the question asks for 3 significant figures, continue until the first four digits stabilise. This demonstrates that the sequence has genuinely converged rather than coincidentally produced similar values. The final answer should be clearly stated with appropriate rounding and labelling, such as "Therefore, the root is 1.32 to 3 s.f." Examiners award the final accuracy mark only if the working supports the stated answer. **Example**: If x₄ = 1.324717 and x₅ = 1.324718, these agree to 5 decimal places, so the root is 1.32 to 3 s.f. or 1.3 to 2 s.f. ## Mathematical Relationships ### Core Formula **Iterative Formula**: x_{n+1} = g(x_n) Where: - x_n is the current term in the sequence (the nth approximation) - x_{n+1} is the next term in the sequence (the (n+1)th approximation) - g(x_n) is a function of x_n derived from rearranging f(x) = 0 **Must memorise** - This formula structure is fundamental and must be understood, though specific rearrangements will be given or derived in context. ### Common Rearrangement Patterns | Original Equation | Rearranged Form | Iterative Formula | |-------------------|-----------------|-------------------| | x² = a | x = √a | x_{n+1} = √a | | x² = f(x) | x = √(f(x)) | x_{n+1} = √(f(x_n)) | | x³ = f(x) | x = ∛(f(x)) | x_{n+1} = ∛(f(x_n)) | | x = f(x) | x = f(x) | x_{n+1} = f(x_n) | | ax = f(x) | x = f(x)/a | x_{n+1} = f(x_n)/a | ### Convergence Criteria A sequence converges to accuracy of k significant figures when |x_{n+1} - x_n| becomes sufficiently small that the first k digits remain unchanged across successive iterations. ## Practical Applications Iteration is not merely an abstract mathematical technique; it underpins computational methods across science, engineering, and technology. Every time you use a calculator to find a square root or solve an equation, iteration is working behind the scenes. The Newton-Raphson method, a more advanced iterative technique, is used in computer graphics to render curves and surfaces. Financial modelling uses iteration to calculate compound interest and loan repayments when exact algebraic solutions are impractical. Engineers apply iterative methods to optimise designs, such as determining the ideal dimensions of a bridge support or the trajectory of a spacecraft. In physics, iteration helps solve differential equations that model everything from planetary motion to electrical circuits. Even weather forecasting relies on iterative numerical methods to approximate solutions to complex atmospheric equations. Understanding iteration at GCSE level provides a foundation for these real-world applications and prepares students for further study in STEM fields where numerical methods are indispensable. ## Podcast: Iteration Explained ![Educational podcast: Iteration in GCSE Further Mathematics (10 minutes)](https://xnnrgnazirrqvdgfhvou.supabase.co/storage/v1/object/public/study-guide-assets/guide_8268753c-dac5-4047-87b4-2f519408a764/iteration_podcast.mp3) Listen to this 10-minute educational podcast for a comprehensive audio guide to iteration, including core concepts, exam tips, common mistakes, and a quick-fire recall quiz. Perfect for revision on the go!

    Revision Podcast Transcript

    ITERATION IN GCSE FURTHER MATHEMATICS - 10-MINUTE EDUCATIONAL PODCAST Speaker: Female educator, warm and engaging tone [INTRO - 1 MINUTE] Hello and welcome to this study session on Iteration - one of the most powerful numerical methods you'll encounter in GCSE Further Mathematics. I'm here to guide you through everything you need to know to confidently tackle iteration questions in your OCR exam. Now, you might be wondering: what exactly is iteration, and why should I care? Well, imagine you're trying to solve an equation like x cubed minus x minus one equals zero. You can't factorise it easily, and the quadratic formula won't help because it's not a quadratic. This is where iteration comes to the rescue. It's a systematic method that lets you find approximate solutions to equations that would otherwise be impossible to solve by hand. The beauty of iteration is that it's like a mathematical treasure hunt. You make an educated guess, apply a formula repeatedly, and watch as your answers get closer and closer to the true solution. It's satisfying, it's powerful, and it's absolutely essential for your exam. So let's dive in. [CORE CONCEPTS - 5 MINUTES] Let's start with the fundamentals. Iteration is all about turning an equation of the form f of x equals zero into what we call an iterative formula: x subscript n plus one equals g of x subscript n. This might look intimidating at first, but think of it as a recipe. You start with an ingredient - your initial value x naught - and you follow the same steps over and over until you get the result you want. The first crucial step is rearranging your equation. If you're given something like x cubed equals x plus one, you need to isolate x on one side. You might rearrange it to x equals the cube root of x plus one. This becomes your iterative formula: x subscript n plus one equals the cube root of x subscript n plus one. The key here is algebraic manipulation - and this is where many candidates lose marks. You must show every single step clearly. Don't skip lines, don't work backwards, and definitely don't just write down the final formula without justification. Once you have your iterative formula, you need a starting value - we call this x naught. Sometimes the question will give you this starting value, like "use x naught equals two." Other times, you might need to estimate it from a graph or use your mathematical intuition. A good starting value helps the iteration converge faster, but even a rough estimate will usually get you there eventually. Now comes the repetitive part - and this is where your calculator becomes your best friend. You substitute x naught into your formula to get x one. Then you substitute x one to get x two. Then x two to get x three, and so on. Here's the golden rule that will save you marks: use the ANS key on your calculator. Press equals, then immediately type your formula using ANS as the variable, and keep pressing equals. This maintains full precision throughout your calculations and prevents rounding errors. Let me give you a concrete example. Suppose we're solving x cubed minus x minus one equals zero, and we've rearranged it to x equals the cube root of x plus one. If we start with x naught equals one, we get: x one equals the cube root of one plus one, which is the cube root of two, approximately one point two six. Then x two equals the cube root of one point two six plus one, which is approximately one point three one two. Then x three is approximately one point three two two. Notice how the values are getting closer together? That's convergence in action. You keep going until consecutive values agree to the required degree of accuracy. If the question asks for three significant figures, you need to continue until at least the first three digits stop changing. Typically, you'll need to calculate four or five iterations and write them all down to at least five decimal places. This shows the examiner you understand the process and aren't just guessing. One more thing about convergence: not all rearrangements work. Some iterative formulas diverge, meaning the values get further apart rather than closer together. OCR will always give you a formula that converges, but you should be aware that the way you rearrange the equation matters. If you're ever asked to suggest your own rearrangement, think carefully about which form will bring values together rather than push them apart. [EXAM TIPS & COMMON MISTAKES - 2 MINUTES] Now let's talk about how to maximise your marks in the exam. Iteration questions typically appear as four to six mark questions, and they follow a predictable structure. You'll usually be asked to show that an equation rearranges to a given form, then use iteration to find a root to a specified accuracy. For the "show that" part, you must show every algebraic step. Start with the original equation, clearly state what operation you're performing, and arrive at the required form. Examiners are looking for logical progression - if you jump straight to the answer, you'll lose method marks even if you're correct. For the iteration part, write down at least your first three or four values to five decimal places. Label them clearly: x naught, x one, x two, x three. Then state your final answer to the required accuracy. If the question asks for three significant figures, write something like "therefore the root is one point three two to three significant figures." Now, the mistakes. The biggest one? Rounding too early. If you round x one to three significant figures, then use that rounded value to calculate x two, your errors compound and you'll never reach the correct answer. Keep full precision until the very end. Second mistake: incorrect algebra when rearranging. Watch out for negative signs, especially when you're moving terms across the equals sign. And if you're dividing by x, remember you can't do that if x might be zero. Third mistake: stopping too soon. Just because x two and x three look similar doesn't mean they've converged to three significant figures. Always calculate one or two extra iterations to be sure. And finally, not using the ANS key. I can't stress this enough - it's the difference between a correct answer and one that's slightly off due to rounding errors. [QUICK-FIRE RECALL QUIZ - 1 MINUTE] Let's test your understanding with some quick-fire questions. Pause after each one and see if you can answer. Question one: What is the standard form of an iterative formula? Answer: x subscript n plus one equals g of x subscript n. Question two: Why must you use the ANS key on your calculator? Answer: To maintain full precision and avoid cumulative rounding errors. Question three: How many decimal places should you write down for your intermediate iterations? Answer: At least five decimal places. Question four: What does it mean when an iterative sequence converges? Answer: The values get closer and closer together, approaching the true root. Question five: In a "show that" question, can you work backwards from the answer? Answer: No - you must show logical forward progression from the starting equation. [SUMMARY & SIGN-OFF - 1 MINUTE] Let's wrap up. Iteration is a powerful method for solving equations that can't be solved algebraically. The process is straightforward: rearrange your equation into the form x subscript n plus one equals g of x subscript n, choose a starting value, and repeatedly apply the formula until your values converge to the required accuracy. Remember the key exam techniques: show all algebraic steps in rearrangement questions, use the ANS key to maintain precision, write down multiple iterations to at least five decimal places, and don't round until you state your final answer. Iteration questions are highly structured and predictable, which means they're a fantastic opportunity to secure marks if you follow the method carefully. Practice a few examples, get comfortable with your calculator, and you'll find these questions become routine. Thank you for listening, and best of luck with your revision. Keep practising, stay precise, and remember - iteration is just a systematic treasure hunt for solutions. You've got this!

    Key Terms & Definitions

    Iteration
    A numerical method for finding approximate solutions to equations by repeatedly applying a formula to generate a sequence of values that converge toward the true root.
    Iterative Formula
    A formula of the form x_{n+1} = g(x_n) that defines each term in a sequence based on the previous term, derived by rearranging an equation f(x) = 0.
    Convergence
    The property of an iterative sequence where successive terms get progressively closer together, approaching a limiting value (the root of the equation).
    Starting Value (x₀)
    The initial value used to begin an iterative sequence, often provided in the question or estimated from a graph.
    Root
    A value of x for which f(x) = 0; the solution to the equation. In iteration, the root is the limiting value toward which the sequence converges.
    Precision
    The number of digits or decimal places to which a value is stated. Full calculator precision (typically 10-12 digits) must be maintained during iteration to avoid cumulative rounding errors.
    Rearrangement
    The algebraic process of transforming an equation f(x) = 0 into the form x = g(x), which then becomes the iterative formula x_{n+1} = g(x_n).
    Significant Figures
    The number of meaningful digits in a number, counting from the first non-zero digit. Used to specify the required accuracy of a final answer.

    Worked Examples

    Practice Questions

    Iteration

    Iteration is a powerful numerical method that allows you to find approximate solutions to equations that cannot be solved algebraically. By repeatedly applying an iterative formula of the form x_{n+1} = g(x_n), you systematically converge on roots to a specified degree of accuracy. This topic is essential for OCR GCSE Further Mathematics and typically appears as structured 4-6 mark questions testing both algebraic manipulation and precise calculator technique.

    8
    Min Read
    3
    Examples
    5
    Questions
    8
    Key Terms
    🎙 Podcast Episode
    Iteration
    0:00-0:00

    Study Notes

    Header image for Iteration in GCSE Further Mathematics

    Overview

    Iteration represents one of the most elegant and practical numerical methods in GCSE Further Mathematics. When faced with equations such as x³ - x - 1 = 0 that resist traditional algebraic techniques like factorisation or the quadratic formula, iteration provides a systematic pathway to approximate solutions with remarkable precision. The method transforms an equation f(x) = 0 into an iterative formula x_{n+1} = g(x_n), which when applied repeatedly from a starting value x₀, generates a sequence of values that converge toward the true root. OCR assesses this topic rigorously, expecting candidates to demonstrate both algebraic fluency in deriving iterative formulas and technical precision in executing calculations using the 'Ans' function on scientific calculators. Iteration questions typically appear as 4-6 mark structured problems, often bridging algebraic manipulation with graphical interpretation. The topic connects deeply with functions, graphs, and solving equations across the specification, making it a synoptic skill that rewards methodical working and attention to detail. Understanding iteration not only secures valuable exam marks but also provides insight into how computers and calculators solve complex equations behind the scenes.

    Key Concepts

    Concept 1: The Iterative Formula x_{n+1} = g(x_n)

    The foundation of iteration lies in transforming an equation from the form f(x) = 0 into an iterative formula x_{n+1} = g(x_n). This transformation requires algebraic manipulation to isolate x on one side of the equation. The subscript notation is crucial: x_n represents the current value in the sequence, while x_{n+1} represents the next value. Think of this as a function machine where you input one value and receive the next approximation as output. The beauty of this approach is that it converts a static equation into a dynamic process. For example, if we start with x³ = x + 1, we can rearrange to x = ∛(x + 1), giving us the iterative formula x_{n+1} = ∛(x_n + 1). This formula becomes our recipe for generating successive approximations.

    Example: Given x² - 3x - 5 = 0, rearrange to x² = 3x + 5, then x = √(3x + 5). The iterative formula is x_{n+1} = √(3x_n + 5).

    Concept 2: Convergence and the Starting Value x₀

    Convergence describes the behaviour of an iterative sequence as it approaches the true root. When a sequence converges, successive values get progressively closer together, eventually stabilising to the required degree of accuracy. The starting value x₀ plays a crucial role in this process. A good starting value, often estimated from a graph or chosen based on the context of the problem, helps the sequence converge more quickly. However, even a rough estimate will typically lead to convergence if the iterative formula is correctly constructed. Examiners often provide x₀ explicitly, such as "use x₀ = 2", removing the need for estimation. The convergence process is visual: imagine a spiral or staircase on a graph, with each iteration bringing you closer to the point where the curve intersects the solution.

    Example: For x_{n+1} = ∛(x_n + 1) with x₀ = 1, the sequence begins: x₁ = ∛2 ≈ 1.26000, x₂ ≈ 1.31244, x₃ ≈ 1.32207, x₄ ≈ 1.32417. Notice the values stabilising around 1.324.

    Numerical convergence visualised: cobweb diagram showing iteration steps x₀ → x₁ → x₂ → x₃ converging to the root

    Concept 3: Precision and the 'Ans' Key Technique

    Maintaining full precision throughout the iteration process is non-negotiable. Rounding intermediate values introduces cumulative errors that prevent convergence to the correct answer. The 'Ans' key on your calculator is your most powerful tool here. After calculating x₁, immediately input your formula using 'Ans' as the variable and press equals repeatedly. This technique ensures that the calculator uses the full stored precision (typically 10-12 digits) rather than the rounded display value. Candidates must write down intermediate values to at least five decimal places to demonstrate to examiners that the process is being followed correctly, even though the calculator is storing more digits internally. The final answer is then stated to the required accuracy, such as three significant figures or two decimal places.

    Example: Using a calculator for x_{n+1} = ∛(Ans + 1) starting with 1: Press 1, =, then type ∛(Ans+1), =, =, =, =. Each press generates the next iteration with full precision.

    Concept 4: Algebraic Rearrangement and 'Show That' Questions

    OCR frequently asks candidates to "show that" an equation f(x) = 0 can be rearranged to a given iterative form. This requires explicit algebraic working showing every step of the manipulation. Candidates must start with the original equation, clearly indicate each operation (adding, subtracting, dividing, taking roots), and arrive at the target form. Working backwards from the answer or skipping steps will lose method marks even if the final form is correct. Common rearrangement techniques include isolating x², taking square roots, isolating x³ and taking cube roots, or rearranging linear terms. Be particularly careful with negative signs and division by variables, as these are frequent sources of error.

    Example: Show that x³ - x - 1 = 0 can be rearranged to x = ∛(x + 1).

    Solution:

    • Start: x³ - x - 1 = 0
    • Add x and 1 to both sides: x³ = x + 1
    • Take cube root of both sides: x = ∛(x + 1) ✓

    The iteration process: from equation f(x)=0 to converged root

    Concept 5: Determining Roots to a Specified Accuracy

    The final stage of an iteration question requires stating the root to a specified degree of accuracy, such as "correct to 3 significant figures" or "to 2 decimal places". To achieve this, candidates must continue iterating until consecutive values agree to at least one more digit than required. For example, if the question asks for 3 significant figures, continue until the first four digits stabilise. This demonstrates that the sequence has genuinely converged rather than coincidentally produced similar values. The final answer should be clearly stated with appropriate rounding and labelling, such as "Therefore, the root is 1.32 to 3 s.f." Examiners award the final accuracy mark only if the working supports the stated answer.

    Example: If x₄ = 1.324717 and x₅ = 1.324718, these agree to 5 decimal places, so the root is 1.32 to 3 s.f. or 1.3 to 2 s.f.

    Mathematical Relationships

    Core Formula

    Iterative Formula: x_{n+1} = g(x_n)

    Where:

    • x_n is the current term in the sequence (the nth approximation)
    • x_{n+1} is the next term in the sequence (the (n+1)th approximation)
    • g(x_n) is a function of x_n derived from rearranging f(x) = 0

    Must memorise - This formula structure is fundamental and must be understood, though specific rearrangements will be given or derived in context.

    Common Rearrangement Patterns

    Original EquationRearranged FormIterative Formula
    x² = ax = √ax_{n+1} = √a
    x² = f(x)x = √(f(x))x_{n+1} = √(f(x_n))
    x³ = f(x)x = ∛(f(x))x_{n+1} = ∛(f(x_n))
    x = f(x)x = f(x)x_{n+1} = f(x_n)
    ax = f(x)x = f(x)/ax_{n+1} = f(x_n)/a

    Convergence Criteria

    A sequence converges to accuracy of k significant figures when |x_{n+1} - x_n| becomes sufficiently small that the first k digits remain unchanged across successive iterations.

    Practical Applications

    Iteration is not merely an abstract mathematical technique; it underpins computational methods across science, engineering, and technology. Every time you use a calculator to find a square root or solve an equation, iteration is working behind the scenes. The Newton-Raphson method, a more advanced iterative technique, is used in computer graphics to render curves and surfaces. Financial modelling uses iteration to calculate compound interest and loan repayments when exact algebraic solutions are impractical. Engineers apply iterative methods to optimise designs, such as determining the ideal dimensions of a bridge support or the trajectory of a spacecraft. In physics, iteration helps solve differential equations that model everything from planetary motion to electrical circuits. Even weather forecasting relies on iterative numerical methods to approximate solutions to complex atmospheric equations. Understanding iteration at GCSE level provides a foundation for these real-world applications and prepares students for further study in STEM fields where numerical methods are indispensable.

    Podcast: Iteration Explained

    Educational podcast: Iteration in GCSE Further Mathematics (10 minutes)

    Listen to this 10-minute educational podcast for a comprehensive audio guide to iteration, including core concepts, exam tips, common mistakes, and a quick-fire recall quiz. Perfect for revision on the go!

    Visual Resources

    2 diagrams and illustrations

    The iteration process: from equation f(x)=0 to converged root
    The iteration process: from equation f(x)=0 to converged root
    Numerical convergence visualised: cobweb diagram showing iteration steps x₀ → x₁ → x₂ → x₃ converging to the root
    Numerical convergence visualised: cobweb diagram showing iteration steps x₀ → x₁ → x₂ → x₃ converging to the root

    Interactive Diagrams

    2 interactive diagrams to visualise key concepts

    Complete iteration process flowchart showing the systematic steps from initial equation to converged root

    Step-by-step algebraic rearrangement showing how to transform an equation into iterative form

    Worked Examples

    3 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    The equation x² + x - 7 = 0 has a root between 2 and 3. Show that this equation can be rearranged to x = √(7 - x).

    2 marks
    foundation

    Hint: Start by moving the x term to the right-hand side, then isolate x² before taking the square root.

    Q2

    Use the iterative formula x_{n+1} = √(7 - x_n) with x₀ = 2 to find a root of x² + x - 7 = 0 correct to 1 decimal place.

    3 marks
    standard

    Hint: Calculate at least 4 iterations to 5 decimal places, then check that your answer to 1 d.p. is stable across consecutive terms.

    Q3

    The equation x³ - 2x - 5 = 0 has a root near x = 2. (a) Show that the equation can be rearranged to x = ∛(2x + 5). (b) Use the iterative formula x_{n+1} = ∛(2x_n + 5) with x₀ = 2 to find the root correct to 3 significant figures.

    5 marks
    standard

    Hint: For part (a), show every algebraic step clearly. For part (b), use the Ans key and calculate at least 5 iterations to demonstrate convergence to 3 s.f.

    Q4

    A student uses the iterative formula x_{n+1} = (x_n³ + 3)/4 with x₀ = 1.5 to solve the equation 4x - x³ - 3 = 0. Explain why the student's sequence of values is likely to diverge rather than converge.

    2 marks
    challenging

    Hint: Consider what happens when you substitute values into the formula. Does x_{n+1} get closer to x_n or further away?

    Q5

    The iterative formula x_{n+1} = √(3x_n + 1) is used with x₀ = 2. (a) Calculate x₁, x₂, and x₃ to 4 decimal places. (b) By considering your answers, suggest to what value the sequence is converging. (c) Verify your answer by substituting it into the original equation x² - 3x - 1 = 0.

    6 marks
    challenging

    Hint: For part (c), if your suggested value is correct, substituting it into x² - 3x - 1 should give a result very close to zero.

    Key Terms

    Essential vocabulary to know