AQA · A-Level · Mathematics
Course version: 7357 · Version from Sept 2017
B: Algebra and functions: Use and manipulate surds, including rationalising the denominator.
A surd is an irrational root such as √2 or √5.
Study notes
From the checked teaching notes for this specification point.
The idea
A surd is an irrational root such as √2 or √5. Simplify by extracting the largest square factor: √ab = √a × √b, so √50 = √(25×2) = 5√2. Combine like surds: 3√2 + 5√2 = 8√2. Multiply using √a × √b = √(ab), and expand brackets normally, e.g. (2+√3)(2−√3) = 4 − 3 = 1. Rationalising the denominator rewrites a fraction so the denominator is rational. For a single surd, multiply numerator and denominator by that surd: 1/√2 = √2/2. For a denominator a ± √b, multiply numerator and denominator by the conjugate a ∓ √b, using the difference of two squares. This skill gives exact answers in geometry, trigonometry and calculus.
What earns the marks
- Simplify surds by extracting the largest square factor, e.g. √72 = 6√2, and combine like surds through addition and subtraction.
- Multiply and divide surds, including expanding brackets such as (3+√2)(3−√2) = 7, and simplify the result.
- Rationalise a denominator containing a single surd by multiplying numerator and denominator by that surd, e.g. 5/√3 = 5√3/3.
- Rationalise a denominator of the form a ± √b by multiplying numerator and denominator by the conjugate, and simplify the resulting expression.
- Use surds in contextual problems, such as finding exact lengths in right-angled triangles or simplifying expressions in coordinate geometry.
Common mistakes and how to put them right
Writing √(a+b) = √a + √b, e.g. √(9+16) = 3+4 = 7 instead of 5.
Put it right: The square root of a sum is not the sum of the square roots; evaluate the sum first or leave as a single surd.
Multiplying only the numerator by the conjugate when rationalising, e.g. writing 1/(2+√3) = 2−√3 without multiplying the denominator.
Put it right: Multiply both numerator and denominator by the conjugate: 1/(2+√3) = (2−√3)/((2+√3)(2−√3)) = (2−√3)/1 = 2−√3. The result is correct here, but the method must apply to both parts to be valid in general.
Simplifying √(a² + b²) as a + b, e.g. √(3²+4²) = 3+4 = 7 instead of 5.
Put it right: This is a common error in Pythagoras; evaluate the sum of squares first, then take the square root.
Incorrectly expanding brackets with surds, e.g. (√2+√3)² = 2+3 = 5 instead of 5+2√6.
Put it right: Use (a+b)² = a² + 2ab + b², remembering that √2×√3 = √6.
Exam tips
- Always simplify surds fully before combining; look for the largest square factor to avoid multiple steps.
- When rationalising a denominator with two terms, multiply by the conjugate and show the expansion clearly, as method marks are often awarded for the correct conjugate.
- Check whether the question requires an exact answer in surd form; do not convert to a decimal unless asked, as this may lose accuracy marks.
- For expressions like (a+√b)(a−√b), recognise the difference of two squares to simplify quickly to a² − b.
Try the lesson
The start of the B: Algebra and functions: Use and manipulate surds, including rationalising the denominator. lesson, made from checked teaching notes for this specification point.
Have a go first
Simplify √50. Select the correct answer.
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