AQA · GCSE · Mathematics

    Course version: 8300 · Version from Sept 2015

    Graphs: use the form y = mx + c to identify perpendicular lines (Higher tier only)

    For Higher tier, two straight lines are perpendicular if the product of their gradients is −1.

    • 2 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    For Higher tier, two straight lines are perpendicular if the product of their gradients is −1. In the form y = mx + c, if one line has gradient m, a perpendicular line has gradient −1/m (the negative reciprocal). For example, a line with gradient 2 is perpendicular to a line with gradient −1/2 because 2 × (−1/2) = −1. To identify perpendicular lines from equations, rearrange each into y = mx + c, read off the gradients, and check whether their product is −1. A horizontal line (gradient 0) is perpendicular to a vertical line, but vertical lines cannot be written in the form y = mx + c.

    What earns the marks

    • State that perpendicular lines have gradients whose product is −1.
    • Find the negative reciprocal of a given gradient to obtain the perpendicular gradient.
    • Rearrange a linear equation into the form y = mx + c to identify its gradient.
    • Check whether two lines are perpendicular by multiplying their gradients and testing whether the result is −1.
    • Recognise that a horizontal line (gradient 0) is perpendicular to a vertical line, which cannot be written as y = mx + c.

    Common mistakes and how to put them right

    • Thinking that perpendicular lines have the same gradient.

      Put it right by using the negative reciprocal relationship m₁ × m₂ = −1.

    • Forgetting the negative sign when finding the perpendicular gradient.

      Put it right by changing the sign as well as flipping the fraction.

    • Assuming that any two lines with different gradients are perpendicular.

      Put it right by checking that the product of the gradients is exactly −1.

    • Trying to write a vertical line in the form y = mx + c.

      Put it right by recognising that vertical lines have equations of the form x = k and are perpendicular to horizontal lines.

    Exam tips

    • Rearrange equations into y = mx + c before comparing gradients.
    • Write down the product of the two gradients to show clearly whether it equals −1.
    • Remember that the negative reciprocal of a whole number m is −1/m, and of a fraction a/b is −b/a.

    Try the lesson

    The start of the Graphs: use the form y = mx + c to identify perpendicular lines (Higher tier only) lesson, made from checked teaching notes for this specification point.

    Have a go first

    A line has equation y = 4x − 7. A second line is perpendicular to it. What is the gradient of the second line?

    Listen

    For Higher tier, two straight lines are perpendicular if the product of their gradients is −1. In the form y = mx + c, if one line has gradient m, a perpendicular line has gradient −1/m (the negative reciprocal). For example, a line with gradient 2 is perpendicular to a line with gradient −1/2 because 2 × (−1/2) = −1. To identify perpendicular lines from equations, rearrange each into y = mx + c, read off the gradients, and check whether their product is −1. A horizontal line (gradient 0) is perpendicular to a vertical line, but vertical lines cannot be written in the form y = mx + c.

    Key words

    Say what each word means before you turn the card.

    Perpendicular lines

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    Negative reciprocals

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    See every definition
    Perpendicular lines
    Two straight lines are perpendicular if the product of their gradients is −1.
    Negative reciprocals
    If one line has gradient m, a perpendicular line has gradient −1/m, the negative reciprocal.

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