Subject: Mathematics | Level: GCSE | Exam Board: OCR
Master the essential GCSE Maths topic of Fractions, Decimals, and Percentages (FDP). This guide will equip you to confidently switch between forms, tackle complex percentage problems, and secure maximum marks in your OCR exam. It's a cornerstone of the curriculum, vital for both calculator and non-calculator papers.
Revision Notes & Key Concepts
Key Terms & Definitions
- Improper Fraction
- A fraction where the numerator is greater than or equal to the denominator (e.g., 5/4).
- Mixed Number
- A number consisting of an integer and a proper fraction (e.g., 1 1/4).
- Reciprocal
- The reciprocal of a number is 1 divided by that number. For a fraction, you 'flip' it (e.g., the reciprocal of 2/3 is 3/2).
- Multiplier
- The decimal used to calculate a percentage change in a single step (e.g., a 25% increase uses a multiplier of 1.25).
- Compound Interest
- Interest calculated on the initial principal, which also includes all of the accumulated interest from previous periods.
- Highest Common Factor (HCF)
- The largest number that divides into two or more numbers without a remainder.
Worked Examples
Worked Example
Question: Calculate the value of 3 1/3 - 2 3/5. Give your answer as a mixed number in its simplest form.
Solution: Step 1: Convert the mixed numbers to improper fractions. 3 1/3 = (3 × 3 + 1) / 3 = 10/3 2 3/5 = (2 × 5 + 3) / 5 = 13/5 Step 2: Find a common denominator for the fractions. The lowest common multiple of 3 and 5 is 15. Step 3: Convert the fractions to have the common denominator. 10/3 = (10 × 5) / (3 × 5) = 50/15 13/5 = (13 × 3) / (5 × 3) = 39/15 Step 4: Subtract the second fraction from the first. 50/15 - 39/15 = 11/15 Final answer: 11/15
Worked Example
Question: In a sale, a television is reduced by 20%. The sale price is £480. What was the original price of the television?
Solution: Step 1: Identify the percentage remaining after the reduction. A 20% reduction means 100% - 20% = 80% of the original price remains. Step 2: Express this as a decimal multiplier. 80% = 0.8. Step 3: Set up an equation. Let the original price be 'x'. Then 0.8 * x = £480. Step 4: Solve for x by dividing the sale price by the multiplier. x = £480 ÷ 0.8 x = £600 Final answer: £600
Worked Example
Question: Jodie invests £1200 in a savings account that pays 3% compound interest per annum. She leaves the money in the account for 4 years. How much money will be in the account at the end of the 4 years? Give your answer correct to the nearest penny.
Solution: Step 1: Determine the multiplier for a 3% increase. Multiplier = 1 + (3/100) = 1.03. Step 2: Apply the multiplier for each year of the investment. Since it's for 4 years, the calculation is £1200 × (1.03)^4. Step 3: Calculate the value. Year 1: £1200 × 1.03 = £1236 Year 2: £1236 × 1.03 = £1273.08 Year 3: £1273.08 × 1.03 = £1311.2724 Year 4: £1311.2724 × 1.03 = £1350.610572 Alternatively, using the power: £1200 × (1.03)^4 = £1350.610572 Step 4: Round the answer to the nearest penny. £1350.61 Final answer: £1350.61
Practice Questions
Question: Express 7/8 as a decimal and a percentage.
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Question: A bag contains 60 sweets. 1/4 are red, 1/3 are green, and the rest are blue. How many blue sweets are there?
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Question: The price of a train ticket is increased by 5% to £94.50. What was the price before the increase?
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Question: Calculate (4/5) × (3/8). Give your answer as a fraction in its simplest form.
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Question: A house is bought for £200,000. Its value increases by 10% in the first year, and then by 20% in the second year. What is its value after 2 years?
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