Pearson Edexcel · GCSE · Mathematics

    Course version: 1MA1 · Version from Mar 2026

    Algebra - Graphs: plot graphs of equations that correspond to straight-line graphs in the coordinate plane; use the form y = mx + c to identify parallel and perpendicular lines; find the equation of the line through two given points or through one point with a given gradient (Higher tier)

    Higher tier only; the addition to shared content is perpendicular lines.

      Study notes

      From the checked teaching notes for this specification point.

      The idea

      Higher tier only; the addition to shared content is perpendicular lines. In y = mx + c, m is the gradient and c the y-intercept. Parallel lines share the same gradient; perpendicular lines have gradients multiplying to −1, so each is the negative reciprocal of the other. A vertical line has no gradient and is perpendicular to a horizontal one. Rearrange so y stands alone before comparing: 3y = 6x + 5 has gradient 2, not 6. To plot a straight-line graph, substitute two or three x-values, plot the points and join them with a ruler. Through two points, find the gradient as the change in y over the change in x, then substitute one point to get c. For y = 4x − 1 through (8, 5), the perpendicular gradient is −1/4, and 5 = −2 + c gives c = 7, so y = −x/4 + 7.

      What earns the marks

      • Plotting a straight-line graph by substituting x-values, plotting the points and joining them with a ruled line.
      • Reading the gradient from y = mx + c only after rearranging so that y is on its own.
      • Identifying parallel lines by equal gradients, and perpendicular lines by gradients multiplying to −1.
      • Using the negative reciprocal as the gradient of a perpendicular line, even if later work is wrong.
      • Finding the gradient through two points as the change in y divided by the change in x, then substituting one point to find c.
      • The finished equation, written in whichever form the question asks for.

      Common mistakes and how to put them right

      • Turning the gradient upside down but leaving its sign alone, so pairing gradient 5 with 1/5 instead of −1/5.

      • Changing the sign but not turning the gradient upside down, so pairing gradient 5 with −5.

      • Reading the gradient straight off an equation such as 2y = 8x + 3 without dividing through first.

      • Keeping the intercept of the original line instead of substituting the point the question gives.

      • Joining plotted points freehand or with too few points, so the line is not straight.

      Exam tips

      • Write the perpendicular gradient as a fraction and cancel it, so −4/8 becomes −1/2 before you substitute.
      • Check the pair by multiplying the two gradients together, because anything other than −1 means one of them is wrong.
      • If a particular form of the equation is asked for, rearrange as the very last step so the method marks are already safe.

      Try the lesson

      The start of the Algebra - Graphs: plot graphs of equations that correspond to straight-line graphs in the coordinate plane; use the form y = mx + c to identify parallel and perpendicular lines; find the equation of the line through two given points or through one point with a given gradient (Higher tier) lesson, made from checked teaching notes for this specification point.

      Have a go first

      A straight line passes through the points (2, 7) and (6, 19). Find the equation of the line in the form y = mx + c.

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      Test your understanding of Algebra - Graphs: plot graphs of equations that correspond to straight-line graphs in the coordinate plane; use the form y = mx + c to identify parallel and perpendicular lines; find the equation of the line through two given points or through one point with a given gradient (Higher tier)

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