Eduqas · GCSE · Mathematics

    Course version: WJEC-GCSE-Mathematics · Version from Mar 2026

    Algebra

    Algebra is the language of mathematics, using letters to represent unknown values and general rules. Mastering algebra unlocks the ability to solve complex problems across the entire specification, making it a critical foundation for exam success.

    • 8 min read
    • 3 worked examples
    • 5 practice questions
    • 6 key terms

    Study Notes

    Overview

    Algebra forms the structural backbone of the GCSE Mathematics specification. Rather than calculating with specific numbers, algebra allows candidates to work with general rules, patterns, and unknown values using letters. This topic is heavily weighted in both Foundation and Higher tiers, typically accounting for 20-30% of the total marks available across the papers.

    Mastering algebra is not just about memorising rules; it is about developing logical, step-by-step problem-solving skills. The examiner will look for clear, methodical working out, and method marks are frequently awarded even when the final answer is incorrect. Algebra connects deeply with other topics, particularly Geometry (e.g., finding the equation of a line or calculating missing angles) and Probability (e.g., setting up equations to find unknown probabilities).

    Typical exam questions range from straightforward skills tests like expanding brackets and factorising, to complex, multi-step problem-solving questions where candidates must form their own equations from a given context before solving them.

    Key Concepts

    Concept 1: Simplifying and Manipulating Expressions

    Before you can solve equations, you must be fluent in manipulating expressions. An expression is a collection of terms without an equals sign (e.g., 3x + 4y - 2). The fundamental rule here is collecting like terms. "Like terms" must have the exact same letter(s) raised to the exact same power.

    Why it works: Think of variables as objects. If you have 3 apples (3a) and someone gives you 2 more apples (2a), you have 5 apples (5a). However, you cannot combine apples (a) and bananas (b). Similarly, x and x^2 represent different dimensions (a line vs. an area) and cannot be added together.

    Example: Simplify 4x + 3y - x + 5y
    Step 1: Group the x terms: 4x - x = 3x
    Step 2: Group the y terms: 3y + 5y = 8y
    Final Answer: 3x + 8y

    Types of Algebraic ExpressionsOpen full-size image (opens in a new tab)

    Concept 2: Expanding Brackets

    Expanding brackets involves multiplying the term on the outside by every term on the inside. For double brackets, every term in the first bracket must be multiplied by every term in the second bracket. This is crucial for quadratic expressions.

    Why it works: Expanding brackets is an application of the distributive property of multiplication. Geometrically, expanding (x+2)(x+3) is equivalent to finding the total area of a rectangle with sides (x+2) and (x+3) by calculating the areas of its four smaller rectangular sections.

    Example: Expand and simplify (x + 4)(x - 2)
    First: x \times x = x^2
    Outer: x \times -2 = -2x
    Inner: 4 \times x = 4x
    Last: 4 \times -2 = -8
    Simplify: x^2 - 2x + 4x - 8 = x^2 + 2x - 8

    Concept 3: Factorising

    Factorising is the exact reverse of expanding. It means taking an expression and writing it as a product of its factors, introducing brackets. For quadratics (ax^2 + bx + c), you are typically looking for two numbers that multiply to give c and add to give b.

    Why it works: Factorising breaks down a complex expression into simpler building blocks (factors). This is essential for solving quadratic equations, because if two brackets multiply to equal zero, one of those brackets MUST equal zero (the zero product property).

    Step-by-step guide to factorising quadraticsOpen full-size image (opens in a new tab)

    Concept 4: Solving Equations

    An equation states that two expressions are equal. To "solve" an equation means to find the specific value(s) of the unknown variable that makes the statement true. The golden rule is balance: whatever operation you perform on one side of the equals sign, you must perform on the other.

    Why it works: An equation is like a balanced set of scales. If you remove a weight from the left side, the scales tip. To restore balance, you must remove the exact same weight from the right side.

    Example: Solve 3(2x - 1) = 21
    Step 1: Expand the bracket: 6x - 3 = 21
    Step 2: Add 3 to both sides: 6x = 24
    Step 3: Divide by 6: x = 4

    Concept 5: Simultaneous Equations

    Sometimes you have two unknowns (e.g., x and y) and two different equations linking them. You must find the pair of values that satisfies both equations at the same time. The most common method is elimination, where you manipulate the equations so that adding or subtracting them eliminates one of the variables.

    Why it works: Graphically, each linear equation represents a straight line. The solution to a pair of simultaneous equations is the exact (x, y) coordinate where the two lines intersect.

    Simultaneous Equations Method SelectionOpen full-size image (opens in a new tab)

    Concept 6: Sequences

    A sequence is an ordered list of numbers following a specific rule. The most common type at GCSE is an arithmetic (or linear) sequence, which increases or decreases by a constant amount each time. Candidates must be able to find the n^{th} term formula, which allows you to calculate any term in the sequence without writing out the whole list.

    Why it works: The n^{th} term relates the position of the number in the sequence (n) to its value. The common difference becomes the multiplier for n, and you adjust by finding what the "zero term" would be.

    Concept 7: Inequalities

    Inequalities are similar to equations but represent a range of values rather than a single specific value. They use symbols like < (less than) and \ge (greater than or equal to).

    Why it works: Inequalities follow the same balancing rules as equations, with one critical exception: multiplying or dividing by a negative number reverses the direction of the inequality sign. This is because multiplying by a negative reflects values across zero on the number line (e.g., 3 < 5, but -3 > -5).

    Mathematical/Scientific Relationships

    The following formulas and relationships are critical for this topic:

    • Quadratic Formula: x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}
      • What it means: Solves any quadratic equation ax^2 + bx + c = 0.
      • When to use: Use when a quadratic equation cannot be easily factorised. (Given on the formula sheet for most boards, but candidates must know how to substitute values correctly).
    • Difference of Two Squares: a^2 - b^2 = (a - b)(a + b)
      • What it means: A specific pattern for factorising quadratics where there is no middle 'x' term and both terms are perfect squares separated by a minus sign.
      • When to use: Quickly factorising expressions like x^2 - 25 into (x-5)(x+5). (Must memorise).
    • n^{th} Term of an Arithmetic Sequence: n^{th} \text{ term} = dn + (a - d)
      • What it means: d is the common difference, a is the first term.
      • When to use: To find the general rule for a sequence that goes up or down by the same amount each time. (Must memorise).
    • Equation of a Straight Line: y = mx + c
      • What it means: m is the gradient (steepness), c is the y-intercept (where the line crosses the y-axis).
      • When to use: When plotting linear graphs or finding the equation from a drawn line. (Must memorise).

    Key features of a quadratic graphOpen full-size image (opens in a new tab)

    Practical Applications

    While algebra often feels abstract, it is the underlying language for modeling the real world:

    • Finance and Business: Calculating break-even points, profit margins, and compound interest rates relies heavily on algebraic formulas and exponential growth models.
    • Engineering and Physics: Designing structures requires solving complex simultaneous equations to balance forces. The trajectory of a thrown object (like a football or a missile) is modeled perfectly by a quadratic parabola.
    • Computer Science: Algorithms and programming logic are fundamentally built on algebraic variables, boolean logic (inequalities), and iterative sequences.

    Listen to our podcast episode to reinforce these concepts:

    Check what you remember

    Read the wording for your board, then hide it and explain Term in your own words. Rough notes are fine. This is a self-check, with no mark or grade.

    Reference: Eduqas

    A single number, a single variable, or numbers and variables multiplied together (e.g., $4$, $x$, $3xy^2$).
    Eduqas · Algebra

    Visual Resources

    1 diagram and illustration

    Solving Quadratics Flowchart
    Solving Quadratics Flowchart

    Interactive Diagrams

    2 interactive diagrams to visualise key concepts

    Conceptual Flow Outline

    Start: ax² + bx + c = 0
    ➔Is a = 1?
    Is a = 1?
    ➔"Yes"Try factorising\nFind two numbers\nthat × to c and + to b
    ➔"No"Try ac method\nFind two numbers\nthat × to ac and + to b
    Try factorising\nFind two numbers\nthat × to c and + to b
    ➔Factorisable?
    Try ac method\nFind two numbers\nthat × to ac and + to b
    ➔Factorisable?
    Factorisable?
    ➔"Yes"Write as two brackets\ne.g. (x+2)(x+3)=0
    ➔"No"Use Quadratic Formula\nx = (-b ± √(b²-4ac)) / 2a
    Write as two brackets\ne.g. (x+2)(x+3)=0
    ➔Set each bracket = 0\nSolve for x
    Use Quadratic Formula\nx = (-b ± √(b²-4ac)) / 2a
    ➔Calculate discriminant\nb² - 4ac
    Set each bracket = 0\nSolve for x
    ➔Write both solutions\ne.g. x = -2 or x = -3
    Calculate discriminant\nb² - 4ac
    ➔Discriminant > 0?
    Discriminant > 0?
    ➔"Yes"Two real solutions
    ➔"No"No real solutions
    Two real solutions
    ➔Write both solutions\ne.g. x = -2 or x = -3
    Write both solutions\ne.g. x = -2 or x = -3
    ➔✓ Check by substituting\nback into equation

    Decision flowchart for solving quadratic equations.

    Conceptual Flow Outline

    Two equations with two unknowns
    ➔Are both equations linear?
    Are both equations linear?
    ➔YesIs one equation already solved for x or y?
    ➔No - one is quadraticUse SUBSTITUTION: Substitute linear into quadratic equation
    Is one equation already solved for x or y?
    ➔YesUse SUBSTITUTION: Substitute expression into other equation
    ➔NoUse ELIMINATION: Multiply equations to match coefficients
    Use SUBSTITUTION: Substitute linear into quadratic equation
    ➔Expand and solve resulting quadratic
    Use SUBSTITUTION: Substitute expression into other equation
    ➔Solve for remaining variable
    Use ELIMINATION: Multiply equations to match coefficients
    ➔Add or subtract equations to eliminate one variable
    Add or subtract equations to eliminate one variable
    ➔Solve for remaining variable
    Solve for remaining variable
    ➔Substitute back to find second variable
    Expand and solve resulting quadratic
    ➔Find both pairs of solutions
    Find both pairs of solutions
    ➔Check both values in BOTH equations
    Substitute back to find second variable
    ➔Check both values in BOTH equations

    Method selection for simultaneous equations.

    Worked Examples

    3 worked examples — open one to explore the question and available guidance.

    Practice Questions

    Try the question, then reveal an answer plan or example response

    Q1

    Simplify fully: 3a + 4b - a + 2b

    2 marks
    foundation

    Hint: Group the 'a' terms together and the 'b' terms together. Remember the sign belongs to the term immediately after it.

    Q2

    Expand and simplify: 3(x - 2) + 2(4x + 1)

    3 marks
    standard

    Hint: Expand each bracket separately first, then collect the like terms.

    Q3

    Solve the inequality: 5 - 2x > 13

    2 marks
    standard

    Hint: Treat it like an equation, but remember the special rule if you divide by a negative number.

    Q4

    The n^{th} term of a sequence is 3n - 2. Find the first three terms of the sequence.

    2 marks
    foundation

    Hint: Substitute n=1, then n=2, then n=3 into the formula.

    Q5

    Solve algebraically the simultaneous equations:
    y = x^2 + 3x - 5
    y = 2x + 1

    5 marks
    challenging

    Hint: Since both equations are equal to 'y', you can set them equal to each other to form a single quadratic equation.

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    Exam technique

    How to turn what you know into marks

    How to approach the question

    Always look for the 'equals' sign. If there is no equals sign, you are simplifying or factorising. If there is an equals sign, you are solving to find a value. In word problems, define your variables first (e.g., 'Let x be the cost of an apple').

    How to structure your answer

    For solving equations, work vertically down the page, keeping the equals signs aligned. Show one clear algebraic step per line. Do not try to do multiple steps in your head.

    Timing

    Approximately 1 minute per mark. A 4-mark equation-forming question should take about 4 minutes.

    Common pitfalls

    • Dividing by a negative number in an inequality and forgetting to flip the inequality sign.
    • Expanding -2(x - 4) and writing -2x - 8 instead of -2x + 8. A negative times a negative is positive.
    • Writing x^2 + x^2 = x^4. When adding like terms, the coefficient changes, not the power: x^2 + x^2 = 2x^2.

    What the command words want

    Solve
    Find the numerical value(s) of the letter(s). Your final answer should look like 'x = ...'
    Expand
    Multiply out the brackets.
    Simplify
    Collect like terms together. Do not attempt to find a numerical value for x.
    Factorise
    Put the expression into brackets by finding common factors.
    Show that
    Provide a step-by-step algebraic proof. The final answer is given in the question; the marks are entirely for the method.
    Form an equation
    Translate the words or diagram in the question into algebra with an equals sign.
    Watch or listen (optional)
    Interactive Video Explainer
    AI Generated • 3-4 Mins
    🎙 Podcast Episode
    Algebra
    0:00-0:00

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