AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    PV = nRT γ adiabatic change : pV = constant isothermal change : pV =…

    Full specification wording

    Non-flow processes (A-level only): pV = nRT γ adiabatic change : pV = constant isothermal change : pV = constant at constant pressure W = pΔV Application of first law of thermodynamics to the above processes.

    The ideal gas equation pV = nRT links pressure, volume, amount and temperature.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 2 of 2
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The ideal gas equation pV = nRT links pressure, volume, amount and temperature. For an isothermal change, T is fixed so pV is constant, giving a smooth p–V curve. For an adiabatic change, no heat flows, so pV^γ is constant, where γ = C_p/C_V; the curve is steeper than an isotherm. At constant pressure, work done by the gas is W = pΔV. The first law ΔU = Q − W then explains each path: isothermal has ΔU = 0 so Q = W; adiabatic has Q = 0 so ΔU = −W; constant pressure has both heat and work; constant volume has W = 0 so Q = ΔU.

    What earns the marks

    • Uses pV = nRT to relate state variables and to show that pV is constant when T is constant.
    • States and applies pV^γ = constant for an adiabatic change, identifying γ as the ratio of principal molar heat capacities.
    • Calculates work done at constant pressure using W = pΔV, with consistent units.
    • Applies ΔU = Q − W to each process, setting the appropriate term to zero.
    • Compares isothermal and adiabatic curves on a p–V diagram, noting the adiabatic curve is steeper through the same point.
    • Uses the first law to deduce temperature change from work done when Q = 0.

    Common mistakes and how to put them right

    • Writing pV = constant for an adiabatic change.

      Put it right: Use pV^γ = constant, where γ is greater than 1.

    • Treating W = pΔV as valid for all processes.

      Put it right: It applies only at constant pressure, otherwise use the area under the p–V curve.

    • Forgetting that γ is dimensionless and greater than 1 for gases.

      Put it right: γ = C_p/C_V and is about 1.4 for diatomic gases.

    Exam tips

    • Quote the equation you use and state the condition that makes it valid.
    • Check units of p and V before substituting into W = pΔV.
    • For adiabatic questions, start from Q = 0 and link work done to internal energy change.

    Try the lesson

    The start of the Non-flow processes (A-level only): pV = nRT γ adiabatic change : pV = constant isothermal change : pV = constant at constant pressure W = pΔV Application of first law of thermodynamics to the above processes. lesson, made from checked teaching notes for this specification point.

    Have a go first

    For an ideal gas, which equation of state links pressure p, volume V, amount in moles n and thermodynamic temperature T?

    Listen

    The ideal gas equation pV = nRT links pressure, volume, amount and temperature. For an isothermal change, T is fixed so pV is constant, giving a smooth p–V curve. For an adiabatic change, no heat flows, so pV^γ is constant, where γ = C_p/C_V; the curve is steeper than an isotherm. At constant pressure, work done by the gas is W = pΔV. The first law ΔU = Q − W then explains each path: isothermal has ΔU = 0 so Q = W; adiabatic has Q = 0 so ΔU = −W; constant pressure has both heat and work; constant volume has W = 0 so Q = ΔU. A strong answer earns marks for these points. Uses pV = nRT to relate state variables and to show that pV is constant when T is constant. States and applies pV^γ = constant for an adiabatic change, identifying γ as the ratio of principal molar heat capacities. Calculates work done at constant pressure using W = pΔV, with consistent units. Applies ΔU = Q − W to each process, setting the appropriate term to zero. A common slip: Writing pV = constant for an adiabatic change. Instead, use pV^γ = constant, where γ is greater than 1. Exam tip: Quote the equation you use and state the condition that makes it valid.

    See it

    A top-down flowchart. The top node reads 'First law: ΔU = Q − W' and branches to four process nodes: 'Isothermal change: T constant, pV = constant', 'Adiabatic change: no heat flow, pV^γ = constant', 'Constant pressure: W = pΔV' and 'Constant volume: W = 0'. Each process node leads to a result node: isothermal leads to 'ΔU = 0 so Q = W'; adiabatic leads to 'Q = 0 so ΔU = −W'; constant pressure leads to 'Both heat and work'; constant volume leads to 'Q = ΔU'.
    Shows how the first law ΔU = Q − W is applied to isothermal, adiabatic, constant pressure and constant volume processes.

    Key words

    Say what each word means before you turn the card.

    Ideal gas equation

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    Adiabatic change

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    Isothermal change

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    Work done by a gas

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    See every definition
    Ideal gas equation
    pV = nRT links pressure, volume, amount and temperature.
    Adiabatic change
    No heat flows, so pV^γ is constant, where γ = C_p/C_V; the curve is steeper than an isotherm.
    Isothermal change
    T is fixed so pV is constant, giving a smooth p–V curve.
    Work done by a gas
    At constant pressure, work done by the gas is W = pΔV.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'First law: ΔU = Q − W' and branches to four process nodes: 'Isothermal change: T constant, pV = constant', 'Adiabatic change: no heat flow, pV^γ = constant', 'Constant pressure: W = pΔV' and 'Constant volume: W = 0'. Each process node leads to a result node: isothermal leads to 'ΔU = 0 so Q = W'; adiabatic leads to 'Q = 0 so ΔU = −W'; constant pressure leads to 'Both heat and work'; constant volume leads to 'Q = ΔU'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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    Test your understanding of Non-flow processes (A-level only): pV = nRT γ adiabatic change : pV = constant isothermal change : pV = constant at constant pressure W = pΔV Application of first law of thermodynamics to the above processes.

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