Absolute Zero Revision Notes
Subject: Physics | Level: GCSE | Exam Board: OCR
This guide provides a comprehensive overview of Absolute Zero (OCR GCSE Physics 6.8), focusing on the core concepts of the Kelvin scale, particle kinetic energy, and the pressure-temperature relationship. It is designed to build exam confidence by providing worked examples, examiner insights, and targeted revision materials.
Revision Notes & Key Concepts
Key Terms & Definitions
- Absolute Zero
- The lowest possible temperature, at which particles have their minimum kinetic energy. It is equal to 0 Kelvin or -273 °C.
- Kelvin Scale
- An absolute temperature scale where 0 K is absolute zero. The intervals are the same size as the Celsius scale.
- Kinetic Energy
- The energy an object has due to its motion. For gas particles, this is related to their speed.
- Pressure
- The force exerted per unit area. For a gas, it is caused by the collisions of particles with the walls of the container.
- Directly Proportional
- A relationship between two variables where if one variable is multiplied by a factor, the other is multiplied by the same factor. The graph is a straight line through the origin.
- Extrapolation
- Extending a line or curve on a graph beyond the measured data points to make a prediction.
Worked Examples
Worked Example
Question: A sealed container of gas is at a temperature of 27 °C and a pressure of 1.5 x 10⁵ Pa. The container is heated to a temperature of 177 °C. Calculate the new pressure of the gas. [4 marks]
Solution: Step 1: Convert the temperatures to Kelvin. Examiners will award marks for this crucial first step. T₁ = 27 °C + 273 = 300 K T₂ = 177 °C + 273 = 450 K Step 2: State the Pressure Law formula. P₁/T₁ = P₂/T₂ Step 3: Rearrange the formula to solve for the new pressure, P₂. P₂ = P₁ × (T₂/T₁) Step 4: Substitute the values and calculate the final answer. P₂ = (1.5 x 10⁵ Pa) × (450 K / 300 K) P₂ = 2.25 x 10⁵ Pa Final answer: 2.25 x 10⁵ Pa
Worked Example
Question: Explain, in terms of the motion of particles, why the pressure of a gas in a sealed container increases when its temperature is increased. [3 marks]
Solution: Step 1: Link temperature to particle kinetic energy. Increasing the temperature of the gas increases the average kinetic energy of its particles. Step 2: Describe the change in particle motion. This means the particles move faster and more energetically. Step 3: Link particle motion to pressure. As a result, the particles collide with the walls of the container more frequently and with greater force, which increases the overall pressure.
Worked Example
Question: A student plots a graph of pressure against temperature for a fixed volume of gas. They find the line of best fit has the equation P = 500T + 136500, where P is pressure in Pa and T is temperature in °C. Use this equation to estimate the value of absolute zero in degrees Celsius. [3 marks]
Solution: Step 1: State the condition for absolute zero. Absolute zero is the temperature at which the pressure of the gas would be zero. Step 2: Set the pressure (P) in the equation to zero. 0 = 500T + 136500 Step 3: Rearrange and solve for the temperature (T). -136500 = 500T T = -136500 / 500 T = -273 °C Final answer: -273 °C
Practice Questions
Question: State the value of absolute zero in Kelvin.
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Question: Describe the motion of particles in a substance at absolute zero.
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Question: A bicycle tyre has a pressure of 4.0 x 10⁵ Pa at 15 °C. After a long ride, the temperature of the tyre increases to 45 °C. Calculate the new pressure in the tyre, assuming the volume is constant. [4 marks]
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Question: Explain why the pressure law (P₁/T₁ = P₂/T₂) is only valid when the temperature is measured in Kelvin. [3 marks]
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Question: A graph of pressure against temperature in degrees Celsius for a fixed volume of gas is a straight line that does not pass through the origin. Describe how you could use this graph to find a value for absolute zero. [2 marks]
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