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    Definition and determination of pH (A-level only) — AQA A-Level Chemistry

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    Definition and determination of pH (A-level only) explained

    Hydrogen ion concentrations in aqueous solution span an enormous range.

    Read the full explanation

    Concentrated hydrochloric acid can exceed 10 mol dm⁻³; pure water at 298 K is 1.00 × 10⁻⁷ mol dm⁻³; a concentrated alkali can be below 1 × 10⁻¹⁵ mol dm⁻³. That is sixteen powers of ten, and no linear axis can show it. On a scale where 1 mol dm⁻³ is drawn a metre long, pure water would be a ten-millionth of a metre. The differences matter even between similar solutions: dissolve SO₂ in water and you reach pH 2 to 3, dissolve SO₃ and you reach pH 0 to 1, a hundredfold difference in [H⁺] from two oxides of the same element. Comparing quantities that differ by powers of ten is exactly the job a logarithm does.

    Therefore, a logarithmic scale, the pH scale, is used as a measure of hydrogen ion concentration.

    The pH scale compresses that huge range by taking a logarithm: pH = −log₁₀[H⁺], with the concentration in mol dm⁻³. Because the logarithm is to base 10, one whole pH unit corresponds to a factor of ten in hydrogen ion concentration, and the minus sign makes acidic solutions, which have large [H⁺], have small pH values. Nothing restricts pH to the range 0 to 14: 2 mol dm⁻³ hydrochloric acid has a negative pH and concentrated sodium hydroxide exceeds 14. pH 7 is neutral only at 298 K, because neutrality means [H⁺] = [OH⁻] and the concentration at which that happens depends on Kw, which rises as temperature rises. Since a logarithm is being taken, answers are normally quoted to two decimal places.

    + pH = –log [H ] Students should be able to: convert concentration of hydrogen ions into pH and vice versa calculate the pH of a solution of a strong acid from its concentration.

    For a strong monoprotic acid the dissociation is complete, so every mole of acid delivers a mole of H⁺ and [H⁺] is simply the acid concentration. Then pH = −log₁₀[H⁺]: for 0.0500 mol dm⁻³ hydrochloric acid, pH = −log(0.0500) = 1.30. Working backwards, [H⁺] = 10⁻ᵖᴴ, so a solution of pH 3.40 has [H⁺] = 3.98 × 10⁻⁴ mol dm⁻³. Two traps recur. A diprotic strong acid supplies two protons per molecule, so 0.0200 mol dm⁻³ H₂SO₄ gives [H⁺] = 0.0400 mol dm⁻³ and pH = 1.40. And if the acid has been diluted or mixed, recalculate the concentration from the moles and the new total volume before taking the logarithm.

    Your focus

    1. Compare the hydrogen ion concentrations of solutions at pH 1 and pH 3 as a factor of 100.
    2. Explain why 2.0 mol dm⁻³ hydrochloric acid can have a pH below zero.
    3. Deduce, from measured pH values of 0 to 1 and 2 to 3, which of two aqueous oxides is the stronger acid.
    Show all 9 objectives
    1. Calculate the pH of a solution in which [H⁺] is 2.5 × 10⁻³ mol dm⁻³, giving the answer to two decimal places.
    2. Explain why pure water at 323 K has a pH below 7 and is still neutral.
    3. Deduce the change in [H⁺] when the pH of a solution falls from 4.0 to 2.0.
    4. Calculate the pH of 0.0500 mol dm⁻³ hydrochloric acid as 1.30.
    5. Convert a pH of 3.40 into a hydrogen ion concentration of 3.98 × 10⁻⁴ mol dm⁻³.
    6. Calculate the pH of 0.0200 mol dm⁻³ sulfuric acid, doubling the concentration before taking the logarithm.

    Definition and determination of pH (A-level only) exam tips

    Marking Points
    • one mark for stating that [H⁺] covers many powers of ten, roughly 10 to 10⁻¹⁵ mol dm⁻³
    • one mark for explaining that a linear scale cannot conveniently display such a range
    • one mark for relating a tenfold change in [H⁺] to a change of one pH unit
    • one mark for comparing two solutions using the ratio of their hydrogen ion concentrations
    • one mark for pH = −log₁₀[H⁺] with the concentration in mol dm⁻³
    • one mark for stating that a fall of one pH unit means a tenfold rise in [H⁺]
    • one mark for stating that a neutral solution has pH 7 only at 298 K
    • one mark for quoting the pH to two decimal places
    • one mark for stating that [H⁺] equals the acid concentration for a strong monoprotic acid
    • one mark for substituting correctly into pH = −log₁₀[H⁺]
    • one mark for the pH quoted to two decimal places
    • one mark for using [H⁺] = 10⁻ᵖᴴ when converting a pH back to a concentration
    • one mark for doubling the concentration when the strong acid is diprotic
    Examiner Tips
    • 💡Whenever a question compares acidity, convert everything to [H⁺] or everything to pH before you compare.
    • 💡A difference of n pH units is a factor of 10ⁿ in hydrogen ion concentration.
    • 💡Sanity-check every answer: an acid should give a small pH and an alkali a large one.
    • 💡Give pH to two decimal places unless the question says otherwise; whole numbers lose marks.
    • 💡Write [H⁺] on its own line before you touch the log button; most lost marks happen before the calculator, not on it.
    • 💡For 'concentration from pH', use the 10ˣ key with a negative exponent and keep three significant figures.
    Common Mistakes
    • saying a solution at pH 1 is twice as acidic as one at pH 2 rather than ten times
    • believing pH cannot fall below 0 or rise above 14
    • comparing a concentration in mol dm⁻³ with a pH value without converting one to the other
    • assuming a strong acid and a weak acid of equal concentration have the same [H⁺]
    • using ln rather than log₁₀ on the calculator
    • omitting the minus sign, so the pH of an acid comes out negative
    • calling any solution of pH 7 neutral regardless of temperature
    • rounding pH to a whole number, when 0.1 of a pH unit is already a 26% change in [H⁺]
    • using a number of moles rather than a concentration in mol dm⁻³ inside the logarithm
    • forgetting that 0.100 mol dm⁻³ H₂SO₄ provides 0.200 mol dm⁻³ H⁺
    • giving the pH to a whole number when two decimal places are expected
    • using Ka for a strong acid, which is unnecessary because dissociation is complete
    • failing to recalculate the concentration after dilution before taking the logarithm