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    Ozone depletion — AQA A-Level Chemistry

    Test yourself on Ozone depletion with AQA A-Level practice questions.

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    Ozone depletion explained

    Ozone, O₃, forms naturally high in the atmosphere: ultraviolet light splits O₂ into oxygen atoms, and each atom joins another O₂ molecule to give O₃.

    Read the full explanation

    The useful part is what happens next. Ozone absorbs ultraviolet radiation, the energy breaking it back to O₂ and an oxygen atom, which then reforms ozone. The cycle absorbs high-energy ultraviolet continuously without consuming the ozone, which is why a thin layer of gas can shield the whole surface. The radiation it removes is the band that damages DNA, so a thinner layer means more skin cancer, more cataracts and damage to crops and plankton. Note the type of radiation carefully: ozone in the stratosphere is filtering ultraviolet, not infrared, so it is not acting against global warming.

    Chlorine atoms are formed in the upper atmosphere when ultraviolet radiation causes C–Cl bonds in chlorofluorocarbons (CFCs) to break.

    Chlorofluoroalkanes were chosen as refrigerants and solvents because they are unreactive, non-flammable and non-toxic. That stability is exactly the problem: nothing destroys them at ground level, so over years they drift up into the stratosphere. There the ultraviolet radiation is energetic enough to break a bond homolytically, one electron going to each atom. It is the C–Cl bond that breaks, not C–F, because C–Cl has the lower bond enthalpy; if a question supplies the two values, quote both, but it is the comparison that carries the mark. For dichlorodifluoromethane the step is CCl₂F₂ → •CClF₂ + Cl•. The species released is a chlorine atom with an unpaired electron, written Cl•, not a chloride ion; the whole catalytic cycle that follows depends on that.

    Chlorine atoms catalyse the decomposition of ozone and contribute to the hole in the ozone layer.

    A single chlorine radical destroys ozone over and over. The two steps are Cl• + O₃ → ClO• + O₂ and ClO• + O₃ → 2O₂ + Cl•. Add them and the radicals cancel, leaving 2O₃ → 3O₂. The chlorine radical is regenerated in the second step, so it is a catalyst, not a reactant, and one atom can remove of the order of 10⁵ ozone molecules before it is finally removed from the cycle. ClO• is the intermediate: it is made and used up inside the cycle, so it appears in neither the overall equation nor the catalyst role. Because catalyst and reactants are all gases in the same phase, this is homogeneous catalysis; AQA has set ozone decomposition as the odd one out in a list of heterogeneous processes.

    Appreciate that results of research by different groups in the scientific community provided evidence for legislation to ban the use of CFCs as solvents and refrigerants.

    This statement is about how science becomes policy, so the credit is for the process, not the chemistry. A laboratory prediction in the 1970s that chlorine radicals could catalyse ozone loss was only a hypothesis. It gained weight when independent teams measured the effect in the real atmosphere: ground-based measurements over Antarctica showed a seasonal collapse in ozone, satellite data confirmed the same hole, and laboratory work reproduced the radical chemistry. Because separate groups using different methods agreed, and the work was published and peer reviewed, governments treated the conclusion as reliable and signed an international agreement restricting chlorofluorocarbons as refrigerants and solvents. Replication by independent groups, not the authority of any one scientist, is what turned evidence into legislation.

    Chemists have now developed alternative chlorine-free compounds.

    The replacements work by removing the source of the problem: with no carbon–chlorine bond, ultraviolet light cannot release a chlorine radical, so no catalytic cycle can start. Hydrofluorocarbons such as CH₂FCF₃ keep the useful properties of the old refrigerants, low boiling point, low flammability and low toxicity. While they contain C–F, C–H, and C–C bonds, they crucially lack C–Cl bonds; the C–F bonds are too strong to break in the stratosphere. Simple alkanes such as pentane are used in domestic fridges for the same reason, since they contain no C–Cl bonds at all. Neither answer is perfect: hydrofluorocarbons are potent greenhouse gases and hydrocarbons are flammable, so the choice trades one environmental or safety cost against another.

    Students should be able to: use equations, such as the following, to explain how chlorine atoms catalyse decomposition of ozone:

    Here you must work with the equations themselves. Write the two steps, Cl• + O₃ → ClO• + O₂ and ClO• + O₃ → 2O₂ + Cl•, then add them. Cl• appears on the left of the first and the right of the second, and ClO• appears on the right of the first and the left of the second, so both cancel, leaving 2O₃ → 3O₂. That cancellation is the proof of catalysis: the chlorine radical is consumed and then regenerated, so it does not appear in the overall equation and a tiny amount keeps working. The species that is made and then used up inside the cycle, ClO•, is the intermediate. The same pattern is used for other radicals, such as nitrogen monoxide, so recognise the shape of the argument rather than memorising one pair of equations.

    Your focus

    1. Name a specific consequence of a thinner ozone layer, such as skin cancer, cataracts or damage to crops, and link it to the radiation the layer would otherwise absorb.
    2. Write equations showing ozone being formed from, and broken back to, oxygen in the upper atmosphere.
    3. Distinguish the consequences of ozone depletion from the consequences of the enhanced greenhouse effect.
    Show all 18 objectives
    1. Write an equation for the ultraviolet fission of a named chlorofluorocarbon, showing the radicals produced.
    2. Justify, using bond enthalpy data, why the carbon–chlorine bond breaks rather than the carbon–fluorine bond.
    3. Explain why a compound chosen for being unreactive ends up causing damage in the stratosphere.
    4. Write the two propagation steps of the chlorine-catalysed decomposition of ozone and combine them into the overall equation.
    5. Distinguish the catalyst from the intermediate in the cycle and justify each label.
    6. Explain why a very small concentration of chlorine radicals destroys a large amount of ozone.
    7. Explain why agreement between independent research groups carries more weight than a single result.
    8. Describe the kinds of evidence that supported restricting chlorofluorocarbons, naming at least one measurement.
    9. Discuss the role of peer review and publication in turning a chemical hypothesis into international regulation.
    10. Explain why a replacement refrigerant containing no C–Cl bond cannot deplete ozone.
    11. Name one chlorine-free refrigerant and state the property that makes it a workable substitute.
    12. Evaluate a proposed replacement by weighing its ozone safety against flammability or greenhouse effects.
    13. Combine two propagation equations into a correct overall equation by cancelling species that appear on both sides.
    14. Deduce from a pair of equations which species is the catalyst and which is the intermediate.
    15. Apply the same reasoning to an unfamiliar radical catalyst such as nitrogen monoxide acting on ozone.

    Ozone depletion exam tips

    Marking Points
    • one mark for stating that ozone absorbs ultraviolet radiation
    • one mark for placing this ozone in the upper atmosphere or stratosphere
    • one mark for an equation showing ozone forming or absorbing ultraviolet, such as O• + O₂ → O₃
    • one mark for a named consequence of more ultraviolet reaching the surface, such as skin cancer or cataracts
    • one mark for homolytic fission of the C–Cl bond caused by ultraviolet radiation
    • one mark for showing the product as a chlorine radical, Cl•, with the dot
    • one mark for stating that C–Cl breaks in preference to C–F because it has the lower bond enthalpy
    • one mark for explaining that the compound is unreactive enough to survive until it reaches the upper atmosphere
    • one mark for the first step, Cl• + O₃ → ClO• + O₂
    • one mark for the second step, ClO• + O₃ → 2O₂ + Cl•
    • one mark for the overall equation 2O₃ → 3O₂ with the radicals cancelled
    • one mark for stating that Cl• is regenerated and so acts as a catalyst
    • one mark for describing this as homogeneous catalysis, all species being gases
    • one mark for saying the evidence came from more than one independent research group
    • one mark for naming a check such as peer review, publication or reproducing the result
    • one mark for naming the kind of evidence, such as measurements of falling ozone concentration over Antarctica
    • one mark for linking the accepted evidence to legislation banning chlorofluorocarbons as solvents and refrigerants
    • one mark for naming a chlorine-free alternative, such as pentane or a hydrofluorocarbon
    • one mark for stating it contains no C–Cl bond, so no chlorine radicals are formed
    • one mark for stating a property that lets it replace the original compound, such as a suitable boiling point
    • one mark for a drawback, such as flammability of alkanes or the greenhouse effect of hydrofluorocarbons
    • one mark for writing both propagation steps with radical dots shown
    • one mark for cancelling Cl• and ClO• because each appears on both sides of the added equations
    • one mark for the overall equation 2O₃ → 3O₂ correctly balanced
    • one mark for identifying Cl• as the catalyst because it is regenerated, and ClO• as the intermediate
    Examiner Tips
    • 💡Use the word ultraviolet in every answer about the ozone layer; a general word for radiation will not score.
    • 💡Keep ozone depletion and the greenhouse effect in separate mental boxes; examiners set them as distractors for each other.
    • 💡State where the ozone is, since the same molecule is harmful at ground level.
    • 💡Where the question supplies the two bond enthalpies, quote both to justify which bond breaks; it is the comparison that earns the mark.
    • 💡Write every radical with its dot, including in the equation for the fission step.
    • 💡Link the stability of the compound to the fact that it reaches the stratosphere at all.
    • 💡Add the two steps on paper and strike out species appearing on both sides; what survives is the overall equation.
    • 💡Say explicitly that the chlorine radical is regenerated; "it is a catalyst" alone often does not score the reason.
    • 💡Check the dots are on both Cl and ClO in every equation you write.
    • 💡Use the words independent, reproduced and peer reviewed; these are the terms the mark scheme looks for.
    • 💡Give one concrete example of evidence rather than a general claim that scientists did research.
    • 💡Finish by naming the outcome, the international restriction on chlorofluorocarbon use.
    • 💡Anchor the answer on the missing C–Cl bond; that single phrase carries the explanation mark.
    • 💡Have one named example ready, pentane or a hydrofluorocarbon, rather than a vague "modern compound".
    • 💡If the question says "evaluate" or "discuss", you must give a disadvantage as well as the advantage.
    • 💡Set the two equations out one above the other before adding; the cancellation is then obvious.
    • 💡State in words that the radical is regenerated, as well as showing it in the equations.
    • 💡If given a different radical such as NO, apply the same two-step pattern rather than recalling chlorine.
    Common Mistakes
    • saying ozone prevents global warming, an answer AQA offers as a wrong option in multiple choice
    • saying ozone absorbs infrared radiation, which is what greenhouse gases do
    • writing that ozone "absorbs radiation" without naming ultraviolet
    • confusing low-level ozone, which is a pollutant, with stratospheric ozone, which is beneficial
    • breaking the C–F bond, which is stronger and therefore not the one that breaks
    • writing Cl⁻ instead of Cl•, which turns a radical mechanism into an ionic one
    • describing the fission as heterolytic, giving a pair of ions
    • saying the chlorofluorocarbon molecule itself destroys ozone, rather than the radical released from it
    • writing Cl⁻ and ClO⁻ in place of the radicals Cl• and ClO•
    • leaving Cl• in the overall equation, which would make it a reactant rather than a catalyst
    • calling ClO• the catalyst and Cl• the intermediate, which reverses the two roles
    • describing the decomposition of ozone by chlorine radicals as heterogeneous catalysis
    • answering with the ozone depletion mechanism when the question asks how the evidence came to be accepted
    • claiming one scientist's result was enough to change the law
    • saying chlorofluorocarbons were banned because they are toxic or flammable, when they are neither
    • describing the ban as based on theory alone, ignoring the atmospheric measurements
    • saying the replacement is safe because it contains fluorine, when the point is the absence of chlorine
    • naming a hydrochlorofluorocarbon as chlorine-free when it still contains C–Cl bonds
    • presenting the alternatives as having no environmental cost at all
    • explaining the benefit in terms of the compound being less toxic rather than releasing no chlorine radicals
    • cancelling ozone rather than the radicals when adding the two steps
    • leaving a chlorine species in the overall equation
    • balancing the overall equation with oxygen atoms instead of O₂ molecules
    • omitting the radical dots so the equations describe ions