Reactions of ions in aqueous solution (A-level only) Revision Guide
Topic Overview
This topic explores the behaviour of metal ions in aqueous solution, focusing on their reactions with water, hydroxide ions, and ammonia. You'll learn why different ions produce acidic, neutral, or alkaline solutions, and how complex ion formation leads to characteristic colour changes and precipitate dissolution. Understanding these reactions is essential for explaining observations in qualitative analysis and for predicting the outcomes of reactions in solution.
The key ideas revolve around the hydration of metal ions, the Brønsted-Lowry acidity of aqua ions, and the stepwise substitution of water ligands by other ligands such as hydroxide and ammonia. You'll encounter the familiar hexaaqua ions of transition metals and Group 2 metals, and see how their reactions differ based on charge density and electronic configuration. This knowledge directly links to topics like transition metal chemistry, acid-base equilibria, and complex ion stability.
Mastering this topic will enable you to write balanced equations for hydrolysis, precipitation, and ligand substitution reactions, and to explain colour changes in terms of ligand field theory. It's a high-yield area for A-level exams, often appearing in multiple-choice, structured, and extended-response questions. A solid grasp here also builds foundations for further study in inorganic chemistry and analytical techniques.
Key Concepts
Core ideas you must understand for this topic
- →Hydrated metal ions act as Brønsted-Lowry acids: [M(H₂O)₆]ⁿ⁺ can donate a proton to water, forming [M(H₂O)₅(OH)]⁽ⁿ⁻¹⁾⁺ and H₃O⁺. The acidity increases with charge density (higher charge, smaller radius).
- →Addition of hydroxide ions (e.g., NaOH) causes stepwise deprotonation, leading to precipitation of metal hydroxides. For example, [Cu(H₂O)₆]²⁺ + 2OH⁻ → Cu(OH)₂(H₂O)₄ (blue precipitate) + 2H₂O.
- →Some metal hydroxides are amphoteric: they dissolve in excess NaOH to form soluble hydroxo complexes. Al³⁺ and Zn²⁺ are classic examples: Al(OH)₃(s) + OH⁻ → [Al(OH)₄]⁻ (colourless).
- →Ammonia can act as a base (deprotonation) or as a ligand (substitution). With Cu²⁺, limited NH₃ gives Cu(OH)₂ precipitate, but excess NH₃ forms the deep blue [Cu(NH₃)₄(H₂O)₂]²⁺ complex.
- →Ligand substitution reactions often involve a colour change and a change in coordination number. For example, [Co(H₂O)₆]²⁺ (pink) reacts with concentrated HCl to form [CoCl₄]²⁻ (blue), with water replaced by chloride ligands.
What You Need to Demonstrate
Key skills and knowledge for this topic
- Formation of [M(H2O)6]2+ ions for Fe and Cu
- Formation of [M(H2O)6]3+ ions for Al and Fe
- Explanation of why [M(H2O)6]3+ is more acidic than [M(H2O)6]2+ based on charge/size ratio
- Description of amphoteric character of Al3+ hydroxide
- Observations for reactions of M2+ and M3+ ions with bases (OH-, NH3, CO32-)
Marking Points
Key points examiners look for in your answers
- Formation of [M(H2O)6]2+ ions for Fe and Cu
- Formation of [M(H2O)6]3+ ions for Al and Fe
- Explanation of why [M(H2O)6]3+ is more acidic than [M(H2O)6]2+ based on charge/size ratio
- Description of amphoteric character of Al3+ hydroxide
- Observations for reactions of M2+ and M3+ ions with bases (OH-, NH3, CO32-)
Examiner Tips
Expert advice for maximising your marks
- 💡Ensure you can write balanced equations for the reactions of metal-aqua ions with bases
- 💡Focus on the charge/size ratio when explaining acidity differences
- 💡Be prepared to describe specific colour changes and precipitate formations for Fe2+, Fe3+, Cu2+, and Al3+
- 💡When writing equations for hydrolysis, always show the equilibrium arrow and include the state symbols. For example: [Fe(H₂O)₆]³⁺(aq) + H₂O(l) ⇌ [Fe(H₂O)₅(OH)]²⁺(aq) + H₃O⁺(aq). This demonstrates you understand it's a reversible reaction.
- 💡For precipitation reactions, use the correct formula of the precipitate. Many students write Cu(OH)₂, but the actual formula is often Cu(OH)₂(H₂O)₄. However, in exam answers, Cu(OH)₂ is usually accepted. Check the mark scheme for your exam board.
- 💡When explaining colour changes, link them to changes in ligand and/or oxidation state. For example, the change from pink [Co(H₂O)₆]²⁺ to blue [CoCl₄]²⁻ is due to a change from octahedral to tetrahedral geometry, which affects the d-orbital splitting and thus the colour absorbed.
Common Mistakes
Pitfalls to avoid in your exam answers
- Confusing the acidity of M2+ and M3+ ions
- Failing to correctly identify the amphoteric nature of aluminium hydroxide
- Incorrectly describing the observations for reactions with limited vs excess base
- Students often think that adding NaOH always gives the hydroxide precipitate, but for amphoteric hydroxides like Al(OH)₃, excess NaOH redissolves the precipitate. Remember: Al³⁺ and Zn²⁺ form soluble hydroxo complexes in excess base.
- Another mistake is assuming that ammonia always acts as a ligand. In limited amounts, ammonia first acts as a base, deprotonating the aqua ion to give the hydroxide precipitate. Only with excess ammonia does ligand substitution occur.
- Many students confuse the colour of hexaaqua ions with the colour of their complexes. For example, [Cu(H₂O)₆]²⁺ is blue, but [Cu(NH₃)₄(H₂O)₂]²⁺ is a deeper blue. Always specify the complex when describing colour.
Frequently Asked Questions
Common questions students ask about this topic