Concentration of solutions — AQA GCSE Combined Science
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Concentration of solutions explained
Concentration tells you how much solute is dissolved in each unit volume of solution, commonly expressed in g/dm³.
Read the full explanation
To find the mass of solute, rearrange the relationship concentration = mass ÷ volume so that mass = concentration × volume. For example, a 250 cm³ solution of concentration 40 g/dm³ contains 40 × 0.250 = 10 g of solute. The crucial step is unit conversion: 1 dm³ = 1000 cm³, so divide a volume in cm³ by 1000 before multiplying. Check the answer by reasoning: a larger volume at the same concentration must contain proportionally more solute, and a more concentrated solution in the same volume must contain more solute. Always attach the correct unit, usually grams, and consider whether the value is sensible for the solute involved.
Your focus
- Select and rearrange the concentration relationship to make mass the subject.
- Convert volumes between cm³ and dm³ correctly before calculation.
- Calculate the mass of solute in a solution of known concentration and volume, giving the answer with an appropriate unit.
Concentration of solutions exam tips
Quick Revision Summary (Key Takeaway)
Concentration of a solution measures the mass of solute dissolved in a given volume of solvent, most commonly calculated using the equation concentration = mass / volume in g/dm3. Mastering this topic requires converting volumes from cm3 to dm3 by dividing by 1000 and understanding how altering solute mass or solvent volume affects concentration.
Topic Overview
Concentration of solutions is a fundamental quantitative chemistry topic in AQA GCSE Combined Science. It describes the amount of a chemical substance (solute) dissolved in a defined volume of liquid (solvent), quantified in grams per cubic decimetre (g/dm3).
Understanding concentration enables students to analyze chemical formulations, interpret titration and neutralisation experiments, and link quantitative calculations to real-world industrial and biological processes. It bridges basic laboratory measurement skills with mathematical chemical analysis.
Key Concepts
- →Concentration formula: concentration (g/dm3) = mass of solute (g) / volume of solution (dm3).
- →Unit conversion: 1 dm3 = 1000 cm3 = 1 litre; always divide cm3 by 1000 to convert to dm3.
- →Proportionality: Concentration increases if more solute is added to the same volume, or if solvent volume decreases by evaporation while solute mass remains constant.
- →Rearranging equations: Mass (g) = concentration (g/dm3) x volume (dm3), and volume (dm3) = mass (g) / concentration (g/dm3).
Marking Points
- State the relationship concentration = mass of solute ÷ volume of solution and rearrange it correctly to mass = concentration × volume.
- Convert a volume given in cm³ into dm³ by dividing by 1000 before substituting, since concentration is normally quoted in g/dm³.
- Substitute the known concentration and converted volume into mass = concentration × volume and evaluate accurately.
- Give the final mass with the correct unit, typically g, and check that the magnitude is reasonable for the volume and concentration involved.
- Interpret the result in context, for example stating the mass of solute present in the stated volume of that particular solution.
Examiner Tips
- 💡Write down the equation mass = concentration × volume before substituting any numbers, so the examiner can follow your method.
- 💡Convert every volume to dm³ in a clearly shown step, since unit errors are the most common source of lost marks in this topic.
- 💡Estimate the answer first, for example 40 g/dm³ × 0.25 dm³ is about 10 g, then compare your calculated value with the estimate to catch slips.
- 💡Write out the rearranged formula before substituting numbers to secure method marks even if a calculator entry error occurs.
- 💡Check your units at the end of the calculation; ensure you have written g/dm3 and not g/cm3 unless specifically instructed.
- 💡Remember that 1 cm3 is equivalent to 1 ml and 1 dm3 is equivalent to 1 litre, which helps in contextual questions.
Common Mistakes
- Multiplying concentration by a volume left in cm³ instead of converting to dm³; correct this by dividing cm³ by 1000 first, so 500 cm³ becomes 0.500 dm³.
- Using mass = volume ÷ concentration instead of mass = concentration × volume; correct this by rearranging concentration = mass ÷ volume carefully before substituting.
- Forgetting the unit on the answer or writing an impossible unit such as g/dm³ for a mass; correct this by checking that the unit matches the quantity calculated, which is grams here.
- Thinking 1 dm3 equals 100 cm3 instead of 1000 cm3, which causes answers to be incorrect by an order of magnitude.
- Believing adding more water makes a solution stronger, confusing total volume with concentration.
- Multiplying cm3 by 1000 instead of dividing when attempting to convert volume to dm3.
Revision Plan
- 1Day 1-2: Memorise the core formula triangle relating mass, volume, and concentration, and practice converting cm3 to dm3.
- 2Day 3-4: Work through direct calculation questions finding concentration when mass and volume are provided.
- 3Day 5-6: Practice rearranging the formula to solve for unknown mass and unknown volume under timed conditions.
- 4Day 7: Tackle multi-step past paper exam questions involving solution dilution, evaporation, and comparison of concentrations.
Exam Question Types
- 📋Direct calculations: Standard 2-mark or 3-mark questions asking you to calculate concentration in g/dm3 given mass in grams and volume in cm3.
- 📋Rearranged calculations: Questions asking for the mass of solute present in a specific volume of a known concentration.
- 📋Comparative explanation questions: Describing and explaining how adding water or evaporating solvent alters the concentration of a given mixture.
Command Word Expectations (AQA)
Use the numbers provided in the question stem to work out an answer, clearly writing down each mathematical step and unit.
Give reasons why a change in mass or volume causes a specific change in concentration using scientific cause-and-effect reasoning.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: A student dissolves 8.5 g of copper sulfate in water to make 200 cm3 of solution. Calculate the concentration of the solution in g/dm3.
- 1.Step 1: Identify given quantities: Mass of solute = 8.5 g; Volume of solution = 200 cm3.
- 2.Step 2: Convert volume from cm3 to dm3: 200 / 1000 = 0.2 dm3.
- 3.Step 3: State the formula: Concentration (g/dm3) = mass (g) / volume (dm3).
- 4.Step 4: Substitute values into the equation: Concentration = 8.5 / 0.2 = 42.5.
- 5.Step 5: State the final numerical answer with units: 42.5 g/dm3.
Question: A solution of sodium chloride has a concentration of 35 g/dm3. Calculate the mass of sodium chloride dissolved in 150 cm3 of this solution.
- 1.Step 1: Identify given quantities: Concentration = 35 g/dm3; Volume = 150 cm3.
- 2.Step 2: Convert volume to dm3: 150 / 1000 = 0.15 dm3.
- 3.Step 3: Rearrange the concentration equation to make mass the subject: Mass (g) = concentration (g/dm3) x volume (dm3).
- 4.Step 4: Substitute known values: Mass = 35 x 0.15 = 5.25 g.
- 5.Step 5: Write the final answer clearly.