Chapter C6: Making useful chemicals — OCR GCSE Combined Science
Test yourself on Chapter C6: Making useful chemicals with OCR GCSE practice questions.
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Chapter C6: Making useful chemicals explained
Chapter C6 focuses on the production of useful chemicals, specifically covering the synthesis of salts from acid reactions and the management of reaction rates.
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It explores how chemists control conditions in both laboratory and industrial settings to optimize yields and efficiency, including the use of catalysts and reversible reactions.
What to demonstrate
- Correct identification of products from acid reactions with metals, hydroxides, and carbonates.
- Accurate description of laboratory procedures for salt preparation (filtration, evaporation, crystallisation, drying).
- Correct use of pH scale and understanding of H+ ion concentration.
Show all 7 objectives
- Explanation of factors affecting reaction rates (temperature, concentration, pressure, surface area) using collision theory.
- Description of catalytic action in terms of activation energy.
- Understanding of dynamic equilibrium in reversible reactions.
- Prediction of equilibrium shifts based on changes in conditions.
Chapter C6: Making useful chemicals exam tips
Quick Revision Summary (Key Takeaway)
Chapter C6: Making useful chemicals covers the production of key industrial chemicals, including the Haber process for ammonia, the Contact process for sulfuric acid, and the electrolysis of brine. It explains the conditions, catalysts, and yields involved, alongside the importance of these chemicals in fertilisers and everyday products.
Topic Overview
Chapter C6, 'Making useful chemicals', is a cornerstone of industrial chemistry in the OCR GCSE Combined Science course. It focuses on how raw materials are transformed into valuable products on a large scale, with an emphasis on the principles of chemical equilibrium, rates of reaction, and energy changes. You will study two major industrial processes: the Haber process for making ammonia (used in fertilisers) and the Contact process for making sulfuric acid (used in many industries). Additionally, you will explore the electrolysis of brine (sodium chloride solution) to produce chlorine, hydrogen, and sodium hydroxide.
Understanding these processes is not just about memorising conditions; it's about applying the concepts of reversible reactions and Le Chatelier's principle. For example, you need to explain why certain temperatures and pressures are chosen to maximise yield while keeping costs manageable. This topic also links to environmental concerns, such as the energy demands of these processes and the importance of sustainability. Mastering this chapter will help you appreciate how chemistry contributes to everyday life, from food production to cleaning products.
In exams, you will be expected to recall specific details, interpret graphs of yield against conditions, and evaluate the economic and environmental trade-offs. The content builds on earlier topics like atomic structure, bonding, and rates of reaction, so a solid grasp of those will be beneficial. By the end of this chapter, you should be able to describe the raw materials, stages, and conditions for each process, and explain the underlying chemistry with confidence.
Key Concepts
- →Reversible reactions and dynamic equilibrium: In a closed system, forward and reverse reactions occur at the same rate, and the concentrations of reactants and products remain constant.
- →Le Chatelier's principle: If a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the equilibrium shifts to counteract the change.
- →The Haber process: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) ΔH = -92 kJ/mol. Conditions: 450°C, 200 atm, iron catalyst. Ammonia is used to make fertilisers.
- →The Contact process: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = -196 kJ/mol. Conditions: 450°C, 2 atm, vanadium(V) oxide catalyst. Sulfuric acid is used in many industries.
- →Electrolysis of brine: 2NaCl(aq) + 2H₂O(l) → 2NaOH(aq) + H₂(g) + Cl₂(g). Products: chlorine at anode, hydrogen at cathode, sodium hydroxide remains in solution.
Marking Points
- Correct identification of products from acid reactions with metals, hydroxides, and carbonates.
- Accurate description of laboratory procedures for salt preparation (filtration, evaporation, crystallisation, drying).
- Correct use of pH scale and understanding of H+ ion concentration.
- Explanation of factors affecting reaction rates (temperature, concentration, pressure, surface area) using collision theory.
- Description of catalytic action in terms of activation energy.
- Understanding of dynamic equilibrium in reversible reactions.
- Prediction of equilibrium shifts based on changes in conditions.
Examiner Tips
- 💡When asked about rate of reaction, always refer to collision frequency and energy.
- 💡Ensure balanced symbol equations include state symbols where required.
- 💡Use the term 'dynamic equilibrium' when discussing reversible reactions in closed systems.
- 💡Practice calculating pH changes based on H+ concentration shifts.
- 💡Clearly distinguish between the effect of conditions on rate versus the effect on equilibrium position.
- 💡Always quote exact conditions (temperature, pressure, catalyst) for each industrial process. Marks are often awarded for specific values, not just 'high temperature'.
- 💡When explaining why a particular condition is used, always link to both rate and yield, and mention the compromise between them. For example, 'A higher temperature would increase rate but decrease yield because the reaction is exothermic, so 450°C is a compromise.'
- 💡For electrolysis questions, write half-equations and state which electrode each product forms. Use the mnemonic 'An Ox, Red Cat' to remember oxidation at anode, reduction at cathode.
Common Mistakes
- Confusing 'strong' and 'weak' acids (degree of ionisation) with 'concentrated' and 'dilute' (amount of substance).
- Incorrectly describing the effect of catalysts as changing the yield rather than just the rate.
- Failing to mention that dynamic equilibrium only occurs in closed systems.
- Misinterpreting the relationship between H+ ion concentration and pH (factor of 10 per pH unit).
- Incomplete descriptions of collision theory (e.g., omitting 'frequency' or 'energy' of collisions).
- Misconception: Increasing pressure always increases the yield of a reaction. Correction: Only if the forward reaction produces fewer gas molecules. In the Haber process, high pressure favours ammonia, but in reactions with equal gas moles, pressure has no effect.
- Misconception: A catalyst increases the yield of a reaction. Correction: A catalyst speeds up the rate of both forward and reverse reactions equally, so it does not change the position of equilibrium or the yield, but helps reach equilibrium faster.
- Misconception: The Haber process and Contact process use the same conditions. Correction: They are different reactions with different optimised conditions. Haber: 450°C, 200 atm, iron; Contact: 450°C, 2 atm, vanadium(V) oxide.
Revision Plan
- 1Week 1, Day 1-2: Review reversible reactions and dynamic equilibrium. Write down definitions and draw a simple diagram of a closed system.
- 2Week 1, Day 3-4: Study the Haber process in detail. Create a fact file with raw materials, stages, conditions, and uses of ammonia. Practice explaining why each condition is used.
- 3Week 1, Day 5-6: Study the Contact process similarly. Compare and contrast with the Haber process.
- 4Week 2, Day 1-2: Learn electrolysis of brine. Draw a labelled diagram of the cell and write half-equations. Practice predicting products.
- 5Week 2, Day 3-4: Work through past exam questions on these processes. Focus on 6-mark questions that ask you to evaluate conditions.
- 6Week 2, Day 5-6: Use active recall to test yourself on key facts. Create mind maps linking the processes to real-world applications.
Exam Question Types
- 📋Multiple-choice questions: Often ask for the correct catalyst or conditions. Tip: Memorise the exact values and catalysts.
- 📋Short-answer questions: 'State the raw materials for the Haber process.' Tip: Be precise – nitrogen from air, hydrogen from natural gas (methane).
- 📋Data analysis: You may be given a graph of yield vs temperature/pressure and asked to interpret it. Tip: Describe the trend and explain using Le Chatelier's principle.
- 📋6-mark extended response: 'Evaluate the use of high pressure in the Haber process.' Tip: Structure your answer with points for and against, and conclude with a justified decision.
Command Word Expectations (OCR)
Give a brief, factual answer without explanation. For example, 'State the catalyst used in the Haber process.' Answer: 'Iron.'
Give reasons or causes. For example, 'Explain why a high pressure is used in the Haber process.' You must link the pressure to the equilibrium position and rate, using Le Chatelier's principle.
Weigh up the pros and cons, then make a judgement. For example, 'Evaluate the conditions used in the Contact process.' You should discuss rate, yield, cost, and safety, and conclude with a justified choice.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: In the Haber process, 100 tonnes of nitrogen are reacted with excess hydrogen. If the percentage yield of ammonia is 30%, what mass of ammonia is produced? (Relative atomic masses: N=14, H=1)
- 1.Step 1: Write the balanced equation: N₂ + 3H₂ ⇌ 2NH₃
- 2.Step 2: Calculate moles of nitrogen: moles = mass / Mr = 100,000,000 g / 28 g/mol = 3,571,428.6 mol
- 3.Step 3: Use molar ratio: 1 mol N₂ produces 2 mol NH₃, so theoretical moles of NH₃ = 2 × 3,571,428.6 = 7,142,857.2 mol
- 4.Step 4: Calculate theoretical mass of NH₃: mass = moles × Mr = 7,142,857.2 × 17 = 121,428,572 g = 121.4 tonnes
- 5.Step 5: Apply percentage yield: actual mass = (30/100) × 121.4 = 36.4 tonnes
Question: In the Contact process, sulfur dioxide is converted to sulfur trioxide. The reaction is: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = -196 kJ/mol. Explain why a temperature of 450°C and a pressure of 2 atmospheres are used, despite the forward reaction being exothermic and producing fewer gas molecules.
- 1.Step 1: Identify the trade-off: lower temperature would increase yield (exothermic), but too low makes rate too slow.
- 2.Step 2: Identify pressure: higher pressure would increase yield (fewer gas molecules), but high pressure is expensive and dangerous.
- 3.Step 3: State the compromise: 450°C gives a reasonable rate with a yield of about 98%, and 2 atm is a compromise between yield and cost.
- 4.Step 4: Mention catalyst: vanadium(V) oxide is used to speed up the reaction without affecting position of equilibrium.