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    Chapter C6: Making useful chemicals — OCR GCSE Combined Science

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    Chapter C6: Making useful chemicals explained

    Chapter C6 focuses on the production of useful chemicals, specifically covering the synthesis of salts from acid reactions and the management of reaction rates.

    Read the full explanation

    It explores how chemists control conditions in both laboratory and industrial settings to optimize yields and efficiency, including the use of catalysts and reversible reactions.

    What to demonstrate

    1. Correct identification of products from acid reactions with metals, hydroxides, and carbonates.
    2. Accurate description of laboratory procedures for salt preparation (filtration, evaporation, crystallisation, drying).
    3. Correct use of pH scale and understanding of H+ ion concentration.
    Show all 7 objectives
    1. Explanation of factors affecting reaction rates (temperature, concentration, pressure, surface area) using collision theory.
    2. Description of catalytic action in terms of activation energy.
    3. Understanding of dynamic equilibrium in reversible reactions.
    4. Prediction of equilibrium shifts based on changes in conditions.

    Chapter C6: Making useful chemicals exam tips

    Quick Revision Summary (Key Takeaway)

    Chapter C6: Making useful chemicals covers the production of key industrial chemicals, including the Haber process for ammonia, the Contact process for sulfuric acid, and the electrolysis of brine. It explains the conditions, catalysts, and yields involved, alongside the importance of these chemicals in fertilisers and everyday products.

    Topic Overview

    Chapter C6, 'Making useful chemicals', is a cornerstone of industrial chemistry in the OCR GCSE Combined Science course. It focuses on how raw materials are transformed into valuable products on a large scale, with an emphasis on the principles of chemical equilibrium, rates of reaction, and energy changes. You will study two major industrial processes: the Haber process for making ammonia (used in fertilisers) and the Contact process for making sulfuric acid (used in many industries). Additionally, you will explore the electrolysis of brine (sodium chloride solution) to produce chlorine, hydrogen, and sodium hydroxide.

    Understanding these processes is not just about memorising conditions; it's about applying the concepts of reversible reactions and Le Chatelier's principle. For example, you need to explain why certain temperatures and pressures are chosen to maximise yield while keeping costs manageable. This topic also links to environmental concerns, such as the energy demands of these processes and the importance of sustainability. Mastering this chapter will help you appreciate how chemistry contributes to everyday life, from food production to cleaning products.

    In exams, you will be expected to recall specific details, interpret graphs of yield against conditions, and evaluate the economic and environmental trade-offs. The content builds on earlier topics like atomic structure, bonding, and rates of reaction, so a solid grasp of those will be beneficial. By the end of this chapter, you should be able to describe the raw materials, stages, and conditions for each process, and explain the underlying chemistry with confidence.

    Key Concepts
    • →Reversible reactions and dynamic equilibrium: In a closed system, forward and reverse reactions occur at the same rate, and the concentrations of reactants and products remain constant.
    • →Le Chatelier's principle: If a system at equilibrium is subjected to a change in concentration, temperature, or pressure, the equilibrium shifts to counteract the change.
    • →The Haber process: N₂(g) + 3H₂(g) ⇌ 2NH₃(g) ΔH = -92 kJ/mol. Conditions: 450°C, 200 atm, iron catalyst. Ammonia is used to make fertilisers.
    • →The Contact process: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = -196 kJ/mol. Conditions: 450°C, 2 atm, vanadium(V) oxide catalyst. Sulfuric acid is used in many industries.
    • →Electrolysis of brine: 2NaCl(aq) + 2H₂O(l) → 2NaOH(aq) + H₂(g) + Cl₂(g). Products: chlorine at anode, hydrogen at cathode, sodium hydroxide remains in solution.
    Marking Points
    • Correct identification of products from acid reactions with metals, hydroxides, and carbonates.
    • Accurate description of laboratory procedures for salt preparation (filtration, evaporation, crystallisation, drying).
    • Correct use of pH scale and understanding of H+ ion concentration.
    • Explanation of factors affecting reaction rates (temperature, concentration, pressure, surface area) using collision theory.
    • Description of catalytic action in terms of activation energy.
    • Understanding of dynamic equilibrium in reversible reactions.
    • Prediction of equilibrium shifts based on changes in conditions.
    Examiner Tips
    • 💡When asked about rate of reaction, always refer to collision frequency and energy.
    • 💡Ensure balanced symbol equations include state symbols where required.
    • 💡Use the term 'dynamic equilibrium' when discussing reversible reactions in closed systems.
    • 💡Practice calculating pH changes based on H+ concentration shifts.
    • 💡Clearly distinguish between the effect of conditions on rate versus the effect on equilibrium position.
    • 💡Always quote exact conditions (temperature, pressure, catalyst) for each industrial process. Marks are often awarded for specific values, not just 'high temperature'.
    • 💡When explaining why a particular condition is used, always link to both rate and yield, and mention the compromise between them. For example, 'A higher temperature would increase rate but decrease yield because the reaction is exothermic, so 450°C is a compromise.'
    • 💡For electrolysis questions, write half-equations and state which electrode each product forms. Use the mnemonic 'An Ox, Red Cat' to remember oxidation at anode, reduction at cathode.
    Common Mistakes
    • Confusing 'strong' and 'weak' acids (degree of ionisation) with 'concentrated' and 'dilute' (amount of substance).
    • Incorrectly describing the effect of catalysts as changing the yield rather than just the rate.
    • Failing to mention that dynamic equilibrium only occurs in closed systems.
    • Misinterpreting the relationship between H+ ion concentration and pH (factor of 10 per pH unit).
    • Incomplete descriptions of collision theory (e.g., omitting 'frequency' or 'energy' of collisions).
    • Misconception: Increasing pressure always increases the yield of a reaction. Correction: Only if the forward reaction produces fewer gas molecules. In the Haber process, high pressure favours ammonia, but in reactions with equal gas moles, pressure has no effect.
    • Misconception: A catalyst increases the yield of a reaction. Correction: A catalyst speeds up the rate of both forward and reverse reactions equally, so it does not change the position of equilibrium or the yield, but helps reach equilibrium faster.
    • Misconception: The Haber process and Contact process use the same conditions. Correction: They are different reactions with different optimised conditions. Haber: 450°C, 200 atm, iron; Contact: 450°C, 2 atm, vanadium(V) oxide.
    Revision Plan
    1. 1Week 1, Day 1-2: Review reversible reactions and dynamic equilibrium. Write down definitions and draw a simple diagram of a closed system.
    2. 2Week 1, Day 3-4: Study the Haber process in detail. Create a fact file with raw materials, stages, conditions, and uses of ammonia. Practice explaining why each condition is used.
    3. 3Week 1, Day 5-6: Study the Contact process similarly. Compare and contrast with the Haber process.
    4. 4Week 2, Day 1-2: Learn electrolysis of brine. Draw a labelled diagram of the cell and write half-equations. Practice predicting products.
    5. 5Week 2, Day 3-4: Work through past exam questions on these processes. Focus on 6-mark questions that ask you to evaluate conditions.
    6. 6Week 2, Day 5-6: Use active recall to test yourself on key facts. Create mind maps linking the processes to real-world applications.
    Exam Question Types
    • 📋Multiple-choice questions: Often ask for the correct catalyst or conditions. Tip: Memorise the exact values and catalysts.
    • 📋Short-answer questions: 'State the raw materials for the Haber process.' Tip: Be precise – nitrogen from air, hydrogen from natural gas (methane).
    • 📋Data analysis: You may be given a graph of yield vs temperature/pressure and asked to interpret it. Tip: Describe the trend and explain using Le Chatelier's principle.
    • 📋6-mark extended response: 'Evaluate the use of high pressure in the Haber process.' Tip: Structure your answer with points for and against, and conclude with a justified decision.
    Command Word Expectations (OCR)
    State

    Give a brief, factual answer without explanation. For example, 'State the catalyst used in the Haber process.' Answer: 'Iron.'

    Explain

    Give reasons or causes. For example, 'Explain why a high pressure is used in the Haber process.' You must link the pressure to the equilibrium position and rate, using Le Chatelier's principle.

    Evaluate

    Weigh up the pros and cons, then make a judgement. For example, 'Evaluate the conditions used in the Contact process.' You should discuss rate, yield, cost, and safety, and conclude with a justified choice.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse the conditions for the Haber process with those for the Contact process, or forget to state the catalyst.
    ❌ Weak Answer (Loses Marks):The Haber process uses high pressure and a catalyst.
    Example improved answer:The Haber process uses a temperature of 450°C, a pressure of 200 atmospheres, and an iron catalyst to produce ammonia from nitrogen and hydrogen.
    Examiner Tip: Always quote the exact temperature, pressure, and catalyst for each industrial process. Use mnemonics like 'Haber: 450°C, 200 atm, iron'.
    Pitfall: In electrolysis of brine, students often mix up the products at each electrode or forget to state the ionic half-equations.
    ❌ Weak Answer (Loses Marks):Chlorine is made at the cathode.
    Example improved answer:In the electrolysis of brine, chlorine gas is produced at the anode (2Cl⁻ → Cl₂ + 2e⁻), hydrogen gas at the cathode (2H⁺ + 2e⁻ → H₂), and sodium hydroxide remains in the solution.
    Examiner Tip: Remember: anode = oxidation (loss of electrons), cathode = reduction (gain of electrons). For brine, chlorine is oxidised at the anode, hydrogen is reduced at the cathode.
    Step-by-Step Worked Solutions

    Question: In the Haber process, 100 tonnes of nitrogen are reacted with excess hydrogen. If the percentage yield of ammonia is 30%, what mass of ammonia is produced? (Relative atomic masses: N=14, H=1)

    1. 1.Step 1: Write the balanced equation: N₂ + 3H₂ ⇌ 2NH₃
    2. 2.Step 2: Calculate moles of nitrogen: moles = mass / Mr = 100,000,000 g / 28 g/mol = 3,571,428.6 mol
    3. 3.Step 3: Use molar ratio: 1 mol N₂ produces 2 mol NH₃, so theoretical moles of NH₃ = 2 × 3,571,428.6 = 7,142,857.2 mol
    4. 4.Step 4: Calculate theoretical mass of NH₃: mass = moles × Mr = 7,142,857.2 × 17 = 121,428,572 g = 121.4 tonnes
    5. 5.Step 5: Apply percentage yield: actual mass = (30/100) × 121.4 = 36.4 tonnes
    Final Answer: 36.4 tonnes of ammonia are produced.

    Question: In the Contact process, sulfur dioxide is converted to sulfur trioxide. The reaction is: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g) ΔH = -196 kJ/mol. Explain why a temperature of 450°C and a pressure of 2 atmospheres are used, despite the forward reaction being exothermic and producing fewer gas molecules.

    1. 1.Step 1: Identify the trade-off: lower temperature would increase yield (exothermic), but too low makes rate too slow.
    2. 2.Step 2: Identify pressure: higher pressure would increase yield (fewer gas molecules), but high pressure is expensive and dangerous.
    3. 3.Step 3: State the compromise: 450°C gives a reasonable rate with a yield of about 98%, and 2 atm is a compromise between yield and cost.
    4. 4.Step 4: Mention catalyst: vanadium(V) oxide is used to speed up the reaction without affecting position of equilibrium.
    Final Answer: 450°C and 2 atm are a compromise between rate, yield, and cost, with a vanadium(V) oxide catalyst to speed up the reaction.
    Active Recall Memory Test
    What are the exact conditions (temperature, pressure, catalyst) for the Haber process?
    Key Fact: 450°C, 200 atmospheres, iron catalyst.
    What is the purpose of the iron catalyst in the Haber process?
    Key Fact: It speeds up the reaction without affecting the position of equilibrium, allowing equilibrium to be reached faster.
    In the electrolysis of brine, which gas is produced at the anode?
    Key Fact: Chlorine gas (Cl₂).
    Why is a temperature of 450°C used in the Contact process, even though the forward reaction is exothermic?
    Key Fact: A lower temperature would give a higher yield but a slower rate. 450°C is a compromise that gives a reasonable rate and a high yield (about 98%).
    Frequently Asked Questions
    What is the difference between the Haber process and the Contact process?
    The Haber process makes ammonia from nitrogen and hydrogen, while the Contact process makes sulfuric acid from sulfur dioxide and oxygen. They use different raw materials, catalysts (iron vs vanadium(V) oxide), and pressures (200 atm vs 2 atm). Both are industrial processes that use reversible reactions and are optimised for yield and rate.
    Why is high pressure used in the Haber process but not in the Contact process?
    In the Haber process, the forward reaction produces fewer gas molecules (1 mol N₂ + 3 mol H₂ → 2 mol NH₃), so high pressure increases yield. In the Contact process, the forward reaction also produces fewer gas molecules (2 mol SO₂ + 1 mol O₂ → 2 mol SO₃), but the yield at 2 atm is already about 98%, so higher pressure is not worth the extra cost and safety risks.
    What is a reversible reaction?
    A reversible reaction is one where the products can react to form the original reactants. It is shown with a ⇌ symbol. In a closed system, it reaches dynamic equilibrium, where the forward and reverse reactions occur at the same rate, so concentrations stay constant.
    How does a catalyst affect the yield of a reversible reaction?
    A catalyst speeds up both the forward and reverse reactions equally, so it does not change the position of equilibrium or the yield. It only helps the system reach equilibrium faster, which saves time and energy in industrial processes.
    Why is ammonia important?
    Ammonia is used to make nitrogen-based fertilisers, such as ammonium nitrate, which are essential for growing crops. It is also used to make nitric acid, plastics, and cleaning products. Without ammonia, global food production would be severely limited.
    What are the products of the electrolysis of brine and why are they useful?
    The products are chlorine gas, hydrogen gas, and sodium hydroxide solution. Chlorine is used to make bleach, disinfectants, and PVC. Hydrogen is used as a fuel and to make ammonia. Sodium hydroxide is used to make soap, paper, and textiles.