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    Circuits — AQA A-Level Physics

    Teaching note checked against the official specification.

    Circuits in AQA A-Level Physics covers the analysis of series and parallel resistor networks, electromotive force (emf), internal resistance, potential dividers, and the conservation of charge and energy in electrical loops. Mastery requires applying Kirchhoff's laws, Ohm's law, and the power equations to solve quantitative problems involving current, potential difference, resistance, and power in both ideal and real circuit scenarios.

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    Circuits explained

    In any dc circuit, charge is neither created nor destroyed, so the current entering a junction equals the total current leaving it.

    Read the full explanation

    Energy is also conserved: each charge carrier that completes the circuit transfers energy from the source to the components, and the sum of potential differences around any closed loop equals the source emf. For example, in a series circuit the current is the same at every point because charge is conserved, while the p.d.s across components add to the supply p.d. because energy is conserved. In parallel branches, the branch currents sum to the total current, and each branch has the same p.d. Applying these principles lets you analyse unknown currents and p.d.s without memorising every circuit configuration.

    Read the Circuits study guideFull revision notes for AQA A-Level Physics

    Your focus

    1. State the principle of conservation of charge at a junction in a dc circuit.
    2. Apply conservation of charge to calculate an unknown current in a series or parallel circuit.
    3. Apply conservation of energy to calculate an unknown potential difference in a closed loop.

    Which command word is this?

    You must use mathematical operations to find a numerical answer. Show all working, include units, and round to an appropriate number of significant figures. Marks are awarded for correct substitution and final answer.

    Circuits exam tips

    Topic Overview

    This topic explores the fundamental principles governing electrical circuits, including Ohm's law, Kirchhoff's laws, and the behaviour of components in series and parallel arrangements. It extends to real-world applications such as potential dividers, internal resistance, and power dissipation, forming the bedrock for understanding more complex electronic systems.

    Circuits are essential in A-Level Physics because they link theoretical concepts of charge, energy, and potential difference to practical measurement and problem-solving. Mastery of this topic is crucial for exams and provides a foundation for further study in fields like electronics, engineering, and renewable energy.

    Key Concepts
    • →Ohm's law: For an ohmic conductor at constant temperature, current is directly proportional to potential difference (V = IR).
    • →Kirchhoff's laws: The sum of currents entering a junction equals the sum leaving (conservation of charge); the sum of emfs equals the sum of pds around any closed loop (conservation of energy).
    • →Series and parallel circuits: In series, current is constant and pds add; in parallel, pd is constant and currents add. Total resistance rules differ accordingly.
    • →Electromotive force (emf) and internal resistance: The emf is the energy transferred per unit charge by the source; internal resistance causes a drop in terminal pd when current flows (ε = I(R + r)).
    • →Potential dividers: Circuits that split a supply voltage in proportion to resistance, often used with sensors like thermistors and LDRs to produce variable output pds.
    Marking Points
    • State that electric charge is conserved at a junction: the sum of currents entering equals the sum of currents leaving.
    • Apply conservation of charge to series and parallel circuits to deduce unknown currents.
    • State that energy is conserved in a closed loop: the sum of potential differences around the loop equals the source emf.
    • Apply conservation of energy to series circuits to deduce unknown potential differences.
    • Use the relationship between energy transferred, charge and potential difference, W = QV, to support energy conservation arguments.
    • Recognise that in a parallel circuit the p.d. across each branch is the same because each branch connects the same two nodes.
    Examiner Tips
    • 💡When asked to find an unknown current, identify a junction and write an equation based on charge conservation before substituting numbers.
    • 💡When asked to find an unknown p.d., trace a closed loop and write an equation based on energy conservation, taking care with the direction of travel.
    • 💡Show the conservation principle explicitly in your working; a correct numerical answer without the principle may not gain full credit.
    • 💡Always define your symbols and state the equations you use before substituting numbers. This secures method marks even if arithmetic errors occur.
    • 💡When drawing circuit diagrams, use standard symbols and label all components, currents, and potential differences clearly. Ambiguous diagrams can lose marks.
    • 💡For 'show that' questions, work through the calculation step-by-step and ensure your final answer matches the given value to the required precision. Do not just state the answer.
    Common Mistakes
    • Thinking current is used up as it passes through components. Correction: current is the rate of flow of charge; charge is conserved, so the same current enters and leaves a series component.
    • Adding branch currents incorrectly in a parallel circuit, for example treating total current as the difference between branch currents. Correction: the total current is the sum of the branch currents.
    • Assuming energy is used up in the sense that charge loses energy permanently. Correction: energy is transferred from the source to components; the total energy transferred per unit charge around a closed loop is conserved.
    • Students often think current is 'used up' in a circuit. In reality, current is conserved; energy is transferred, causing potential difference across components.
    • Many believe that adding resistors in parallel increases total resistance. Actually, adding parallel resistors provides more paths for current, decreasing total resistance.
    • Some confuse emf with terminal potential difference. Emf is the total energy per unit charge supplied, while terminal pd is the energy per unit charge available to the external circuit, reduced by internal resistance.
    Revision Plan
    1. 1Day 1-2: Review definitions of current, potential difference, resistance, and emf. Practice using I = ΔQ/Δt and V = W/Q with numerical examples.
    2. 2Day 3-4: Master series and parallel circuit rules. Solve problems calculating total resistance, current, and pd in various combinations.
    3. 3Day 5-6: Study Kirchhoff's laws and apply them to multi-loop circuits. Practice deriving equations for unknown currents and pds.
    4. 4Day 7-8: Learn about internal resistance and terminal pd. Solve problems involving ε = I(R + r) and V = ε - Ir.
    5. 5Day 9-10: Explore potential dividers, including with thermistors and LDRs. Practice calculating output voltage and interpreting graphs.
    6. 6Day 11-12: Complete past paper questions on circuits, focusing on structured 6-mark questions and calculations. Review mark schemes for examiner expectations.
    Exam Question Types
    • 📋Calculation questions: Often ask for current, pd, resistance, or power in series/parallel circuits. Advice: Write down the relevant equation, substitute values with units, and give the answer to an appropriate number of significant figures.
    • 📋Circuit analysis with Kirchhoff's laws: May present a multi-loop circuit and ask to calculate unknown currents or pds. Advice: Label currents and pds clearly, apply junction and loop rules systematically, and solve simultaneous equations.
    • 📋Practical-based questions: Involve interpreting I-V graphs for ohmic and non-ohmic conductors, or explaining the effect of internal resistance. Advice: Describe the shape of graphs and relate to physical principles, using correct terminology.
    • 📋Potential divider design: Ask to calculate output voltage or explain how a thermistor/LDR changes output. Advice: Use the potential divider equation Vout = Vin × (R2/(R1+R2)) and explain how resistance changes with temperature or light intensity.
    Command Word Expectations (AQA)
    Calculate

    You must use mathematical operations to find a numerical answer. Show all working, include units, and round to an appropriate number of significant figures. Marks are awarded for correct substitution and final answer.

    Explain

    You must provide a detailed justification that links cause and effect, using correct physics terminology. Typically requires a sequence of logical steps, often worth 2-3 marks. Avoid vague statements; be specific about physical principles.

    Describe

    You must give a detailed account of a process, pattern, or observation without necessarily explaining why. Use precise language and include key features. Often worth 2-3 marks, with marks for each correct point.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often assume that current is 'used up' as it flows through components in a series circuit, leading to incorrect calculations of current at different points.
    ❌ Weak Answer (Loses Marks):The current decreases after each resistor because some is used by the resistor.
    Example improved answer:In a series circuit, the current is the same at every point because charge is conserved (Kirchhoff's first law). The current is not used up; rather, energy is transferred from the charge carriers to the components, causing a potential difference across each component.
    Examiner Tip: Always state that current is the rate of flow of charge and is conserved at a junction or in a series loop. Use the equation I = ΔQ/Δt to reinforce the definition.
    Pitfall: When calculating total resistance in a parallel circuit, students often add resistances directly instead of using the reciprocal formula, or they forget to take the reciprocal of the sum at the end.
    ❌ Weak Answer (Loses Marks):The total resistance is 2 + 3 = 5 Ω.
    Example improved answer:For resistors in parallel, the reciprocal of the total resistance is the sum of the reciprocals of the individual resistances: 1/RT = 1/R1 + 1/R2. For 2 Ω and 3 Ω, 1/RT = 1/2 + 1/3 = 5/6, so RT = 6/5 = 1.2 Ω.
    Examiner Tip: Remember that the total resistance of parallel resistors is always less than the smallest individual resistance. Use the formula 1/RT = Σ(1/Ri) and double-check your final reciprocal step.
    Step-by-Step Worked Solutions

    Question: A battery of emf 9.0 V and internal resistance 0.50 Ω is connected to a resistor of resistance 4.0 Ω. Calculate the current in the circuit and the terminal potential difference across the battery.

    1. 1.Step 1: Identify given facts: emf ε = 9.0 V, internal resistance r = 0.50 Ω, external resistance R = 4.0 Ω.
    2. 2.Step 2: Apply the equation for a real battery: ε = I(R + r). Rearrange to find current: I = ε / (R + r).
    3. 3.Step 3: Substitute values: I = 9.0 / (4.0 + 0.50) = 9.0 / 4.5 = 2.0 A.
    4. 4.Step 4: Calculate terminal pd using V = IR: V = 2.0 × 4.0 = 8.0 V. Alternatively, V = ε - Ir = 9.0 - (2.0 × 0.50) = 8.0 V.
    5. 5.Step 5: State final answers with units: current = 2.0 A, terminal pd = 8.0 V.
    Final Answer: Current = 2.0 A; terminal potential difference = 8.0 V.

    Question: Two resistors, R1 = 6.0 Ω and R2 = 3.0 Ω, are connected in parallel across a 12 V supply of negligible internal resistance. Calculate the total resistance, the current through each resistor, and the total current drawn from the supply.

    1. 1.Step 1: Identify given facts: R1 = 6.0 Ω, R2 = 3.0 Ω, V = 12 V (same across parallel branches).
    2. 2.Step 2: Calculate total resistance using 1/RT = 1/R1 + 1/R2 = 1/6 + 1/3 = 1/6 + 2/6 = 3/6 = 1/2. Therefore RT = 2.0 Ω.
    3. 3.Step 3: Calculate current through R1: I1 = V / R1 = 12 / 6.0 = 2.0 A.
    4. 4.Step 4: Calculate current through R2: I2 = V / R2 = 12 / 3.0 = 4.0 A.
    5. 5.Step 5: Total current I = I1 + I2 = 2.0 + 4.0 = 6.0 A. Check with I = V / RT = 12 / 2.0 = 6.0 A.
    6. 6.Step 6: State final answers with units: RT = 2.0 Ω, I1 = 2.0 A, I2 = 4.0 A, total current = 6.0 A.
    Final Answer: Total resistance = 2.0 Ω; current through 6.0 Ω = 2.0 A; current through 3.0 Ω = 4.0 A; total current = 6.0 A.
    Active Recall Memory Test
    State Kirchhoff's first and second laws and explain the conservation principle behind each.
    Key Fact: Kirchhoff's first law: The sum of currents entering a junction equals the sum leaving (conservation of charge). Second law: The sum of emfs equals the sum of pds around any closed loop (conservation of energy).
    What is the formula for total resistance of two resistors in parallel?
    Key Fact: 1/RT = 1/R1 + 1/R2, or RT = (R1 × R2) / (R1 + R2).
    Define electromotive force (emf) and state its unit.
    Key Fact: Emf is the energy transferred per unit charge by a source when converting other forms of energy into electrical energy. Unit: volt (V), which is joule per coulomb (J/C).
    How does the terminal potential difference of a battery change as the current drawn from it increases?
    Key Fact: Terminal pd decreases because the potential drop across the internal resistance (Ir) increases, so V = ε - Ir becomes smaller.
    Frequently Asked Questions
    What is the difference between emf and potential difference?
    Emf (electromotive force) is the total energy transferred per unit charge by a source, such as a battery, when converting chemical energy to electrical energy. Potential difference (pd) is the energy transferred per unit charge between two points in a circuit, where electrical energy is converted to other forms. Emf is the cause that drives current, while pd is the effect across components. In a real battery, terminal pd is less than emf due to internal resistance.
    How do I calculate total resistance in a parallel circuit?
    For resistors in parallel, the reciprocal of the total resistance is the sum of the reciprocals of the individual resistances: 1/RT = 1/R1 + 1/R2 + ... . For two resistors, you can use RT = (R1 × R2) / (R1 + R2). Always remember that the total resistance is less than the smallest individual resistance. After summing reciprocals, take the reciprocal of the result to find RT.
    Why does the current stay the same in a series circuit?
    In a series circuit, there is only one path for charge to flow, so the rate of flow of charge (current) must be the same at every point. This is a consequence of the conservation of charge: charge cannot accumulate or disappear at any point. The energy carried by each coulomb of charge is transferred to components as potential difference, but the number of coulombs passing per second remains constant.
    What is internal resistance and how does it affect a circuit?
    Internal resistance is the resistance within a power source (like a battery) that opposes the flow of current. It causes some energy to be dissipated inside the source, reducing the terminal potential difference available to the external circuit. The relationship is given by ε = I(R + r), where ε is emf, I is current, R is external resistance, and r is internal resistance. As current increases, the terminal pd decreases.
    How do I use a potential divider to control output voltage?
    A potential divider consists of two resistors in series across a supply voltage. The output voltage is taken across one of the resistors and is given by Vout = Vin × (R2 / (R1 + R2)), where R2 is the resistor across which output is measured. By changing the resistance values (e.g., using a variable resistor or a sensor like a thermistor), you can control the output voltage. This is commonly used in sensing circuits.
    What are the key differences between series and parallel circuits?
    In a series circuit, components are connected end-to-end, so the current is the same through all components, and the total potential difference is the sum of individual pds. Total resistance is the sum of individual resistances. In a parallel circuit, components are connected across the same potential difference, so the pd is the same across all branches, and the total current is the sum of branch currents. Total resistance is less than the smallest individual resistance, calculated using reciprocals.