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    Doppler effect (A-level only) — AQA A-Level Physics

    Teaching note checked against the official specification.

    The Doppler effect is the change in observed frequency (and wavelength) of a wave when there is relative motion between the source and the observer. For AQA A-Level Physics, you must apply the formula f' = fv / (v +/- vs) for a moving source and f' = f(v +/- vo) / v for a moving observer, and explain redshift in terms of receding galaxies.

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    Doppler effect (A-level only) explained

    Galaxies are vast gravitationally bound systems of stars, gas, dust and dark matter; our Milky Way is one example.

    Read the full explanation

    Their spectra contain absorption and emission lines, so the observed wavelengths identify chemical composition and reveal motion through the Doppler effect. Quasars are extremely luminous active galactic nuclei powered by supermassive black holes accreting matter; they can outshine their host galaxy and are observed at great distances, so their light was emitted when the universe was younger. In this section you interpret galactic and quasar spectra, recognise large redshifts, and relate observed wavelength shifts to recession speed using Δλ/λ₀ = v/c for speeds much less than c. You should distinguish a galaxy from a quasar by scale, luminosity and spectral appearance, and explain why quasars are useful probes of the distant universe.

    Read the Doppler effect (A-level only) study guideFull revision notes for AQA A-Level Physics

    Your focus

    1. Distinguish between a galaxy and a quasar in terms of scale, structure and luminosity.
    2. Interpret redshifted spectral lines from galaxies and quasars using the Doppler effect.
    3. Calculate recession speed from observed and rest wavelengths using Δλ/λ₀ = v/c for speeds much less than c.

    Which command word is this?

    You must use the correct formula, substitute numerical values, and give your answer to an appropriate number of significant figures with units. Show all working.

    Doppler effect (A-level only) exam tips

    Topic Overview

    The Doppler effect describes how the observed frequency of a wave changes when there is relative motion between the source and the observer. It applies to all waves, including sound, light, and water waves. In AQA A-Level Physics, you must be able to derive and use the equations for a moving source and a moving observer, and explain the effect in terms of wavefronts.

    This topic is crucial for understanding redshift in astronomy, which provides evidence for the Big Bang and an expanding universe. It also has practical applications such as speed guns, medical ultrasound, and radar. Mastering the Doppler effect requires careful attention to sign conventions and the distinction between wave speed, frequency, and wavelength.

    Key Concepts
    • →The observed frequency f' increases when the source and observer move towards each other, and decreases when they move apart.
    • →For a stationary observer and a source moving towards them: f' = fv / (v - vs). For a source moving away: f' = fv / (v + vs).
    • →For a stationary source and an observer moving towards it: f' = f(v + vo) / v. For an observer moving away: f' = f(v - vo) / v.
    • →The wave speed v is determined by the medium and does not change due to relative motion; only frequency and wavelength change.
    • →Redshift z = (lambda_obs - lambda_rest) / lambda_rest = delta_lambda / lambda, and for small z, recessional velocity v = cz. Hubble's law v = H0 d links velocity to distance.
    Marking Points
    • A galaxy is a gravitationally bound system containing stars, gas, dust and dark matter; the Milky Way is the galaxy containing the Solar System.
    • A quasar is an extremely luminous active galactic nucleus powered by accretion onto a supermassive black hole, often outshining its host galaxy.
    • Spectral lines from galaxies and quasars are compared with laboratory reference wavelengths to identify redshift or blueshift.
    • For speeds much less than c, the Doppler shift is approximated by Δλ/λ₀ = v/c, where Δλ is the observed minus rest wavelength and λ₀ is the rest wavelength.
    • Large redshifts of quasars indicate high recession speeds and great distances, so they are observed as they were when the universe was younger.
    • Quasars are not simply distant galaxies; they are compact, exceptionally luminous active nuclei, whereas galaxies are extended systems of stars and gas.
    Examiner Tips
    • 💡When comparing spectra, state clearly whether lines are shifted to longer or shorter wavelengths and link this to motion away from or towards the observer.
    • 💡Show the substitution into Δλ/λ₀ = v/c, including the rest wavelength λ₀, before calculating the speed.
    • 💡Use the term active galactic nucleus when explaining quasar energy sources, and avoid saying that a quasar is simply a bright star.
    • 💡If a question asks why quasars are useful, refer to their extreme luminosity allowing them to be observed at large distances and their large redshifts indicating early cosmic times.
    • 💡Always write down the formula you are using and define each symbol. This secures method marks even if arithmetic slips.
    • 💡For 'explain' questions, refer to wavefronts: when the source moves towards the observer, wavefronts are compressed, so the wavelength is shorter and frequency higher.
    • 💡In redshift calculations, use the rest wavelength as the denominator and state that z is dimensionless. For high speeds, use the relativistic formula if given, but AQA typically uses v = cz for z << 1.
    Common Mistakes
    • Treating a quasar as just a very distant galaxy: correct by stating that a quasar is an active galactic nucleus powered by a supermassive black hole and can outshine its host galaxy.
    • Using the relativistic Doppler formula when the non-relativistic approximation Δλ/λ₀ = v/c is intended: correct by checking that the recession speed is much less than c before using the simple formula.
    • Confusing redshift with blueshift: correct by remembering that redshift means observed wavelengths are longer than rest wavelengths, which corresponds to recession.
    • Forgetting to convert wavelength units consistently: correct by converting all wavelengths to the same unit, such as nanometres or metres, before calculating Δλ/λ₀.
    • Students think the speed of the wave changes when the source moves. Correction: The wave speed is constant in a given medium; only the observed frequency and wavelength change.
    • Students mix up the signs in the Doppler formula. Correction: Always determine whether the source or observer is moving towards or away, and use the formula that increases frequency for approach and decreases for recession.
    • Students believe redshift means the galaxy is actually red. Correction: Redshift refers to the increase in wavelength of any electromagnetic radiation due to relative motion away from the observer; it is not about colour.
    Revision Plan
    1. 1Day 1: Revise wave basics and the wave equation. Watch a video on the Doppler effect to visualise wavefront compression.
    2. 2Day 2: Learn the two Doppler formulas for moving source and moving observer. Practice 5 calculations for each, paying attention to signs.
    3. 3Day 3: Study redshift and Hubble's law. Derive z = delta_lambda / lambda and v = cz. Practice 3 redshift problems.
    4. 4Day 4: Attempt exam-style questions on the Doppler effect, including 6-mark explanations. Mark your answers using the mark scheme.
    5. 5Day 5: Review common misconceptions and create a summary sheet with key formulas and definitions. Test yourself with active recall prompts.
    Exam Question Types
    • 📋Calculation of observed frequency for a moving source or observer. Advice: Identify the correct formula, substitute values, and give units.
    • 📋Explanation of the Doppler effect in terms of wavefronts. Advice: Use clear diagrams and refer to compression and stretching of wavefronts.
    • 📋Redshift calculation and estimation of distance using Hubble's law. Advice: Calculate z first, then v = cz, then d = v / H0. Keep units consistent.
    • 📋Practical application question, e.g., speed gun or ultrasound. Advice: Link the observed frequency shift to the relative speed and use the appropriate formula.
    Command Word Expectations (AQA)
    Calculate

    You must use the correct formula, substitute numerical values, and give your answer to an appropriate number of significant figures with units. Show all working.

    Explain

    You must give a detailed account of the physics, using correct terminology such as 'wavefronts', 'compressed', 'wavelength', and 'frequency'. Link cause and effect clearly.

    Derive

    You must start from the wave equation and the definition of frequency, and show logical steps to obtain the Doppler formula. State any assumptions made.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often confuse which sign to use in the Doppler formula, especially when the source moves towards or away from a stationary observer. They also forget that the speed of the wave in the medium remains constant; only frequency and wavelength change.
    ❌ Weak Answer (Loses Marks):The observed frequency increases because the source is moving, so use f' = fv / (v - vs) without checking direction or stating that v is the speed of sound.
    Example improved answer:For a source moving towards a stationary observer, the observed frequency is f' = fv / (v - vs), where v is the speed of sound in air (340 m/s) and vs is the speed of the source. The wavelength in front of the source is shortened, so more wavefronts reach the observer per second, increasing the observed frequency. The wave speed v remains constant.
    Examiner Tip: Always define your symbols and state the direction of motion. Draw a diagram showing wavefronts compressed in front of the source and stretched behind. Remember: if the source moves towards the observer, the denominator is (v - vs); if away, (v + vs).
    Pitfall: In redshift calculations, students incorrectly use the non-relativistic Doppler formula for high-speed galaxies or forget that redshift z = (lambda_observed - lambda_rest) / lambda_rest = delta_lambda / lambda. They also fail to link redshift to the expansion of the universe.
    ❌ Weak Answer (Loses Marks):Redshift means the galaxy is moving away, so use v = H0 d and say the universe is expanding. No calculation of z or mention of wavelength change.
    Example improved answer:Redshift z is defined as z = (lambda_obs - lambda_rest) / lambda_rest. For a receding galaxy, the observed wavelength is longer than the rest wavelength, so z is positive. Using the relativistic Doppler formula for small z, v = cz, and combining with Hubble's law v = H0 d gives d = cz / H0. This provides evidence that the universe is expanding.
    Examiner Tip: For AQA, you are expected to use z = delta_lambda / lambda and v = cz for speeds much less than c. Always state that redshift is evidence for an expanding universe and that Hubble's law relates recessional velocity to distance.
    Step-by-Step Worked Solutions

    Question: An ambulance siren emits a sound of frequency 750 Hz. The ambulance moves towards a stationary observer at 25 m/s. The speed of sound in air is 340 m/s. Calculate the frequency heard by the observer.

    1. 1.Step 1: Identify given facts: f = 750 Hz, vs = 25 m/s, v = 340 m/s, observer stationary (vo = 0). Source moving towards observer.
    2. 2.Step 2: Apply the Doppler formula for a moving source towards a stationary observer: f' = fv / (v - vs).
    3. 3.Step 3: Substitute values: f' = (750 x 340) / (340 - 25) = 255000 / 315 = 809.52 Hz.
    4. 4.Step 4: State final conclusion with units: The observed frequency is approximately 810 Hz (to 2 s.f.).
    Final Answer: f' = 810 Hz (2 s.f.)

    Question: A distant galaxy emits light with a rest wavelength of 656.3 nm. The observed wavelength on Earth is 689.1 nm. Calculate the redshift z and the recessional velocity of the galaxy. Take the speed of light c = 3.00 x 10^8 m/s. Hence estimate the distance to the galaxy using Hubble's law with H0 = 2.2 x 10^-18 s^-1.

    1. 1.Step 1: Calculate redshift z = (lambda_obs - lambda_rest) / lambda_rest = (689.1 - 656.3) / 656.3 = 32.8 / 656.3 = 0.0500.
    2. 2.Step 2: Use v = cz for small z: v = 0.0500 x 3.00 x 10^8 = 1.50 x 10^7 m/s.
    3. 3.Step 3: Apply Hubble's law: v = H0 d, so d = v / H0 = (1.50 x 10^7) / (2.2 x 10^-18) = 6.82 x 10^24 m.
    4. 4.Step 4: State final conclusion with units: The galaxy is approximately 6.8 x 10^24 m away.
    Final Answer: z = 0.0500, v = 1.5 x 10^7 m/s, d = 6.8 x 10^24 m
    Active Recall Memory Test
    State the Doppler formula for a source moving towards a stationary observer.
    Key Fact: f' = fv / (v - vs), where v is the speed of the wave, vs is the speed of the source, and f is the emitted frequency.
    What is redshift and how is it calculated?
    Key Fact: Redshift is the increase in observed wavelength of light from a receding source. It is calculated as z = (lambda_obs - lambda_rest) / lambda_rest = delta_lambda / lambda.
    State Hubble's law and explain what it implies.
    Key Fact: Hubble's law: v = H0 d, where v is recessional velocity, H0 is the Hubble constant, and d is distance. It implies that the universe is expanding.
    Why does the speed of a wave not change due to the Doppler effect?
    Key Fact: The speed of a wave is determined by the properties of the medium (e.g., temperature for sound, permittivity for light). Relative motion of source and observer does not alter the medium, so wave speed remains constant.
    Frequently Asked Questions
    What is the Doppler effect in simple terms?
    The Doppler effect is the change in frequency or wavelength of a wave when the source or observer is moving. If they move closer together, the observed frequency increases; if they move apart, it decreases. A common example is the change in pitch of an ambulance siren as it passes you.
    How do I know which Doppler formula to use?
    First identify whether the source or observer is moving. If the source moves towards a stationary observer, use f' = fv / (v - vs). If it moves away, use f' = fv / (v + vs). If the observer moves towards a stationary source, use f' = f(v + vo) / v; if away, use f' = f(v - vo) / v. Always check that the observed frequency increases for approach and decreases for recession.
    What is redshift and how does it provide evidence for the Big Bang?
    Redshift is the increase in wavelength of light from galaxies moving away from us. The further away a galaxy is, the greater its redshift, implying it is receding faster. This observation, summarised by Hubble's law, suggests that the universe is expanding. Extrapolating backwards in time leads to the idea that all matter was once concentrated in a hot, dense point, supporting the Big Bang theory.
    Do I need to use the relativistic Doppler formula for AQA A-Level Physics?
    For AQA A-Level Physics, you are only required to use the non-relativistic formula v = cz for redshift, which is valid when the recessional velocity is much less than the speed of light. You should be aware that for speeds close to c, relativistic effects become significant, but you will not be examined on the relativistic formula unless it is provided in the question.
    What are some real-world applications of the Doppler effect?
    The Doppler effect is used in police radar speed guns to measure vehicle speed, in medical ultrasound to measure blood flow, in weather radar to track storm motion, and in astronomy to measure the speed of stars and galaxies. It is also used in some types of burglar alarms and in satellite communication.
    Why does the frequency change but not the wave speed?
    The wave speed is determined by the medium through which the wave travels. For sound, it depends on the temperature and composition of the air; for light, it depends on the permittivity and permeability of the medium. The relative motion of the source and observer does not change these properties, so the wave speed remains constant. However, the motion causes the wavefronts to be compressed or stretched, changing the observed wavelength and hence the observed frequency.