Electric Circuits — Edexcel A-Level Physics
Test yourself on Electric Circuits with PEARSON EDEXCEL A-Level practice questions.
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Electric Circuits explained
This topic covers Ohm's law, resistance calculations, and resistivity.
Read the full explanation
Learners apply formulas to solve circuit problems and understand material properties.
Your focus
- Use Ohm's law and calculate resistance
- Calculate resistivity of a material
Electric Circuits exam tips
Quick Revision Summary (Key Takeaway)
Electric Circuits in A-Level Physics covers the relationships between current, voltage, and resistance in series and parallel circuits, including Kirchhoff's laws, electromotive force (e.m.f.), and internal resistance. Mastery of circuit analysis, using Ohm's law and power equations, is essential for solving problems involving real batteries and complex resistor networks.
Topic Overview
Electric circuits form a fundamental part of A-Level Physics, bridging theoretical concepts with practical applications. This topic introduces the key quantities of current, potential difference, and resistance, and explores how they interact in series and parallel configurations. Understanding these relationships is crucial for analysing real-world electrical systems, from simple household wiring to complex electronic devices.
The study of circuits also introduces Kirchhoff's laws, which are powerful tools for solving multi-loop circuits, and the concept of electromotive force (e.m.f.) and internal resistance, which explains why a battery's terminal voltage drops when it supplies current. These principles are not only examinable but also essential for understanding energy transfer and power distribution in electrical engineering.
Mastery of this topic requires a solid grasp of both theoretical rules and practical problem-solving skills. Students must be able to draw and interpret circuit diagrams, calculate equivalent resistances, and apply Ohm's law and power equations accurately. This knowledge forms the foundation for more advanced topics such as capacitance, alternating current, and electronics, making it a cornerstone of the physics curriculum.
Key Concepts
- →Current (I) is the rate of flow of charge, measured in amperes (A), and is the same at all points in a series circuit.
- →Potential difference (V) is the energy transferred per unit charge between two points, measured in volts (V).
- →Resistance (R) is a measure of how a component opposes current flow, calculated using Ohm's law: V = IR.
- →In series circuits, resistances add: R_total = R1 + R2 + ...; in parallel, reciprocals add: 1/R_total = 1/R1 + 1/R2 + ...
- →Kirchhoff's first law (junction rule) states that total current entering a junction equals total current leaving; Kirchhoff's second law (loop rule) states that the sum of e.m.f.s equals the sum of potential differences around a closed loop.
- →A real battery has internal resistance (r), causing terminal voltage (V = ε - Ir) to be less than e.m.f. when current flows.
Marking Points
- Applies Ohm's law (V=IR) correctly.
- Calculates resistance in series and parallel circuits.
- Uses resistivity formula (R=ρL/A) to find resistivity.
- Interprets circuit diagrams and experimental data.
Examiner Tips
- 💡Write down formulas before substituting values.
- 💡Check units and convert if necessary.
- 💡Draw circuit diagrams to visualise connections.
- 💡Always show your working and include units in every step of a calculation. Even if your final answer is wrong, you can gain method marks.
- 💡When drawing circuit diagrams, use standard symbols and label components clearly. Check that meters are correctly placed: ammeters in series, voltmeters in parallel.
- 💡For questions involving internal resistance, remember to use the full circuit equation ε = I(R + r) and not just V = IR for the external circuit.
Common Mistakes
- Mixing up units (volts, amps, ohms).
- Incorrectly adding resistors in parallel.
- Forgetting to convert units (e.g., mm² to m²).
- Misconception: Current is 'used up' as it flows through a circuit. Correction: Charge is conserved; current is the same throughout a series circuit, but energy is transferred to components.
- Misconception: In parallel circuits, the voltage is divided among branches. Correction: Voltage is the same across each parallel branch; it is current that divides.
- Misconception: A voltmeter should be connected in series to measure the voltage across a component. Correction: Voltmeters are connected in parallel, as they measure the potential difference between two points.
Revision Plan
- 1Day 1-2: Review the definitions of current, voltage, and resistance, and practice using Ohm's law with simple calculations.
- 2Day 3-4: Learn the rules for series and parallel circuits, and practice calculating total resistance for various combinations.
- 3Day 5-6: Study Kirchhoff's laws and apply them to multi-loop circuits. Work through past exam questions.
- 4Day 7-8: Focus on e.m.f. and internal resistance, including how to measure them experimentally and solve problems.
- 5Day 9-10: Consolidate by attempting mixed problem sets and timed exam-style questions. Review mistakes and revisit weak areas.
Exam Question Types
- 📋Calculation questions: These often ask you to find current, voltage, resistance, or power in a given circuit. Show all steps and check units.
- 📋Circuit diagram questions: You may be asked to draw or interpret a circuit, including placing ammeters and voltmeters correctly.
- 📋Experimental design questions: Describe how to determine the e.m.f. and internal resistance of a battery using a variable resistor and voltmeter.
- 📋6-mark extended response: Explain the differences between series and parallel circuits, or discuss the effect of internal resistance on terminal voltage.
Command Word Expectations (PEARSON EDEXCEL)
Use the given data and relevant formulae to work out a numerical answer. Show all working and include units in your final answer.
Provide a clear, logical account of why something happens, using scientific principles and terminology. Give reasons and mechanisms.
Give a detailed account of what happens or how something is done, without necessarily explaining why. Include key features and steps.
How Students Lose Marks (Examiner Pitfalls)
Step-by-Step Worked Solutions
Question: A battery of e.m.f. 12 V and internal resistance 0.5 Ω is connected to a 5 Ω resistor. Calculate: (a) the current in the circuit, (b) the terminal voltage of the battery, (c) the power dissipated in the 5 Ω resistor.
- 1.Step 1: Identify given values: e.m.f. (ε) = 12 V, internal resistance (r) = 0.5 Ω, external resistance (R) = 5 Ω.
- 2.Step 2: Use the circuit equation ε = I(R + r) to find current: I = ε / (R + r) = 12 / (5 + 0.5) = 12 / 5.5 = 2.18 A.
- 3.Step 3: Calculate terminal voltage: V = ε - Ir = 12 - (2.18 × 0.5) = 12 - 1.09 = 10.91 V.
- 4.Step 4: Calculate power in external resistor: P = I²R = (2.18)² × 5 = 4.75 × 5 = 23.8 W.
Question: Three resistors of 4 Ω, 6 Ω, and 12 Ω are connected in parallel across a 24 V supply. Calculate: (a) the total resistance, (b) the current drawn from the supply, (c) the current through each resistor.
- 1.Step 1: For parallel resistors, use 1/R_total = 1/4 + 1/6 + 1/12.
- 2.Step 2: Compute the sum: 1/4 = 0.25, 1/6 = 0.1667, 1/12 = 0.0833, so 1/R_total = 0.5. Therefore R_total = 2 Ω.
- 3.Step 3: Use Ohm's law to find total current: I = V / R_total = 24 / 2 = 12 A.
- 4.Step 4: Since voltage is same across each branch, I1 = 24/4 = 6 A, I2 = 24/6 = 4 A, I3 = 24/12 = 2 A.