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    Electric Circuits — Edexcel A-Level Physics

    Test yourself on Electric Circuits with PEARSON EDEXCEL A-Level practice questions.

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    Electric Circuits explained

    This topic covers Ohm's law, resistance calculations, and resistivity.

    Read the full explanation

    Learners apply formulas to solve circuit problems and understand material properties.

    Your focus

    1. Use Ohm's law and calculate resistance
    2. Calculate resistivity of a material

    Electric Circuits exam tips

    Quick Revision Summary (Key Takeaway)

    Electric Circuits in A-Level Physics covers the relationships between current, voltage, and resistance in series and parallel circuits, including Kirchhoff's laws, electromotive force (e.m.f.), and internal resistance. Mastery of circuit analysis, using Ohm's law and power equations, is essential for solving problems involving real batteries and complex resistor networks.

    Topic Overview

    Electric circuits form a fundamental part of A-Level Physics, bridging theoretical concepts with practical applications. This topic introduces the key quantities of current, potential difference, and resistance, and explores how they interact in series and parallel configurations. Understanding these relationships is crucial for analysing real-world electrical systems, from simple household wiring to complex electronic devices.

    The study of circuits also introduces Kirchhoff's laws, which are powerful tools for solving multi-loop circuits, and the concept of electromotive force (e.m.f.) and internal resistance, which explains why a battery's terminal voltage drops when it supplies current. These principles are not only examinable but also essential for understanding energy transfer and power distribution in electrical engineering.

    Mastery of this topic requires a solid grasp of both theoretical rules and practical problem-solving skills. Students must be able to draw and interpret circuit diagrams, calculate equivalent resistances, and apply Ohm's law and power equations accurately. This knowledge forms the foundation for more advanced topics such as capacitance, alternating current, and electronics, making it a cornerstone of the physics curriculum.

    Key Concepts
    • →Current (I) is the rate of flow of charge, measured in amperes (A), and is the same at all points in a series circuit.
    • →Potential difference (V) is the energy transferred per unit charge between two points, measured in volts (V).
    • →Resistance (R) is a measure of how a component opposes current flow, calculated using Ohm's law: V = IR.
    • →In series circuits, resistances add: R_total = R1 + R2 + ...; in parallel, reciprocals add: 1/R_total = 1/R1 + 1/R2 + ...
    • →Kirchhoff's first law (junction rule) states that total current entering a junction equals total current leaving; Kirchhoff's second law (loop rule) states that the sum of e.m.f.s equals the sum of potential differences around a closed loop.
    • →A real battery has internal resistance (r), causing terminal voltage (V = ε - Ir) to be less than e.m.f. when current flows.
    Marking Points
    • Applies Ohm's law (V=IR) correctly.
    • Calculates resistance in series and parallel circuits.
    • Uses resistivity formula (R=ρL/A) to find resistivity.
    • Interprets circuit diagrams and experimental data.
    Examiner Tips
    • 💡Write down formulas before substituting values.
    • 💡Check units and convert if necessary.
    • 💡Draw circuit diagrams to visualise connections.
    • 💡Always show your working and include units in every step of a calculation. Even if your final answer is wrong, you can gain method marks.
    • 💡When drawing circuit diagrams, use standard symbols and label components clearly. Check that meters are correctly placed: ammeters in series, voltmeters in parallel.
    • 💡For questions involving internal resistance, remember to use the full circuit equation ε = I(R + r) and not just V = IR for the external circuit.
    Common Mistakes
    • Mixing up units (volts, amps, ohms).
    • Incorrectly adding resistors in parallel.
    • Forgetting to convert units (e.g., mm² to m²).
    • Misconception: Current is 'used up' as it flows through a circuit. Correction: Charge is conserved; current is the same throughout a series circuit, but energy is transferred to components.
    • Misconception: In parallel circuits, the voltage is divided among branches. Correction: Voltage is the same across each parallel branch; it is current that divides.
    • Misconception: A voltmeter should be connected in series to measure the voltage across a component. Correction: Voltmeters are connected in parallel, as they measure the potential difference between two points.
    Revision Plan
    1. 1Day 1-2: Review the definitions of current, voltage, and resistance, and practice using Ohm's law with simple calculations.
    2. 2Day 3-4: Learn the rules for series and parallel circuits, and practice calculating total resistance for various combinations.
    3. 3Day 5-6: Study Kirchhoff's laws and apply them to multi-loop circuits. Work through past exam questions.
    4. 4Day 7-8: Focus on e.m.f. and internal resistance, including how to measure them experimentally and solve problems.
    5. 5Day 9-10: Consolidate by attempting mixed problem sets and timed exam-style questions. Review mistakes and revisit weak areas.
    Exam Question Types
    • 📋Calculation questions: These often ask you to find current, voltage, resistance, or power in a given circuit. Show all steps and check units.
    • 📋Circuit diagram questions: You may be asked to draw or interpret a circuit, including placing ammeters and voltmeters correctly.
    • 📋Experimental design questions: Describe how to determine the e.m.f. and internal resistance of a battery using a variable resistor and voltmeter.
    • 📋6-mark extended response: Explain the differences between series and parallel circuits, or discuss the effect of internal resistance on terminal voltage.
    Command Word Expectations (PEARSON EDEXCEL)
    Calculate

    Use the given data and relevant formulae to work out a numerical answer. Show all working and include units in your final answer.

    Explain

    Provide a clear, logical account of why something happens, using scientific principles and terminology. Give reasons and mechanisms.

    Describe

    Give a detailed account of what happens or how something is done, without necessarily explaining why. Include key features and steps.

    How Students Lose Marks (Examiner Pitfalls)
    Pitfall: Students often forget that ammeters are placed in series and voltmeters in parallel, leading to incorrect circuit diagrams and measurements.
    ❌ Weak Answer (Loses Marks):I connected the ammeter in parallel to measure the current through the resistor.
    Example improved answer:To measure the current through the resistor, the ammeter must be connected in series with the resistor so that the same current flows through both. A voltmeter is connected in parallel across the component to measure the potential difference without drawing significant current.
    Examiner Tip: Always check the placement of meters in circuit diagrams. Ammeters have very low resistance and must be in series; voltmeters have very high resistance and must be in parallel.
    Pitfall: When calculating total resistance in parallel circuits, students often add reciprocals incorrectly or forget to take the reciprocal of the sum.
    ❌ Weak Answer (Loses Marks):For two resistors in parallel, total resistance = R1 + R2.
    Example improved answer:For resistors in parallel, the reciprocal of the total resistance equals the sum of the reciprocals of each resistance: 1/R_total = 1/R1 + 1/R2. For two resistors, this simplifies to R_total = (R1 * R2) / (R1 + R2).
    Examiner Tip: Remember that the total resistance in parallel is always less than the smallest individual resistance. Practice with simple numbers to avoid reciprocal errors.
    Step-by-Step Worked Solutions

    Question: A battery of e.m.f. 12 V and internal resistance 0.5 Ω is connected to a 5 Ω resistor. Calculate: (a) the current in the circuit, (b) the terminal voltage of the battery, (c) the power dissipated in the 5 Ω resistor.

    1. 1.Step 1: Identify given values: e.m.f. (ε) = 12 V, internal resistance (r) = 0.5 Ω, external resistance (R) = 5 Ω.
    2. 2.Step 2: Use the circuit equation ε = I(R + r) to find current: I = ε / (R + r) = 12 / (5 + 0.5) = 12 / 5.5 = 2.18 A.
    3. 3.Step 3: Calculate terminal voltage: V = ε - Ir = 12 - (2.18 × 0.5) = 12 - 1.09 = 10.91 V.
    4. 4.Step 4: Calculate power in external resistor: P = I²R = (2.18)² × 5 = 4.75 × 5 = 23.8 W.
    Final Answer: (a) Current = 2.18 A, (b) Terminal voltage = 10.91 V, (c) Power = 23.8 W.

    Question: Three resistors of 4 Ω, 6 Ω, and 12 Ω are connected in parallel across a 24 V supply. Calculate: (a) the total resistance, (b) the current drawn from the supply, (c) the current through each resistor.

    1. 1.Step 1: For parallel resistors, use 1/R_total = 1/4 + 1/6 + 1/12.
    2. 2.Step 2: Compute the sum: 1/4 = 0.25, 1/6 = 0.1667, 1/12 = 0.0833, so 1/R_total = 0.5. Therefore R_total = 2 Ω.
    3. 3.Step 3: Use Ohm's law to find total current: I = V / R_total = 24 / 2 = 12 A.
    4. 4.Step 4: Since voltage is same across each branch, I1 = 24/4 = 6 A, I2 = 24/6 = 4 A, I3 = 24/12 = 2 A.
    Final Answer: (a) Total resistance = 2 Ω, (b) Total current = 12 A, (c) Currents: 6 A, 4 A, 2 A respectively.
    Active Recall Memory Test
    State Kirchhoff's two laws for electric circuits.
    Key Fact: Kirchhoff's first law: The sum of currents entering a junction equals the sum of currents leaving it. Kirchhoff's second law: The sum of e.m.f.s around a closed loop equals the sum of potential differences across each component.
    How does the total resistance of a parallel circuit compare to the smallest individual resistance?
    Key Fact: The total resistance is always less than the smallest individual resistance because there are multiple paths for current to flow.
    What is the difference between e.m.f. and terminal voltage?
    Key Fact: e.m.f. is the total energy supplied per unit charge by the battery, while terminal voltage is the potential difference across the battery terminals when current flows, reduced by the voltage drop due to internal resistance.
    Write the formula for power dissipated in a resistor in terms of current and resistance.
    Key Fact: P = I²R, where P is power in watts, I is current in amperes, and R is resistance in ohms.
    Frequently Asked Questions
    Why does the terminal voltage of a battery drop when it supplies current?
    A real battery has internal resistance. When current flows, some of the e.m.f. is used to overcome this internal resistance, causing a voltage drop (V = Ir). The terminal voltage is therefore less than the e.m.f. and decreases as current increases.
    What is the difference between series and parallel circuits?
    In a series circuit, components are connected end-to-end, so the same current flows through each, and the total resistance is the sum of individual resistances. In a parallel circuit, components are connected across the same two points, so the voltage is the same across each branch, and the total resistance is less than the smallest branch resistance.
    How do I calculate the total resistance of resistors in parallel?
    Use the reciprocal formula: 1/R_total = 1/R1 + 1/R2 + 1/R3 + ... For two resistors, you can also use the product over sum formula: R_total = (R1 × R2) / (R1 + R2).
    What is Kirchhoff's second law and how is it applied?
    Kirchhoff's second law states that around any closed loop in a circuit, the sum of the e.m.f.s equals the sum of the potential differences (voltage drops). It is a consequence of conservation of energy. To apply it, choose a direction around the loop, assign signs to voltages based on whether they are rises or drops, and set the sum equal to zero.
    Why is a voltmeter connected in parallel and an ammeter in series?
    A voltmeter measures the potential difference across a component, so it must be connected in parallel to experience the same voltage. It has very high resistance to avoid drawing current. An ammeter measures the current flowing through a component, so it must be in series to have the same current pass through it. It has very low resistance to not affect the circuit.
    What is the difference between e.m.f. and potential difference?
    e.m.f. (electromotive force) is the energy supplied per unit charge by a source, such as a battery, and is measured in volts. Potential difference is the energy transferred per unit charge between two points in a circuit, also in volts. e.m.f. is the maximum voltage a source can provide, while potential difference is what is actually measured across a component or the terminals of a source when current flows.