AQA · A-Level · Chemistry

    Course version: 7405 · Version from Sept 2016

    The trends in electronegativity and boiling point of the halogens.

    Full specification wording

    Trends in properties: The trends in electronegativity and boiling point of the halogens.

    Two trends that run in opposite directions.

    Checked against the AQA 7405 specification (opens in a new tab) on .

    • Point 1 of 7
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Two trends that run in opposite directions. Electronegativity falls from fluorine at 4.0 to iodine at 2.5: going down the group the atom has more shells, so the bonding pair of electrons lies further from the nucleus and is screened by more inner electrons, and the attraction for it weakens despite the larger nuclear charge. Boiling point rises: F₂ and Cl₂ are gases, Br₂ is a red-brown liquid and I₂ is a grey-black solid that sublimes to a purple vapour. The halogens are simple molecular, so boiling only separates molecules and the covalent bond inside each molecule is untouched. Each step down the group adds electrons, so the electron cloud is larger and more easily distorted, the induced dipoles are bigger, and the van der Waals forces between molecules take more energy to overcome.

    What earns the marks

    • Electronegativity decreasing down the group.
    • Explaining that by increasing atomic radius and shielding, so the nucleus attracts the shared pair less strongly.
    • Boiling point increasing down the group.
    • Stating that the halogens are simple molecular and that van der Waals forces are overcome on boiling.
    • Linking stronger van der Waals forces to more electrons and a more polarisable electron cloud.

    Common mistakes and how to put them right

    • Saying the covalent bond within the molecule is broken when a halogen boils.

    • Explaining the boiling point trend by relative molecular mass alone, with no mention of electrons or polarisability.

    • Claiming electronegativity increases down the group because nuclear charge increases.

    • Calling van der Waals forces 'bonds'.

    • Describing iodine vapour as black rather than purple.

    Exam tips

    • Always say what is overcome on boiling, because 'the forces get stronger' with no name attached scores nothing.
    • Learn the colours and states of chlorine, bromine and iodine as a set; they are asked for directly.

    Try the lesson

    The start of the Trends in properties: The trends in electronegativity and boiling point of the halogens. lesson, made from checked teaching notes for this specification point.

    Have a go first

    What happens to the boiling point of the halogens as you go down Group 7?

    Listen

    Two trends that run in opposite directions. Electronegativity falls from fluorine at 4.0 to iodine at 2.5: going down the group the atom has more shells, so the bonding pair of electrons lies further from the nucleus and is screened by more inner electrons, and the attraction for it weakens despite the larger nuclear charge. Boiling point rises: F₂ and Cl₂ are gases, Br₂ is a red-brown liquid and I₂ is a grey-black solid that sublimes to a purple vapour. The halogens are simple molecular, so boiling only separates molecules and the covalent bond inside each molecule is untouched. Each step down the group adds electrons, so the electron cloud is larger and more easily distorted, the induced dipoles are bigger, and the van der Waals forces between molecules take more energy to overcome. A strong answer earns marks for these points. electronegativity decreasing down the group. explaining that by increasing atomic radius and shielding, so the nucleus attracts the shared pair less strongly. boiling point increasing down the group. stating that the halogens are simple molecular and that van der Waals forces are overcome on boiling. Exam tip: Always say what is overcome on boiling, because 'the forces get stronger' with no name attached scores nothing.

    See it

    A flowchart starting from a single node labelled 'Going down the group', which branches into two paths. The first path leads to a node saying more shells mean the bonding pair is further from the nucleus and screened by more inner electrons, then to a node saying electronegativity falls from fluorine at 4.0 to iodine at 2.5. The second path leads to a node saying more electrons give a larger, more easily distorted electron cloud, then to bigger induced dipoles, then to stronger van der Waals forces between molecules, and finally to a node saying boiling point rises, with F2 and Cl2 as gases, Br2 a red-brown liquid and I2 a grey-black solid.
    It shows how going down the halogen group lowers electronegativity while raising boiling point through stronger van der Waals forces.

    Key words

    Say what each word means before you turn the card.

    electronegativity down a group

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    van der Waals forces

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    simple molecular structure

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    colours and states

    Try answering aloud or in your head before turning the card.

    See every definition
    electronegativity down a group
    Falls from fluorine at 4.0 to iodine at 2.5, because the atom has more shells so the bonding pair lies further from the nucleus and is screened by more inner electrons.
    van der Waals forces
    Forces between molecules that take more energy to overcome as each step down the group adds electrons, making the electron cloud larger and more easily distorted and the induced dipoles bigger.
    simple molecular structure
    The halogens are simple molecular, so boiling only separates molecules and the covalent bond inside each molecule is untouched.
    colours and states
    F₂ and Cl₂ are gases, Br₂ is a red-brown liquid and I₂ is a grey-black solid that sublimes to a purple vapour.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart starting from a single node labelled 'Going down the group', which branches into two paths. The first path leads to a node saying more shells mean the bonding pair is further from the nucleus and screened by more inner electrons, then to a node saying electronegativity falls from fluorine at 4.0 to iodine at 2.5. The second path leads to a node saying more electrons give a larger, more easily distorted electron cloud, then to bigger induced dipoles, then to stronger van der Waals forces between molecules, and finally to a node saying boiling point rises, with F2 and Cl2 as gases, Br2 a red-brown liquid and I2 a grey-black solid.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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