AQA · GCSE · Chemistry

    Course version: 8462 · Version from Sept 2018

    For example: ethanediol and hexanedioic acid polymerise to produce a…

    Full specification wording

    Condensation polymerisation (HT only): For example: ethanediol and hexanedioic acid polymerise to produce a polyester: Students should be able to explain the basic principles of condensation polymerisation by reference to the functional groups in the monomers and the repeating units in the polymers.

    Ethanediol, HO–CH₂–CH₂–OH, has two alcohol groups.

    Checked against the AQA 8462 specification (opens in a new tab) on .

    • Point 4 of 4
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Ethanediol, HO–CH₂–CH₂–OH, has two alcohol groups. Hexanedioic acid, HOOC–(CH₂)₄–COOH, has two carboxylic acid groups. When they react, an alcohol group on ethanediol reacts with a carboxylic acid group on hexanedioic acid to form an ester link, releasing water. Because both monomers have two functional groups, the process repeats and builds a polyester chain. The repeating unit shows the two monomer residues joined by ester links, with the atoms of the eliminated water molecules missing. To explain the principles, identify the functional groups in each monomer, state the link formed, and show how the repeating unit reflects the loss of water at each join.

    What earns the marks

    • Ethanediol contains two alcohol groups and hexanedioic acid contains two carboxylic acid groups.
    • An alcohol group reacts with a carboxylic acid group to form an ester link.
    • Water is eliminated at each ester link formed.
    • The repeating unit shows both monomer residues joined by ester links.
    • The repeating unit contains fewer atoms than the monomers because water has been lost.
    • The two functional groups on each monomer allow the chain to continue growing.

    Common mistakes and how to put them right

    • Drawing the repeating unit with the water molecule still present.

      Put it right by removing the atoms of water at each ester link.

    • Showing only one functional group reacting.

      Put it right by showing both ends of each monomer able to react.

    • Labelling the link as an amide link.

      Put it right by naming it an ester link when alcohol and carboxylic acid groups react.

    Exam tips

    • Identify the functional groups in each monomer before drawing the repeating unit.
    • Show the ester link clearly and account for the eliminated water.
    • Use the monomer structures to check that the repeating unit has the correct number of carbon atoms.

    Try the lesson

    The start of the Condensation polymerisation (HT only): For example: ethanediol and hexanedioic acid polymerise to produce a polyester: Students should be able to explain the basic principles of condensation polymerisation by reference to the functional groups in the monomers and the repeating units in the polymers. lesson, made from checked teaching notes for this specification point.

    Have a go first

    Ethanediol and hexanedioic acid react together in a condensation polymerisation. Which functional groups do these two monomers contain?

    Listen

    Ethanediol, HO–CH₂–CH₂–OH, has two alcohol groups. Hexanedioic acid, HOOC–(CH₂)₄–COOH, has two carboxylic acid groups. When they react, an alcohol group on ethanediol reacts with a carboxylic acid group on hexanedioic acid to form an ester link, releasing water. Because both monomers have two functional groups, the process repeats and builds a polyester chain. The repeating unit shows the two monomer residues joined by ester links, with the atoms of the eliminated water molecules missing. To explain the principles, identify the functional groups in each monomer, state the link formed, and show how the repeating unit reflects the loss of water at each join. A strong answer earns marks for these points. Ethanediol contains two alcohol groups and hexanedioic acid contains two carboxylic acid groups. An alcohol group reacts with a carboxylic acid group to form an ester link. Water is eliminated at each ester link formed. The repeating unit shows both monomer residues joined by ester links. A common slip: Drawing the repeating unit with the water molecule still present. Instead, removing the atoms of water at each ester link. Exam tip: Identify the functional groups in each monomer before drawing the repeating unit.

    See it

    A top-down flowchart. Two nodes at the top: 'Ethanediol: two alcohol groups' and 'Hexanedioic acid: two carboxylic acid groups'. Both arrows lead to 'Alcohol group reacts with carboxylic acid group', which leads to 'Ester link formed', then to 'Water eliminated at each ester link', then to 'Process repeats because each monomer has two functional groups', then to 'Polyester chain built', and finally to 'Repeating unit: both monomer residues joined by ester links, with atoms of eliminated water missing'.
    Shows how ethanediol and hexanedioic acid react to form ester links, eliminate water and build a polyester repeating unit.

    Key words

    Say what each word means before you turn the card.

    Ester links

    Try answering aloud or in your head before turning the card.

    Functional groups

    Try answering aloud or in your head before turning the card.

    Repeating units

    Try answering aloud or in your head before turning the card.

    Condensation polymerisation

    Try answering aloud or in your head before turning the card.

    See every definition
    Ester links
    The link formed when an alcohol group reacts with a carboxylic acid group, with water eliminated at each link formed.
    Functional groups
    The groups in the monomers, such as the alcohol groups and carboxylic acid groups, whose reaction allows the chain to continue growing.
    Repeating units
    The part of the polymer showing both monomer residues joined by ester links, with the atoms of the eliminated water molecules missing.
    Condensation polymerisation
    The process in which monomers react so that water is eliminated at each ester link formed and a polyester chain is built.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. Two nodes at the top: 'Ethanediol: two alcohol groups' and 'Hexanedioic acid: two carboxylic acid groups'. Both arrows lead to 'Alcohol group reacts with carboxylic acid group', which leads to 'Ester link formed', then to 'Water eliminated at each ester link', then to 'Process repeats because each monomer has two functional groups', then to 'Polyester chain built', and finally to 'Repeating unit: both monomer residues joined by ester links, with atoms of eliminated water missing'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

    There is more to this lesson

    The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.

    Carry on with the full lesson

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge

    Test your understanding of Condensation polymerisation (HT only): For example: ethanediol and hexanedioic acid polymerise to produce a polyester: Students should be able to explain the basic principles of condensation polymerisation by reference to the functional groups in the monomers and the repeating units in the polymers.

    Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.

    Take topic quiz

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge