AQA · GCSE · Combined Science
Course version: 8464 · Version from Sept 2018
Forces and elasticity: calculate a spring constant in linear cases
In the linear region of a force–extension graph, force and extension are directly proportional, so the spring constant k is the constant ratio F ÷ e.
Checked against the AQA 8464 specification (opens in a new tab) on .
- Point 13 of 19
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
In the linear region of a force–extension graph, force and extension are directly proportional, so the spring constant k is the constant ratio F ÷ e. Rearranging F = k e gives k = F ÷ e. For example, if a 6.0 N force stretches a spring by 0.030 m, then k = 6.0 N ÷ 0.030 m = 200 N/m. The gradient of the straight-line section of a force–extension graph also equals k, so a steeper line means a stiffer spring. Convert extension to metres before dividing, and remember that extension is the increase in length, not the total length. The unit of k is newtons per metre (N/m). This calculation applies only while the graph is a straight line through the origin; beyond the limit of proportionality the relationship is non-linear and k is not constant.
What earns the marks
- State the relationship F = k e and rearrange it correctly to k = F ÷ e before substituting values.
- Identify the extension as the increase in length, calculated by subtracting the original length from the stretched length.
- Convert all lengths from centimetres or millimetres into metres before dividing force by extension.
- Substitute the force in newtons and the extension in metres, then evaluate k and give the unit N/m.
- Recognise that the gradient of the straight-line section of a force–extension graph is numerically equal to the spring constant.
- Check that the value of k is calculated only from data in the linear region, where force and extension are directly proportional.
Common mistakes and how to put them right
Using the total stretched length instead of the extension.
Put it right by subtracting the original length first.
Forgetting to convert centimetres to metres.
Put it right by dividing the length in cm by 100.
Dividing extension by force instead of force by extension.
Put it right by using k = F ÷ e.
Exam tips
- Write the equation, then the rearrangement, then the substitution with units, so the examiner can follow your method even if the final value is wrong.
- Check whether the question gives total length or extension; if it gives total length, calculate the extension before using k = F ÷ e.
- Give the unit N/m with your answer, and check that a stiffer spring has a larger value of k than a less stiff one.
Try the lesson
The start of the Forces and elasticity: calculate a spring constant in linear cases lesson, made from checked teaching notes for this specification point.
Have a go first
A force of 12 N is applied to a spring and it stretches by 0.04 m. Calculate the spring constant of the spring.
Listen
In the linear region of a force–extension graph, force and extension are directly proportional, so the spring constant k is the constant ratio F ÷ e. Rearranging F = k e gives k = F ÷ e. For example, if a 6.0 N force stretches a spring by 0.030 m, then k = 6.0 N ÷ 0.030 m = 200 N/m. The gradient of the straight-line section of a force–extension graph also equals k, so a steeper line means a stiffer spring. Convert extension to metres before dividing, and remember that extension is the increase in length, not the total length. The unit of k is newtons per metre (N/m). This calculation applies only while the graph is a straight line through the origin; beyond the limit of proportionality the relationship is non-linear and k is not constant. A strong answer earns marks for these points. State the relationship F = k e and rearrange it correctly to k = F ÷ e before substituting values. Identify the extension as the increase in length, calculated by subtracting the original length from the stretched length. Convert all lengths from centimetres or millimetres into metres before dividing force by extension. Substitute the force in newtons and the extension in metres, then evaluate k and give the unit N/m. A common slip: Using the total stretched length instead of the extension: the error gives too small a value of k. Instead, subtracting the original length first. Exam tip: Write the equation, then the rearrangement, then the substitution with units, so the examiner can follow your method even if the final value is wrong.
See it
Put it in order
Put these steps in the order they happen.
- 1. Convert lengths to metres
- 2. Gradient of straight-line section also equals k
- 3. Substitute F in newtons and e in metres
- 4. Force F and extension e in the linear region
- 5. F = k e
- 6. Evaluate k and give unit N/m
- 7. Rearrange to k = F ÷ e
- 8. Identify extension as increase in length
Key words
Say what each word means before you turn the card.
spring constant
Try answering aloud or in your head before turning the card.
extension
Try answering aloud or in your head before turning the card.
gradient
Try answering aloud or in your head before turning the card.
linear region
Try answering aloud or in your head before turning the card.
See every definition
- spring constant
- The constant ratio F ÷ e in the linear region, where force and extension are directly proportional, with unit newtons per metre (N/m).
- extension
- The increase in length, not the total length, calculated by subtracting the original length from the stretched length.
- gradient
- Of the straight-line section of a force–extension graph, it is numerically equal to the spring constant, so a steeper line means a stiffer spring.
- linear region
- The part of a force–extension graph that is a straight line through the origin, where force and extension are directly proportional and k is constant.
Label the diagram
Some boxes have lost their names. Pick the right name for each number.
1Box 1
2Box 2
3Box 3
There is more to this lesson
The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.
A week of Premium from your first lesson · Then the free plan continues · No card, no charge
Test your understanding of Forces and elasticity: calculate a spring constant in linear cases
Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.
A week of Premium from your first lesson · Then the free plan continues · No card, no charge