Constructions

    Constructions and Loci is one of the most mark-rich precision topics in OCR Further Mathematics, demanding not just accurate drawing but a clear demonstration of method through visible construction arcs. Candidates who master the four fundamental loci and learn to combine them algebraically — interpreting strict versus inclusive inequalities — will find this topic a reliable source of full marks. The examiner rewards method as much as accuracy, making it a topic where disciplined technique pays dividends.

    8
    Min Read
    5
    Examples
    6
    Questions
    9
    Key Terms
    🎙 Podcast Episode
    Constructions
    5:53
    0:00-5:53

    Study Notes

    Overview

    Constructions and Loci — OCR GCSE Further Mathematics Study Guide

    Constructions and Loci sits at the intersection of geometry and algebra in the OCR Level 2 Further Mathematics specification (Section 4.6). Unlike standard GCSE, this course demands a higher level of rigour: candidates must not only produce accurate geometric constructions but must also interpret and combine multiple locus conditions — often expressed as algebraic inequalities — to define precise regions on a diagram. The topic draws on compass-and-ruler techniques that date back to Euclid, yet the OCR Further Mathematics examination applies them in sophisticated, multi-step contexts that reward careful reading and methodical working.

    In the exam, questions on this topic are typically worth between 3 and 6 marks and will almost always carry the command word 'Construct' or 'Show the region'. These command words carry specific expectations: 'Construct' requires visible construction arcs, and 'Show the region' requires correct shading with attention to whether boundary lines are solid or dashed. Understanding these expectations is the difference between full marks and a frustrating loss of method marks.

    This topic connects directly to coordinate geometry (the equations of loci can be derived algebraically), to inequalities (the shading of regions mirrors linear programming), and to circle theorems (the perpendicular bisector of a chord passes through the centre). Mastering constructions therefore strengthens your performance across the entire specification.


    Key Concepts

    Concept 1: What is a Locus?

    A locus (plural: loci) is the complete set of all points that satisfy a given geometric condition. Think of it as the 'path' or 'region' traced out by a point that moves according to a rule. The word comes from the Latin for 'place', and that is exactly what it describes: every place a point can be, given a constraint.

    For example, if you are told that a point P is always exactly 3 cm from a fixed point O, then P can be anywhere on a circle of radius 3 cm centred on O. That circle is the locus. The power of loci is that a single geometric rule generates an entire shape.

    Why does this work? Because every point on a circle is, by definition, equidistant from the centre. The locus rule and the geometric shape are two descriptions of the same mathematical truth.


    Concept 2: The Four Fundamental Loci

    Candidates must be fluent in constructing all four of the following:

    Locus RuleResulting ShapeConstruction Method
    Fixed distance from a pointCircleSet compass to radius; draw full circle
    Equidistant from two pointsPerpendicular bisectorIntersecting arcs from each point
    Equidistant from two linesAngle bisectorArcs from vertex, then arcs from intersections
    Fixed distance from a lineRunning track (stadium) shapeParallel lines + semicircular ends

    How to construct the perpendicular bisector — the most frequently examined construction in OCR Further Mathematics

    The Perpendicular Bisector in Detail: This is the most frequently examined construction. Given two points A and B, the perpendicular bisector is the unique line where every point is exactly the same distance from A as it is from B. The construction requires opening the compass to a radius greater than half of AB, drawing arcs from A and B that intersect above and below the line, and connecting those intersection points. The resulting line is perpendicular to AB and passes through its midpoint.

    The Angle Bisector in Detail: Given two intersecting lines meeting at a vertex V, the angle bisector is the ray from V that cuts the angle exactly in half. Place the compass on V and draw an arc crossing both lines. From each crossing point, draw equal arcs into the interior of the angle. Connect V to where these arcs meet.


    Concept 3: Combining Loci to Define Regions

    This is where OCR Further Mathematics raises the difficulty above standard GCSE. A question will present multiple locus conditions simultaneously, and candidates must identify the region that satisfies all of them at once.

    Combining multiple loci to define a required region — the core skill in OCR Further Mathematics Constructions

    The process is always the same:

    1. Construct each locus boundary separately.
    2. Identify which side of each boundary satisfies the given condition.
    3. Shade the intersection — the area that satisfies all conditions simultaneously.

    Worked Strategy: Suppose the conditions are: (i) distance from point A is less than 4 cm, and (ii) closer to B than to C. Construct the circle of radius 4 cm centred on A (condition i) and the perpendicular bisector of BC (condition ii). The required region is inside the circle AND on the B-side of the perpendicular bisector. Shade where these two regions overlap.


    Concept 4: Strict vs Inclusive Inequalities — Dashed vs Solid Lines

    This is a mark-scoring detail that many candidates overlook. The type of boundary line signals whether the boundary itself is included in the region:

    Inequality SymbolMeaningBoundary Line Style
    < or > (strict)Boundary NOT includedDashed line
    ≤ or ≥ (inclusive)Boundary IS includedSolid line

    This mirrors exactly the convention used in graphical linear inequalities. An examiner's mark scheme will explicitly credit candidates who correctly distinguish between dashed and solid boundaries. Drawing a solid line where a dashed one is required will cost a mark.

    Analogy: Think of a nightclub with a height restriction. 'Taller than 1.8 m' (strict, >) means someone who is exactly 1.8 m cannot enter — dashed boundary. 'At least 1.8 m' (inclusive, ≥) means exactly 1.8 m is fine — solid boundary.


    Concept 5: Accuracy and the ±2mm Tolerance

    The OCR mark scheme awards accuracy marks only when constructions fall within ±2 mm of the correct position. This means:

    • Your compass pencil must be sharp. A thick pencil line can be 1–2 mm wide on its own, consuming your entire tolerance allowance.
    • The metal compass point must be placed precisely on the given point, not approximately.
    • For circles, check the radius carefully against the scale of the diagram before drawing.

    A common trap is a diagram drawn to a scale (e.g., 1 cm represents 2 m). If you are asked to construct a circle representing a distance of 6 m, you must draw a circle of radius 3 cm on the diagram. Failing to apply the scale results in a circle of the wrong size — and no accuracy mark.


    Mathematical Relationships

    The loci studied here have precise algebraic equivalents, which can be tested in the Further Mathematics context:

    • Circle (locus equidistant from point (a, b) at distance r): (x - a)^2 + (y - b)^2 = r^2Must memorise
    • Perpendicular bisector of two points (x_1, y_1) and (x_2, y_2): found by setting distances equal and simplifying — derived from the distance formula — Must memorise method
    • Distance formula (used to verify locus conditions algebraically): d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}Must memoriseNote: The circle equation is given on the OCR formula sheet in some forms, but candidates should be comfortable deriving and applying it independently.

    Practical Applications

    Constructions and loci appear in real-world planning and design contexts that examiners sometimes use as question settings:

    • Mobile phone mast coverage: The area within signal range of a mast is a circle (locus equidistant from a point). Overlapping coverage areas model the intersection of loci.
    • Equidistant boundaries: Property boundaries, electoral ward boundaries, and Voronoi diagrams in geography all use perpendicular bisectors to define regions equidistant from two locations.
    • Safety exclusion zones: A fixed distance from a hazardous line (e.g., a railway) produces the 'running track' locus shape.
    • Navigation: A ship maintaining a fixed distance from a coastline traces a locus parallel to that coast.

    Visual Resources

    2 diagrams and illustrations

    How to construct the perpendicular bisector — the most frequently examined construction in OCR Further Mathematics
    How to construct the perpendicular bisector — the most frequently examined construction in OCR Further Mathematics
    Combining multiple loci to define a required region — the core skill in OCR Further Mathematics Constructions
    Combining multiple loci to define a required region — the core skill in OCR Further Mathematics Constructions

    Interactive Diagrams

    3 interactive diagrams to visualise key concepts

    OneTwo or moreStrict: < or >Inclusive: ≤ or ≥YesNoRead the question carefullyHow many locus conditions?Construct single locusConstruct each locus separatelyStrict or inclusive inequality?Draw DASHED boundaryDraw SOLID boundaryIdentify required regionTest a point inside the regionDoes it satisfy ALL conditions?Shade the region — DONERe-check which side to shade

    Decision flowchart for answering a Constructions and Loci exam question — follow this process for every question to ensure full marks.

    Two POINTSTwo LINESA POINTA LINELocus ConditionEquidistant from...Perpendicular BisectorAngle BisectorFixed distance from...CircleRunning Track ShapeConstruction: intersecting arcs from each pointConstruction: arc from vertex, then arcs from intersectionsConstruction: compass set to radius, draw full circleConstruction: parallel lines + semicircular ends

    Concept map linking each locus condition to its resulting shape and construction method — use this to quickly identify which construction a question requires.

    Perpendicular Bisector of ABMidpoint of AB90° angle with ABEvery point equidistant from A and BCircumcentre of triangle: intersection of 3 perpendicular bisectorsVoronoi diagrams: boundaries between regionsAlgebraic form: derived from distance formulaSet distance from A = distance from B and simplify

    Synoptic connections from the perpendicular bisector to other areas of the specification and beyond — examiners reward candidates who demonstrate cross-topic understanding.

    Worked Examples

    5 detailed examples with solutions and examiner commentary

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    Mark two points, A and B, 6 cm apart on plain paper. Construct the perpendicular bisector of AB. [2 marks]

    2 marks
    foundation

    Hint: Open your compass to more than 3 cm. Draw arcs from both A and B on both sides of the line.

    Q2

    On a diagram, point P is at the origin (0, 0). Shade the region where the distance from P is greater than or equal to 2 units and less than 5 units. [3 marks]

    3 marks
    standard

    Hint: You need two circles. Think carefully about which boundary is dashed and which is solid.

    Q3

    A diagram (scale 1 cm : 5 m) shows a rectangular park ABCD where AB = 8 cm and BC = 6 cm. A path is to be built in the region of the park that is: (i) closer to AD than to BC, and (ii) within 20 m of corner A. Construct both loci and shade the required region. [4 marks]

    4 marks
    standard

    Hint: Apply the scale first: 20 m = 4 cm on the diagram. The midline between AD and BC is a line parallel to both, halfway across the park.

    Q4

    Two points, A(1, 2) and B(5, 6), are plotted on a coordinate grid. Without using a ruler to measure, show algebraically that the point (3, 4) lies on the perpendicular bisector of AB. [3 marks]

    3 marks
    challenging

    Hint: Use the distance formula. A point is on the perpendicular bisector of AB if and only if it is equidistant from A and B.

    Q5

    Construct the angle bisector of angle BAC in a given triangle ABC, where angle BAC = 80°. Hence, describe the locus of points inside the triangle that are equidistant from AB and AC. [3 marks]

    3 marks
    standard

    Hint: The angle bisector construction requires three sets of arcs: one from the vertex, then one from each intersection point on the arms of the angle.

    Q6

    A mobile phone mast M is located at point (4, 3) on a coordinate grid (scale: 1 unit = 1 km). The mast has a signal range of 5 km. A second mast N is at (10, 3) with a range of 3 km. Shade the region where a phone can receive signal from mast M but NOT from mast N. [4 marks]

    4 marks
    challenging

    Hint: Draw two circles. The required region is inside circle M but outside circle N.

    Key Terms

    Essential vocabulary to know

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