AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Λ Rayleigh criterion, θ ≈ D Collecting power is proportional to diameter .

    Full specification wording

    Advantages of large diameter telescopes (A-level only): λ Rayleigh criterion, θ ≈ D Collecting power is proportional to diameter .

    The Rayleigh criterion gives the minimum angular resolution θ of a telescope as θ ≈ λ ÷ D, where λ is the wavelength of the radiation and D is the diameter of the objective aperture.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 2 of 4
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The Rayleigh criterion gives the minimum angular resolution θ of a telescope as θ ≈ λ ÷ D, where λ is the wavelength of the radiation and D is the diameter of the objective aperture. The angle θ is in radians. Because the ratio is dimensionless, λ and D must simply be in the same units, not necessarily metres. A larger D produces a smaller θ, meaning finer detail can be resolved. Separately, the collecting power of a telescope is proportional to the area of its objective, so it is proportional to D². A larger diameter gathers more radiation per second, allowing fainter objects to be detected.

    For example: Doubling D halves θ and quadruples the collecting power.

    What earns the marks

    • The Rayleigh criterion is θ ≈ λ ÷ D, with θ in radians, λ the wavelength and D the objective diameter.
    • A smaller θ corresponds to better angular resolution, separating closer sources.
    • Collecting power is proportional to the area of the objective, which is proportional to D².
    • Doubling the diameter halves the minimum resolvable angle and increases collecting power by a factor of four.

    Common mistakes and how to put them right

    • Writing collecting power as proportional to D rather than D².

      Put it right: The objective is a circular area, so collecting power ∝ D².

    • Mixing units by substituting λ in nanometres while D is in metres.

      Put it right: Convert both to the same unit so the ratio is dimensionless.

    • Confusing resolution with collecting power.

      Put it right: Treat θ ≈ λ ÷ D as the resolution relationship and collecting power ∝ D² as the light-gathering relationship.

    Exam tips

    • Quote θ ≈ λ ÷ D and collecting power ∝ D² explicitly before using them.
    • For comparison questions, calculate the ratio of diameters and use it to find both the change in θ and the change in collecting power.

    Try the lesson

    The start of the Advantages of large diameter telescopes (A-level only): λ Rayleigh criterion, θ ≈ D Collecting power is proportional to diameter . lesson, made from checked teaching notes for this specification point.

    Have a go first

    Which statement correctly describes how the collecting power of a telescope depends on its objective diameter D?

    Listen

    The Rayleigh criterion gives the minimum angular resolution θ of a telescope as θ ≈ λ ÷ D, where λ is the wavelength of the radiation and D is the diameter of the objective aperture. The angle θ is in radians. Because the ratio is dimensionless, λ and D must simply be in the same units, not necessarily metres. A larger D produces a smaller θ, meaning finer detail can be resolved. Separately, the collecting power of a telescope is proportional to the area of its objective, so it is proportional to D². A larger diameter gathers more radiation per second, allowing fainter objects to be detected. For example, doubling D halves θ and quadruples the collecting power. A strong answer earns marks for these points. The Rayleigh criterion is θ ≈ λ ÷ D, with θ in radians, λ the wavelength and D the objective diameter. A smaller θ corresponds to better angular resolution, separating closer sources. Collecting power is proportional to the area of the objective, which is proportional to D². Doubling the diameter halves the minimum resolvable angle and increases collecting power by a factor of four. Exam tip: Quote θ ≈ λ ÷ D and collecting power ∝ D² explicitly before using them.

    See it

    A top-down flowchart. At the top, a node labelled Objective diameter D branches into two paths. The left path goes to Rayleigh criterion: θ ≈ λ ÷ D, then to Larger D gives smaller θ, then to Finer detail resolved. The right path goes to Collecting power ∝ D², then to Larger D gathers more radiation per second, then to Fainter objects detected. A separate node labelled Doubling D branches into two outcomes: θ halved and Collecting power quadrupled.
    It shows how the objective diameter D affects both angular resolution through θ ≈ λ ÷ D and collecting power through D², including the effect of doubling D.

    Key words

    Say what each word means before you turn the card.

    Rayleigh criterion

    Try answering aloud or in your head before turning the card.

    Collecting power

    Try answering aloud or in your head before turning the card.

    Angular resolution

    Try answering aloud or in your head before turning the card.

    See every definition
    Rayleigh criterion
    Gives the minimum angular resolution θ of a telescope as θ ≈ λ ÷ D, where λ is the wavelength and D is the diameter of the objective aperture.
    Collecting power
    Proportional to the area of the objective, so it is proportional to D², and a larger diameter gathers more radiation per second.
    Angular resolution
    Given by θ ≈ λ ÷ D in radians, and a larger D produces a smaller θ, meaning finer detail can be resolved.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. At the top, a node labelled Objective diameter D branches into two paths. The left path goes to Rayleigh criterion: θ ≈ λ ÷ D, then to Larger D gives smaller θ, then to Finer detail resolved. The right path goes to Collecting power ∝ D², then to Larger D gathers more radiation per second, then to Fainter objects detected. A separate node labelled Doubling D branches into two outcomes: θ halved and Collecting power quadrupled.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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