AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Angular impulse = change in angular momentum; T ∆t = ∆ Iω where T is…

    Full specification wording

    Angular momentum (A-level only): Angular impulse = change in angular momentum; T ∆t = ∆ Iω where T is constant.

    Angular impulse is the rotational analogue of linear impulse.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 2 of 3
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Angular impulse is the rotational analogue of linear impulse. When a constant torque T acts for a time ∆t, the angular impulse is T ∆t and it equals the change in angular momentum, ∆(Iω). This follows from Newton's second law in rotational form, T = ∆(Iω)/∆t, rearranged to T ∆t = ∆(Iω). If I is constant, the change is I∆ω; if I changes, the change is ∆(Iω) as a whole. For example, a flywheel with I = 0.50 kg m² accelerated from rest to 12 rad s⁻¹ by a constant torque of 3.0 N m takes ∆t = I∆ω/T = (0.50 × 12)/3.0 = 2.0 s. To solve problems, identify the torque, the time interval, and the initial and final angular momenta, then apply T ∆t = ∆(Iω) with consistent signs.

    What earns the marks

    • State that angular impulse is the product of torque and the time for which it acts, with units N m s.
    • Apply the relationship T ∆t = ∆(Iω) for a constant torque, recognising that ∆(Iω) may involve changes in I, ω, or both.
    • Rearrange the equation to find torque, time interval, or change in angular momentum as required.
    • Use consistent sign conventions for torque and angular momentum about the chosen axis.
    • Link the equation to Newton's second law in rotational form, T = ∆(Iω)/∆t, to justify why angular impulse equals the change in angular momentum.
    • Calculate ∆ω from initial and final angular velocities in rad s⁻¹, converting units where necessary.

    Common mistakes and how to put them right

    • Confusing angular impulse with linear impulse.

      Put it right by using torque T and angular momentum Iω rather than force F and linear momentum mv.

    • Assuming T ∆t = I∆ω always, even when I changes.

      Put it right by writing the change as ∆(Iω) and evaluating initial and final values separately.

    • Forgetting that torque must be constant for the simple form T ∆t = ∆(Iω).

      Put it right by checking the question states or implies a constant torque.

    Exam tips

    • Show the substitution into T ∆t = ∆(Iω) with units, so the examiner can follow the calculation and check the final unit.
    • If the torque is not constant, do not use T ∆t directly; instead consider the area under a torque–time graph or use the average torque.
    • Keep angular velocities in rad s⁻¹ and torques in N m throughout to avoid unit conversion errors.

    Try the lesson

    The start of the Angular momentum (A-level only): Angular impulse = change in angular momentum; T ∆t = ∆ Iω where T is constant. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A constant torque of 6.0 N m acts on a wheel for 2.0 s. What is the angular impulse delivered to the wheel?

    Listen

    Angular impulse is the rotational analogue of linear impulse. When a constant torque T acts for a time ∆t, the angular impulse is T ∆t and it equals the change in angular momentum, ∆(Iω). This follows from Newton's second law in rotational form, T = ∆(Iω)/∆t, rearranged to T ∆t = ∆(Iω). If I is constant, the change is I∆ω; if I changes, the change is ∆(Iω) as a whole. For example, a flywheel with I = 0.50 kg m² accelerated from rest to 12 rad s⁻¹ by a constant torque of 3.0 N m takes ∆t = I∆ω/T = (0.50 × 12)/3.0 = 2.0 s. To solve problems, identify the torque, the time interval, and the initial and final angular momenta, then apply T ∆t = ∆(Iω) with consistent signs. A strong answer earns marks for these points. State that angular impulse is the product of torque and the time for which it acts, with units N m s. Apply the relationship T ∆t = ∆(Iω) for a constant torque, recognising that ∆(Iω) may involve changes in I, ω, or both. Rearrange the equation to find torque, time interval, or change in angular momentum as required. Use consistent sign conventions for torque and angular momentum about the chosen axis. A common slip: Confusing angular impulse with linear impulse. Instead, using torque T and angular momentum Iω rather than force F and linear momentum mv. Exam tip: Show the substitution into T ∆t = ∆(Iω) with units, so the examiner can follow the calculation and check the final unit.

    See it

    A top-down flowchart. The first box says a constant torque T acts for time ∆t. An arrow leads to a box stating angular impulse equals T ∆t, with units N m s. An arrow leads to a box saying this equals the change in angular momentum ∆(Iω). An arrow leads to the equation T ∆t = ∆(Iω). From this equation three arrows branch out: one to a box saying that if I is constant the change is I∆ω; one to a box saying that if I changes the change is ∆(Iω) as a whole; and one to a box saying the equation is rearranged from Newton's second law in rotational form, T = ∆(Iω)/∆t.
    It shows that a constant torque acting over a time interval gives an angular impulse equal to the change in angular momentum, with the two cases for constant and changing moment of inertia.

    Key words

    Say what each word means before you turn the card.

    Angular impulse

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    Newton's second law for rotation

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    Change in angular momentum

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    See every definition
    Angular impulse
    The product of torque and the time for which it acts, with units N m s.
    Newton's second law for rotation
    Written as T = ∆(Iω)/∆t, and rearranged to T ∆t = ∆(Iω).
    Change in angular momentum
    Written as ∆(Iω), which may involve changes in I, ω, or both.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first box says a constant torque T acts for time ∆t. An arrow leads to a box stating angular impulse equals T ∆t, with units N m s. An arrow leads to a box saying this equals the change in angular momentum ∆(Iω). An arrow leads to the equation T ∆t = ∆(Iω). From this equation three arrows branch out: one to a box saying that if I is constant the change is I∆ω; one to a box saying that if I changes the change is ∆(Iω) as a whole; and one to a box saying the equation is rearranged from Newton's second law in rotational form, T = ∆(Iω)/∆t.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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