AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Angular momentum = Iω Conservation of angular momentum.

    Full specification wording

    Angular momentum (A-level only): angular momentum = Iω Conservation of angular momentum.

    Angular momentum is the rotational analogue of linear momentum.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 1 of 3
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Angular momentum is the rotational analogue of linear momentum. For a rigid body rotating about a fixed axis, it equals the product of moment of inertia I and angular velocity ω, so L = Iω. I depends on mass distribution about the axis; ω is the angular velocity in rad s⁻¹. Conservation of angular momentum states that if the resultant external torque on a system is zero, its total angular momentum remains constant. A skater pulling in their arms reduces I, so ω increases to keep Iω unchanged. Similarly, a planet in an elliptical orbit moves faster when closer to the Sun because its moment of inertia about the Sun is smaller. To solve problems, identify the axis, calculate I for the given shape, convert ω to rad s⁻¹, then apply L = Iω before and after any change.

    What earns the marks

    • State that angular momentum L is the product of moment of inertia I and angular velocity ω, with L = Iω and units kg m² rad s⁻¹ or kg m² s⁻¹.
    • Explain that moment of inertia I depends on mass and how that mass is distributed about the chosen axis, so the same body can have different I values for different axes.
    • Apply conservation of angular momentum when the resultant external torque is zero, setting I₁ω₁ = I₂ω₂ for a system whose mass distribution changes.
    • Convert angular velocity between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω.
    • Interpret a decrease in I as causing an increase in ω when L is conserved, and link this to the skater or collapsing-star example.
    • Use consistent sign conventions for clockwise and anticlockwise rotation when combining angular momenta of interacting bodies.

    Common mistakes and how to put them right

    • Treating angular momentum as a scalar and ignoring direction.

      Put it right by assigning positive and negative signs to opposite senses of rotation about the chosen axis.

    • Using linear momentum p = mv instead of L = Iω for a rotating rigid body.

      Put it right by identifying the rotational variables and the axis of rotation.

    • Assuming I is always mr² for any body.

      Put it right by selecting the appropriate expression for the shape, such as ½mr² for a solid disc about its central axis.

    Exam tips

    • Write the conservation equation explicitly as I₁ω₁ = I₂ω₂ before substituting values, so the examiner can see the physical principle being applied.
    • Check that ω is in rad s⁻¹; if a frequency in Hz or rev s⁻¹ is given, convert using ω = 2πf.
    • State the condition for conservation clearly: resultant external torque is zero, not merely that no forces act.

    Try the lesson

    The start of the Angular momentum (A-level only): angular momentum = Iω Conservation of angular momentum. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A flywheel has a moment of inertia of 4.0 kg m² and spins at an angular velocity of 3.0 rad/s. What is the magnitude of its angular momentum?

    Listen

    Angular momentum is the rotational analogue of linear momentum. For a rigid body rotating about a fixed axis, it equals the product of moment of inertia I and angular velocity ω, so L = Iω. I depends on mass distribution about the axis; ω is the angular velocity in rad s⁻¹. Conservation of angular momentum states that if the resultant external torque on a system is zero, its total angular momentum remains constant. A skater pulling in their arms reduces I, so ω increases to keep Iω unchanged. Similarly, a planet in an elliptical orbit moves faster when closer to the Sun because its moment of inertia about the Sun is smaller. To solve problems, identify the axis, calculate I for the given shape, convert ω to rad s⁻¹, then apply L = Iω before and after any change. A strong answer earns marks for these points. State that angular momentum L is the product of moment of inertia I and angular velocity ω, with L = Iω and units kg m² rad s⁻¹ or kg m² s⁻¹. Explain that moment of inertia I depends on mass and how that mass is distributed about the chosen axis, so the same body can have different I values for different axes. Apply conservation of angular momentum when the resultant external torque is zero, setting I₁ω₁ = I₂ω₂ for a system whose mass distribution changes. Convert angular velocity between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω. A common slip: Treating angular momentum as a scalar and ignoring direction. Instead, assigning positive and negative signs to opposite senses of rotation about the chosen axis. Exam tip: Write the conservation equation explicitly as I₁ω₁ = I₂ω₂ before substituting values, so the examiner can see the physical principle being applied.

    See it

    A flowchart running from top to bottom. The first box reads 'Angular momentum L = Iω' and points to a box reading 'Resultant external torque is zero'. That points to 'Total angular momentum remains constant', which points to the equation 'I₁ω₁ = I₂ω₂'. From this equation two branches emerge. The first branch goes to 'Mass distribution changes: I decreases', which leads to 'ω increases to keep Iω unchanged'. The second branch goes to 'Mass distribution changes: I increases', which leads to 'ω decreases to keep Iω unchanged'.
    It shows that when the resultant external torque is zero, total angular momentum is conserved, so a change in moment of inertia changes angular velocity to keep Iω constant.

    Key words

    Say what each word means before you turn the card.

    Angular momentum

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    Moment of inertia

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    Conservation of angular momentum

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    Angular velocity

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    See every definition
    Angular momentum
    The product of moment of inertia I and angular velocity ω, so L = Iω, with units kg m² rad s⁻¹ or kg m² s⁻¹.
    Moment of inertia
    A quantity that depends on mass and how that mass is distributed about the chosen axis, so the same body can have different values for different axes.
    Conservation of angular momentum
    If the resultant external torque on a system is zero, its total angular momentum remains constant, so I₁ω₁ = I₂ω₂.
    Angular velocity
    A quantity in rad s⁻¹, converted between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart running from top to bottom. The first box reads 'Angular momentum L = Iω' and points to a box reading 'Resultant external torque is zero'. That points to 'Total angular momentum remains constant', which points to the equation 'I₁ω₁ = I₂ω₂'. From this equation two branches emerge. The first branch goes to 'Mass distribution changes: I decreases', which leads to 'ω increases to keep Iω unchanged'. The second branch goes to 'Mass distribution changes: I increases', which leads to 'ω decreases to keep Iω unchanged'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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