AQA · A-Level · Physics
Course version: 7408 · Version from Sept 2016
Angular momentum = Iω Conservation of angular momentum.
Full specification wording
Angular momentum (A-level only): angular momentum = Iω Conservation of angular momentum.
Angular momentum is the rotational analogue of linear momentum.
Checked against the AQA 7408 specification (opens in a new tab) on .
- Point 1 of 3
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
Angular momentum is the rotational analogue of linear momentum. For a rigid body rotating about a fixed axis, it equals the product of moment of inertia I and angular velocity ω, so L = Iω. I depends on mass distribution about the axis; ω is the angular velocity in rad s⁻¹. Conservation of angular momentum states that if the resultant external torque on a system is zero, its total angular momentum remains constant. A skater pulling in their arms reduces I, so ω increases to keep Iω unchanged. Similarly, a planet in an elliptical orbit moves faster when closer to the Sun because its moment of inertia about the Sun is smaller. To solve problems, identify the axis, calculate I for the given shape, convert ω to rad s⁻¹, then apply L = Iω before and after any change.
What earns the marks
- State that angular momentum L is the product of moment of inertia I and angular velocity ω, with L = Iω and units kg m² rad s⁻¹ or kg m² s⁻¹.
- Explain that moment of inertia I depends on mass and how that mass is distributed about the chosen axis, so the same body can have different I values for different axes.
- Apply conservation of angular momentum when the resultant external torque is zero, setting I₁ω₁ = I₂ω₂ for a system whose mass distribution changes.
- Convert angular velocity between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω.
- Interpret a decrease in I as causing an increase in ω when L is conserved, and link this to the skater or collapsing-star example.
- Use consistent sign conventions for clockwise and anticlockwise rotation when combining angular momenta of interacting bodies.
Common mistakes and how to put them right
Treating angular momentum as a scalar and ignoring direction.
Put it right by assigning positive and negative signs to opposite senses of rotation about the chosen axis.
Using linear momentum p = mv instead of L = Iω for a rotating rigid body.
Put it right by identifying the rotational variables and the axis of rotation.
Assuming I is always mr² for any body.
Put it right by selecting the appropriate expression for the shape, such as ½mr² for a solid disc about its central axis.
Exam tips
- Write the conservation equation explicitly as I₁ω₁ = I₂ω₂ before substituting values, so the examiner can see the physical principle being applied.
- Check that ω is in rad s⁻¹; if a frequency in Hz or rev s⁻¹ is given, convert using ω = 2πf.
- State the condition for conservation clearly: resultant external torque is zero, not merely that no forces act.
Try the lesson
The start of the Angular momentum (A-level only): angular momentum = Iω Conservation of angular momentum. lesson, made from checked teaching notes for this specification point.
Have a go first
A flywheel has a moment of inertia of 4.0 kg m² and spins at an angular velocity of 3.0 rad/s. What is the magnitude of its angular momentum?
Listen
Angular momentum is the rotational analogue of linear momentum. For a rigid body rotating about a fixed axis, it equals the product of moment of inertia I and angular velocity ω, so L = Iω. I depends on mass distribution about the axis; ω is the angular velocity in rad s⁻¹. Conservation of angular momentum states that if the resultant external torque on a system is zero, its total angular momentum remains constant. A skater pulling in their arms reduces I, so ω increases to keep Iω unchanged. Similarly, a planet in an elliptical orbit moves faster when closer to the Sun because its moment of inertia about the Sun is smaller. To solve problems, identify the axis, calculate I for the given shape, convert ω to rad s⁻¹, then apply L = Iω before and after any change. A strong answer earns marks for these points. State that angular momentum L is the product of moment of inertia I and angular velocity ω, with L = Iω and units kg m² rad s⁻¹ or kg m² s⁻¹. Explain that moment of inertia I depends on mass and how that mass is distributed about the chosen axis, so the same body can have different I values for different axes. Apply conservation of angular momentum when the resultant external torque is zero, setting I₁ω₁ = I₂ω₂ for a system whose mass distribution changes. Convert angular velocity between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω. A common slip: Treating angular momentum as a scalar and ignoring direction. Instead, assigning positive and negative signs to opposite senses of rotation about the chosen axis. Exam tip: Write the conservation equation explicitly as I₁ω₁ = I₂ω₂ before substituting values, so the examiner can see the physical principle being applied.
See it
Key words
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Angular momentum
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Moment of inertia
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Conservation of angular momentum
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Angular velocity
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See every definition
- Angular momentum
- The product of moment of inertia I and angular velocity ω, so L = Iω, with units kg m² rad s⁻¹ or kg m² s⁻¹.
- Moment of inertia
- A quantity that depends on mass and how that mass is distributed about the chosen axis, so the same body can have different values for different axes.
- Conservation of angular momentum
- If the resultant external torque on a system is zero, its total angular momentum remains constant, so I₁ω₁ = I₂ω₂.
- Angular velocity
- A quantity in rad s⁻¹, converted between rev s⁻¹ and rad s⁻¹ using ω = 2πf before substituting into L = Iω.
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