AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Use of Stefan’s law to compare the power output, temperature and size of…

    Full specification wording

    Classification by temperature, black-body radiation (A-level only): Use of Stefan’s law to compare the power output, temperature and size of stars P = σAT

    Stefan's law states that a black body radiates power P = σAT⁴, where σ is the Stefan constant, A is surface area and T is absolute temperature in kelvin.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 4 of 4
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Stefan's law states that a black body radiates power P = σAT⁴, where σ is the Stefan constant, A is surface area and T is absolute temperature in kelvin. For a spherical star, A = 4πr², so P = 4πσr²T⁴. This lets you compare stars: if two stars have the same luminosity but different temperatures, the cooler one must be larger. Form a ratio to cancel σ and 4π, for example P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴). Rearranged, r ∝ √P / T². Always convert temperatures to kelvin, use radius in metres, and remember that doubling temperature increases power by a factor of sixteen. The law assumes the star behaves as a black-body radiator.

    What earns the marks

    • States Stefan's law as P = σAT⁴ and identifies each symbol, including T in kelvin and A as the emitting surface area.
    • Uses A = 4πr² for a spherical star to obtain P = 4πσr²T⁴ and rearranges for radius, temperature or power as required.
    • Forms a ratio for two stars so that σ and 4π cancel, for example P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴), and solves for the unknown quantity.
    • Applies the fourth-power dependence correctly, for example recognising that doubling absolute temperature multiplies radiated power by sixteen at constant area.
    • Compares stars of different temperature and size, explaining that a cooler star must have a larger radius to emit the same power as a hotter star.
    • Converts temperatures from degrees Celsius to kelvin by adding 273 before substitution, and keeps consistent SI units throughout.
    • States that the star is modelled as a black-body radiator, so the law gives the total power radiated across all wavelengths.

    Common mistakes and how to put them right

    • Substituting temperature in degrees Celsius instead of kelvin.

      Put it right: Add 273 to convert to kelvin before raising to the fourth power.

    • Using the diameter or circumference in place of the radius when calculating surface area.

      Put it right: Use A = 4πr² with the radius, halving a diameter if necessary.

    • Forgetting to square the radius when forming a ratio, or applying the fourth power to the radius.

      Put it right: Keep r² and T⁴ separate in the ratio expression.

    • Treating σ as a variable that must be evaluated when comparing two stars.

      Put it right: Cancel it, along with 4π, in the ratio.

    Exam tips

    • Write the full equation P = 4πσr²T⁴ before substituting, then rearrange symbolically to reduce arithmetic errors.
    • For comparison questions, set up a ratio and cancel constants; this is quicker and less error-prone than calculating absolute values.
    • Check whether the question gives diameter or radius, and whether temperature is in kelvin, before starting the calculation.
    • Give the final answer with an appropriate unit and a sensible number of significant figures, and comment on whether the result is physically reasonable.

    Try the lesson

    The start of the Classification by temperature, black-body radiation (A-level only): Use of Stefan’s law to compare the power output, temperature and size of stars P = σAT lesson, made from checked teaching notes for this specification point.

    Have a go first

    Two stars have the same surface area, but star X has twice the surface temperature of star Y. According to Stefan’s law, what is the ratio of the power output of star X to that of star Y?

    Listen

    Stefan's law states that a black body radiates power P = σAT⁴, where σ is the Stefan constant, A is surface area and T is absolute temperature in kelvin. For a spherical star, A = 4πr², so P = 4πσr²T⁴. This lets you compare stars: if two stars have the same luminosity but different temperatures, the cooler one must be larger. Form a ratio to cancel σ and 4π, for example P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴). Rearranged, r ∝ √P / T². Always convert temperatures to kelvin, use radius in metres, and remember that doubling temperature increases power by a factor of sixteen. The law assumes the star behaves as a black-body radiator. A strong answer earns marks for these points. States Stefan's law as P = σAT⁴ and identifies each symbol, including T in kelvin and A as the emitting surface area. Uses A = 4πr² for a spherical star to obtain P = 4πσr²T⁴ and rearranges for radius, temperature or power as required. Forms a ratio for two stars so that σ and 4π cancel, for example P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴), and solves for the unknown quantity. Applies the fourth-power dependence correctly, for example recognising that doubling absolute temperature multiplies radiated power by sixteen at constant area. A common slip: Substituting temperature in degrees Celsius instead of kelvin. Instead, add 273 to convert to kelvin before raising to the fourth power. Exam tip: Write the full equation P = 4πσr²T⁴ before substituting, then rearrange symbolically to reduce arithmetic errors.

    See it

    A top-down flowchart. The first box reads 'Stefan's law: P = σAT⁴' and points down to a box reading 'Spherical star: A = 4πr²'. That points down to 'P = 4πσr²T⁴', which points down to 'Form ratio for two stars'. This points down to 'P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴)', which points down to 'σ and 4π cancel'. That points down to 'Solve for unknown quantity', which finally points down to 'Compare power output, temperature and size of stars'.
    It shows how Stefan's law for a spherical star leads to a ratio that lets you compare the power output, temperature and size of two stars.

    Put it in order

    Put these steps in the order they happen.

    1. 1. P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴)
    2. 2. Compare power output, temperature and size of stars
    3. 3. σ and 4π cancel
    4. 4. Stefan's law: P = σAT⁴
    5. 5. Spherical star: A = 4πr²
    6. 6. Solve for unknown quantity
    7. 7. P = 4πσr²T⁴
    8. 8. Form ratio for two stars

    Key words

    Say what each word means before you turn the card.

    Stefan's law

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    Stefan constant

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    Black-body radiator

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    Ratio method

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    See every definition
    Stefan's law
    A black body radiates power P = σAT⁴, where σ is the Stefan constant, A is surface area and T is absolute temperature in kelvin.
    Stefan constant
    The constant σ in Stefan's law, which cancels along with 4π when a ratio is formed for two stars.
    Black-body radiator
    The model assumed for the star, so that the law gives the total power radiated across all wavelengths.
    Ratio method
    Forming a ratio such as P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴) so that σ and 4π cancel, then solving for the unknown quantity.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first box reads 'Stefan's law: P = σAT⁴' and points down to a box reading 'Spherical star: A = 4πr²'. That points down to 'P = 4πσr²T⁴', which points down to 'Form ratio for two stars'. This points down to 'P₁/P₂ = (r₁²T₁⁴)/(r₂²T₂⁴)', which points down to 'σ and 4π cancel'. That points down to 'Solve for unknown quantity', which finally points down to 'Compare power output, temperature and size of stars'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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