AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    For a charged sphere, charge may be considered to be at the centre.

    Full specification wording

    Coulomb's law (A-level only): For a charged sphere, charge may be considered to be at the centre.

    A uniformly charged conducting sphere behaves, for points outside it, as though all its charge were concentrated at its centre.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 1 of 2
    • 2 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A uniformly charged conducting sphere behaves, for points outside it, as though all its charge were concentrated at its centre. This follows from the spherical symmetry of the charge distribution: every shell of charge contributes as a point charge at the centre, so the field outside is radial and Coulomb's law applies with r measured from the centre. For a point charge Q, the force on q is F = kQq/r², where k = 1/(4πε₀). The same result lets you treat a charged sphere as a point charge when finding force or field outside it. Inside a conductor in electrostatic equilibrium the field is zero, so the result is used only for external points.

    What earns the marks

    • For a uniformly charged sphere, external field lines are radial and appear to come from the centre.
    • Coulomb's law may be applied with r measured from the centre of the sphere, not from its surface.
    • The force between two charged spheres is F = kQ₁Q₂/r² when r is the centre-to-centre distance and the spheres do not overlap.
    • The result depends on spherical symmetry and uniform charge distribution.
    • Inside a conducting sphere in electrostatic equilibrium, the electric field is zero.

    Common mistakes and how to put them right

    • Measuring r from the surface of the sphere instead of its centre.

      Put it right by using the centre-to-centre distance.

    • Applying the point-charge result inside the sphere.

      Put it right by noting that the field inside a conductor in equilibrium is zero.

    • Assuming the result holds for a non-uniformly charged or irregular object.

      Put it right by restricting it to a uniformly charged sphere.

    Exam tips

    • Mark the centre of each sphere on a diagram and label r as the centre-to-centre distance.
    • State that the sphere behaves as a point charge at its centre before substituting into F = kQ₁Q₂/r².
    • Check whether the question asks for force or field, and use the appropriate equation.
    • Keep charges in coulombs and distances in metres before calculating.

    Try the lesson

    The start of the Coulomb's law (A-level only): For a charged sphere, charge may be considered to be at the centre. lesson, made from checked teaching notes for this specification point.

    Have a go first

    When using Coulomb's law to find the force between two charged spheres, where may the charge on each sphere be considered to act?

    Listen

    A uniformly charged conducting sphere behaves, for points outside it, as though all its charge were concentrated at its centre. This follows from the spherical symmetry of the charge distribution: every shell of charge contributes as a point charge at the centre, so the field outside is radial and Coulomb's law applies with r measured from the centre. For a point charge Q, the force on q is F = kQq/r², where k = 1/(4πε₀). The same result lets you treat a charged sphere as a point charge when finding force or field outside it. Inside a conductor in electrostatic equilibrium the field is zero, so the result is used only for external points. A strong answer earns marks for these points. For a uniformly charged sphere, external field lines are radial and appear to come from the centre. Coulomb's law may be applied with r measured from the centre of the sphere, not from its surface. The force between two charged spheres is F = kQ₁Q₂/r² when r is the centre-to-centre distance and the spheres do not overlap. The result depends on spherical symmetry and uniform charge distribution. A common slip: Measuring r from the surface of the sphere instead of its centre. Instead, using the centre-to-centre distance. Exam tip: Mark the centre of each sphere on a diagram and label r as the centre-to-centre distance.

    See it

    A top-down flowchart. The first node, 'Uniformly charged sphere', leads to 'Spherical symmetry of charge distribution', which leads to 'Every shell of charge contributes as a point charge at the centre', which leads to 'Charge may be considered to be at the centre'. From that node three branches emerge. The first branch goes to 'External field lines are radial, appearing to come from the centre'. The second branch goes to 'Coulomb's law applies with r measured from the centre', which leads to 'F = kQq/r², where k = 1/(4πε₀)'. The third branch goes to 'Valid only for external points', which leads to 'Inside a conductor in electrostatic equilibrium the field is zero'.
    It shows how the spherical symmetry of a uniformly charged sphere lets its charge be treated as being at the centre, so Coulomb's law applies for external points with r measured from the centre.

    Key words

    Say what each word means before you turn the card.

    Coulomb's law for point charges

    Try answering aloud or in your head before turning the card.

    Spherical symmetry and equivalent point charge

    Try answering aloud or in your head before turning the card.

    See every definition
    Coulomb's law for point charges
    For a point charge Q, the force on q is F = kQq/r², where k = 1/(4πε₀).
    Spherical symmetry and equivalent point charge
    For a uniformly charged sphere, charge may be considered to be at the centre, so it can be treated as a point charge for external points.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The first node, 'Uniformly charged sphere', leads to 'Spherical symmetry of charge distribution', which leads to 'Every shell of charge contributes as a point charge at the centre', which leads to 'Charge may be considered to be at the centre'. From that node three branches emerge. The first branch goes to 'External field lines are radial, appearing to come from the centre'. The second branch goes to 'Coulomb's law applies with r measured from the centre', which leads to 'F = kQq/r², where k = 1/(4πε₀)'. The third branch goes to 'Valid only for external points', which leads to 'Inside a conductor in electrostatic equilibrium the field is zero'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

    There is more to this lesson

    The full lesson goes on to check your understanding and help you earn the marks. Create a free account to carry on, with your progress saved.

    Carry on with the full lesson

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge

    Test your understanding of Coulomb's law (A-level only): For a charged sphere, charge may be considered to be at the centre.

    Active recall beats re-reading. Take an instant quiz now to test what you’ve learned and lock it into long-term memory.

    Take topic quiz

    A week of Premium from your first lesson · Then the free plan continues · No card, no charge