AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Derivation of dsinθ = nλ Use of the spectrometer will not be tested.

    Full specification wording

    Diffraction: Derivation of dsinθ = nλ Use of the spectrometer will not be tested.

    The grating equation d sinθ = nλ links the spacing d between adjacent slits, the diffraction angle θ and the wavelength λ for the nth order maximum.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 4 of 5
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The grating equation d sinθ = nλ links the spacing d between adjacent slits, the diffraction angle θ and the wavelength λ for the nth order maximum. Derive it by considering two adjacent slits: the extra distance travelled by light from the second slit is d sinθ. For constructive interference this path difference must equal a whole number of wavelengths, nλ, giving d sinθ = nλ. The equation shows that larger λ or smaller d spreads the pattern more, and that n counts the order. Although you must be able to derive and use the equation, practical work with a spectrometer is not examined, so focus on the geometry, the meaning of each symbol and calculations involving d, θ, n and λ.

    What earns the marks

    • State that the path difference between light from two adjacent slits is d sinθ, where d is the slit spacing and θ is the angle from the straight-through direction.
    • Explain that constructive interference occurs when the path difference equals a whole number of wavelengths, so d sinθ = nλ.
    • Identify n as the order of the maximum, with n = 0 for the central maximum and n = 1, 2, 3 … for successive maxima.
    • Use the equation to calculate d, θ, n or λ, converting angles to radians where required and using sinθ correctly.
    • Recognise that the derivation applies to any pair of adjacent slits and that all such pairs reinforce at the same angle.
    • Explain how the equation predicts that decreasing d or increasing λ increases the diffraction angle for a given order.

    Common mistakes and how to put them right

    • Using the angle from the grating surface instead of the angle from the normal.

      Put it right by measuring θ between the diffracted ray and the straight-through direction.

    • Treating d as the number of lines per metre rather than the slit spacing.

      Put it right by using d = 1 / N, where N is the number of lines per metre.

    • Forgetting that n must be an integer for a maximum.

      Put it right by checking that the calculated order is a whole number and rejecting non-integer values.

    Exam tips

    • Sketch two adjacent slits and mark the path difference d sinθ before writing the equation; this makes the derivation clear and earns method credit.
    • When calculating, keep d and λ in the same unit, usually metres, and give the angle to an appropriate number of significant figures.
    • If asked to derive the equation, state the condition for constructive interference explicitly rather than just quoting d sinθ = nλ.

    Try the lesson

    The start of the Diffraction: Derivation of dsinθ = nλ Use of the spectrometer will not be tested. lesson, made from checked teaching notes for this specification point.

    Have a go first

    In the grating equation d sinθ = nλ, what does the symbol d represent?

    Listen

    The grating equation d sinθ = nλ links the spacing d between adjacent slits, the diffraction angle θ and the wavelength λ for the nth order maximum. Derive it by considering two adjacent slits: the extra distance travelled by light from the second slit is d sinθ. For constructive interference this path difference must equal a whole number of wavelengths, nλ, giving d sinθ = nλ. The equation shows that larger λ or smaller d spreads the pattern more, and that n counts the order. Although you must be able to derive and use the equation, practical work with a spectrometer is not examined, so focus on the geometry, the meaning of each symbol and calculations involving d, θ, n and λ. A strong answer earns marks for these points. State that the path difference between light from two adjacent slits is d sinθ, where d is the slit spacing and θ is the angle from the straight-through direction. Explain that constructive interference occurs when the path difference equals a whole number of wavelengths, so d sinθ = nλ. Identify n as the order of the maximum, with n = 0 for the central maximum and n = 1, 2, 3 … for successive maxima. Use the equation to calculate d, θ, n or λ, converting angles to radians where required and using sinθ correctly. A common slip: Using the angle from the grating surface instead of the angle from the normal. Instead, measuring θ between the diffracted ray and the straight-through direction. Exam tip: Sketch two adjacent slits and mark the path difference d sinθ before writing the equation; this makes the derivation clear and earns method credit.

    See it

    A flowchart running from top to bottom. The first box reads 'Two adjacent slits, spacing d' and points to a second box reading 'Extra distance travelled by light from second slit = d sinθ'. This points to a third box reading 'Constructive interference when path difference = whole number of wavelengths', which points to a fourth box reading 'd sinθ = nλ'. From this fourth box two arrows lead out: one to a box reading 'n is the order: n = 0 central maximum, n = 1, 2, 3 … successive maxima', and the other to a box reading 'Decreasing d or increasing λ increases the diffraction angle for a given order'.
    It shows the derivation of the grating equation d sinθ = nλ from the path difference between two adjacent slits, and what the equation tells you about order and the spread of the pattern.

    Key words

    Say what each word means before you turn the card.

    Path difference

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    Constructive interference

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    Order of the maximum

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    Slit spacing

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    See every definition
    Path difference
    The extra distance travelled by light from the second slit compared with the first of two adjacent slits, equal to d sinθ.
    Constructive interference
    Occurs when the path difference between light from two adjacent slits equals a whole number of wavelengths, nλ.
    Order of the maximum
    The value n, with n = 0 for the central maximum and n = 1, 2, 3 … for successive maxima.
    Slit spacing
    The spacing d between adjacent slits, which with the diffraction angle θ and wavelength λ gives the grating equation.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart running from top to bottom. The first box reads 'Two adjacent slits, spacing d' and points to a second box reading 'Extra distance travelled by light from second slit = d sinθ'. This points to a third box reading 'Constructive interference when path difference = whole number of wavelengths', which points to a fourth box reading 'd sinθ = nλ'. From this fourth box two arrows lead out: one to a box reading 'n is the order: n = 0 central maximum, n = 1, 2, 3 … successive maxima', and the other to a box reading 'Decreasing d or increasing λ increases the diffraction angle for a given order'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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