AQA · A-Level · Physics
Course version: 7408 · Version from Sept 2016
Motion along a straight line: Displacement, speed, velocity, acceleration.
These four quantities describe motion along a straight line.
Checked against the AQA 7408 specification (opens in a new tab) on .
- Point 1 of 4
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
These four quantities describe motion along a straight line. Displacement is the vector change in position, so it has magnitude and direction; a walk of 3 m east then 4 m west gives displacement 1 m west but distance travelled 7 m. Speed is the scalar rate of change of distance, while velocity is the vector rate of change of displacement, so a car on a roundabout can have constant speed but changing velocity. Acceleration is the vector rate of change of velocity, produced by a resultant force; it can be positive or negative relative to a chosen direction. Average values use total change divided by total time, whereas instantaneous values describe a single moment. In calculations, choose a positive direction, assign signs consistently, and use v = Δs/Δt and a = Δv/Δt.
What earns the marks
- Defines displacement as a vector quantity giving the straight-line distance and direction from the starting point to the finishing point, and distinguishes it from scalar distance travelled.
- Defines speed as the scalar rate of change of distance and velocity as the vector rate of change of displacement, including direction or sign.
- Defines acceleration as the vector rate of change of velocity, recognising that a change in direction or a change in speed both produce acceleration.
- Applies v = Δs/Δt and a = Δv/Δt correctly, including consistent sign conventions and appropriate units such as m, m s⁻¹ and m s⁻².
- Distinguishes average values from instantaneous values, for example using total displacement divided by total time for average velocity.
- Interprets negative values as directions relative to a chosen positive axis rather than as automatically meaning slower or smaller.
Common mistakes and how to put them right
Treating distance and displacement as interchangeable.
Put it right by stating that distance is scalar and displacement is vector, then calculating each separately.
Assuming an object moving at constant speed cannot be accelerating.
Put it right by explaining that acceleration occurs whenever velocity changes, including a change in direction.
Using speed and velocity as synonyms in written answers.
Put it right by including direction or a sign whenever velocity is quoted.
Forgetting to convert units such as km h⁻¹ to m s⁻¹ before substitution.
Put it right by converting to SI units first.
Exam tips
- State the positive direction at the start of a calculation and keep the same sign convention throughout.
- When asked to compare scalar and vector quantities, name the quantity, give its definition and give one clear example.
- Show the equation, substitution and unit in calculation answers so that method and final value are both visible.
- Use the wording of the question to decide whether average or instantaneous values are required.
Try the lesson
The start of the Motion along a straight line: Displacement, speed, velocity, acceleration. lesson, made from checked teaching notes for this specification point.
Have a go first
A cyclist travels 240 m due north in 30 s. What is the cyclist's average velocity?
Listen
These four quantities describe motion along a straight line. Displacement is the vector change in position, so it has magnitude and direction; a walk of 3 m east then 4 m west gives displacement 1 m west but distance travelled 7 m. Speed is the scalar rate of change of distance, while velocity is the vector rate of change of displacement, so a car on a roundabout can have constant speed but changing velocity. Acceleration is the vector rate of change of velocity, produced by a resultant force; it can be positive or negative relative to a chosen direction. Average values use total change divided by total time, whereas instantaneous values describe a single moment. In calculations, choose a positive direction, assign signs consistently, and use v = Δs/Δt and a = Δv/Δt. A strong answer earns marks for these points. Defines displacement as a vector quantity giving the straight-line distance and direction from the starting point to the finishing point, and distinguishes it from scalar distance travelled. Defines speed as the scalar rate of change of distance and velocity as the vector rate of change of displacement, including direction or sign. Defines acceleration as the vector rate of change of velocity, recognising that a change in direction or a change in speed both produce acceleration. Applies v = Δs/Δt and a = Δv/Δt correctly, including consistent sign conventions and appropriate units such as m, m s⁻¹ and m s⁻². A common slip: Treating distance and displacement as interchangeable. Instead, stating that distance is scalar and displacement is vector, then calculating each separately. Exam tip: State the positive direction at the start of a calculation and keep the same sign convention throughout.
Key words
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Displacement
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Velocity
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Acceleration
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Average versus instantaneous motion
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See every definition
- Displacement
- The vector change in position, so it has magnitude and direction from the starting point to the finishing point.
- Velocity
- The vector rate of change of displacement, so a car on a roundabout can have constant speed but changing velocity.
- Acceleration
- The vector rate of change of velocity, produced by a resultant force, and it can be positive or negative relative to a chosen direction.
- Average versus instantaneous motion
- Average values use total change divided by total time, whereas instantaneous values describe a single moment.
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