AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Representation by graphical methods of uniform and non- uniform…

    Full specification wording

    Motion along a straight line: Representation by graphical methods of uniform and non- uniform acceleration.

    Motion graphs represent acceleration by their shape.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 2 of 4
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Motion graphs represent acceleration by their shape. On a displacement–time graph, the gradient gives velocity: a straight line means uniform velocity, while a curve means changing velocity and therefore acceleration. On a velocity–time graph, the gradient gives acceleration: a straight sloping line means uniform acceleration, a horizontal line means zero acceleration, and a curve means non-uniform acceleration. The area between the velocity–time graph and the time axis gives displacement, with areas below the axis counted as negative. To find a gradient, draw a tangent at the required instant and use Δv/Δt; to find displacement, split the area into triangles, rectangles or trapezia. A velocity–time graph that crosses the time axis shows a change of direction.

    What earns the marks

    • Interprets the gradient of a displacement–time graph as velocity, including the sign of the gradient.
    • Interprets the gradient of a velocity–time graph as acceleration, using a tangent where the graph is curved.
    • Recognises that a straight velocity–time line represents uniform acceleration and a curved line represents non-uniform acceleration.
    • Finds displacement from the area under a velocity–time graph, treating areas below the time axis as negative.
    • Sketches or selects graphs that match a described motion, such as constant velocity followed by uniform deceleration.
    • Uses units and scales correctly when reading gradients and areas from axes.

    Common mistakes and how to put them right

    • Reading the height of a velocity–time graph as displacement.

      Put it right by using the area under the graph for displacement.

    • Treating a curved displacement–time graph as constant velocity.

      Put it right by drawing tangents and noting that the gradient changes.

    • Ignoring the sign of areas below the time axis.

      Put it right by subtracting those areas when finding displacement.

    • Using the whole graph gradient when an instantaneous acceleration is requested.

      Put it right by drawing a tangent at the specified time.

    Exam tips

    • Label axes with quantity and unit before plotting or interpreting a graph.
    • For curved graphs, draw a clear tangent at the required point and show the triangle used for the gradient.
    • For area calculations, divide the region into simple shapes and state whether each area is positive or negative.
    • Check that the gradient units follow from the axes, for example m s⁻¹ divided by s gives m s⁻².

    Try the lesson

    The start of the Motion along a straight line: Representation by graphical methods of uniform and non- uniform acceleration. lesson, made from checked teaching notes for this specification point.

    Have a go first

    On a velocity-time graph, a straight line sloping upwards from left to right represents which type of motion?

    Listen

    Motion graphs represent acceleration by their shape. On a displacement–time graph, the gradient gives velocity: a straight line means uniform velocity, while a curve means changing velocity and therefore acceleration. On a velocity–time graph, the gradient gives acceleration: a straight sloping line means uniform acceleration, a horizontal line means zero acceleration, and a curve means non-uniform acceleration. The area between the velocity–time graph and the time axis gives displacement, with areas below the axis counted as negative. To find a gradient, draw a tangent at the required instant and use Δv/Δt; to find displacement, split the area into triangles, rectangles or trapezia. A velocity–time graph that crosses the time axis shows a change of direction. A strong answer earns marks for these points. Interprets the gradient of a displacement–time graph as velocity, including the sign of the gradient. Interprets the gradient of a velocity–time graph as acceleration, using a tangent where the graph is curved. Recognises that a straight velocity–time line represents uniform acceleration and a curved line represents non-uniform acceleration. Finds displacement from the area under a velocity–time graph, treating areas below the time axis as negative. A common slip: Reading the height of a velocity–time graph as displacement. Instead, using the area under the graph for displacement. Exam tip: Label axes with quantity and unit before plotting or interpreting a graph.

    See it

    A top-down flowchart. The top node, 'Motion graphs', splits into two branches: 'Displacement–time graph' and 'Velocity–time graph'. From 'Displacement–time graph' a node reads 'Gradient gives velocity', which splits into 'Straight line: uniform velocity' and 'Curve: changing velocity, so acceleration'. From 'Velocity–time graph' a node reads 'Gradient gives acceleration', which splits into three: 'Straight sloping line: uniform acceleration', 'Horizontal line: zero acceleration' and 'Curve: non-uniform acceleration'. Also from 'Velocity–time graph' a separate node reads 'Area to time axis gives displacement', leading to 'Areas below axis counted as negative'.
    It shows how the two motion graphs are read: gradient of a displacement–time graph gives velocity, gradient of a velocity–time graph gives acceleration, and area under a velocity–time graph gives displacement.

    Key words

    Say what each word means before you turn the card.

    Gradient as a rate of change

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    Area under a graph as a product

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    Uniform and non-uniform acceleration

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    Sign and direction in motion graphs

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    See every definition
    Gradient as a rate of change
    On a displacement–time graph the gradient gives velocity, and on a velocity–time graph it gives acceleration, found using a tangent where the graph is curved.
    Area under a graph as a product
    The area between the velocity–time graph and the time axis gives displacement, with areas below the axis counted as negative.
    Uniform and non-uniform acceleration
    A straight sloping velocity–time line means uniform acceleration, a horizontal line means zero acceleration, and a curve means non-uniform acceleration.
    Sign and direction in motion graphs
    The sign of the gradient of a displacement–time graph is included in the velocity, and a velocity–time graph that crosses the time axis shows a change of direction.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node, 'Motion graphs', splits into two branches: 'Displacement–time graph' and 'Velocity–time graph'. From 'Displacement–time graph' a node reads 'Gradient gives velocity', which splits into 'Straight line: uniform velocity' and 'Curve: changing velocity, so acceleration'. From 'Velocity–time graph' a node reads 'Gradient gives acceleration', which splits into three: 'Straight sloping line: uniform acceleration', 'Horizontal line: zero acceleration' and 'Curve: non-uniform acceleration'. Also from 'Velocity–time graph' a separate node reads 'Area to time axis gives displacement', leading to 'Areas below axis counted as negative'.
    • 1Box 1

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    • 3Box 3

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