AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Rotational kinetic energy (A-level only): Use of flywheels in machines.

    A flywheel is a rotating mass used to store rotational kinetic energy, E = ½Iω², where I is its moment of inertia and ω its angular velocity.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 1 of 2
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A flywheel is a rotating mass used to store rotational kinetic energy, E = ½Iω², where I is its moment of inertia and ω its angular velocity. Because a large I and high ω store substantial energy, a flywheel can smooth the output of an engine or machine: it absorbs energy when the driving torque exceeds demand and releases it when demand exceeds supply. In a vehicle, a heavy flywheel keeps the crankshaft turning between power strokes; in a press or wind turbine, it reduces speed fluctuations during each cycle. Energy stored depends on both I and ω², so doubling ω quadruples the stored energy. A flywheel of I = 0.50 kg m² spinning at 60 rad s⁻¹ stores ½ × 0.50 × 60² = 900 J.

    What earns the marks

    • Describe a flywheel as a rotating mass that stores rotational kinetic energy given by ½Iω².
    • Explain that energy is stored when the flywheel speeds up and released when it slows down, smoothing variations in speed or torque.
    • Link a large moment of inertia and high angular velocity to a large stored energy, noting the ω² dependence.
    • Apply the conservation idea that energy transferred from the drive is stored and later returned to the machine.
    • Calculate rotational kinetic energy or angular velocity using E = ½Iω² with consistent SI units.

    Common mistakes and how to put them right

    • Using linear kinetic energy.

      Put it right: Use ½Iω² with moment of inertia and angular velocity.

    • Confusing ω with frequency.

      Put it right: Convert to rad s⁻¹ using ω = 2πf.

    • Assuming a flywheel creates energy.

      Put it right: Describe it as storing and returning energy already supplied by the drive.

    Exam tips

    • State clearly whether the flywheel is storing or releasing energy at the point described in the question.
    • Show the substitution into E = ½Iω² with units, especially converting rpm to rad s⁻¹.
    • When explaining smoothing, refer to energy transfer during acceleration and deceleration of the flywheel.

    Try the lesson

    The start of the Rotational kinetic energy (A-level only): Use of flywheels in machines. lesson, made from checked teaching notes for this specification point.

    Have a go first

    Why is a flywheel often incorporated into the design of a mechanical punch press?

    Listen

    A flywheel is a rotating mass used to store rotational kinetic energy, E = ½Iω², where I is its moment of inertia and ω its angular velocity. Because a large I and high ω store substantial energy, a flywheel can smooth the output of an engine or machine: it absorbs energy when the driving torque exceeds demand and releases it when demand exceeds supply. In a vehicle, a heavy flywheel keeps the crankshaft turning between power strokes; in a press or wind turbine, it reduces speed fluctuations during each cycle. Energy stored depends on both I and ω², so doubling ω quadruples the stored energy. A flywheel of I = 0.50 kg m² spinning at 60 rad s⁻¹ stores ½ × 0.50 × 60² = 900 J. A strong answer earns marks for these points. Describe a flywheel as a rotating mass that stores rotational kinetic energy given by ½Iω². Explain that energy is stored when the flywheel speeds up and released when it slows down, smoothing variations in speed or torque. Link a large moment of inertia and high angular velocity to a large stored energy, noting the ω² dependence. Apply the conservation idea that energy transferred from the drive is stored and later returned to the machine. A common slip: Using linear kinetic energy: the error is applying ½mv² to a rotating flywheel. Instead, use ½Iω² with moment of inertia and angular velocity. Exam tip: State clearly whether the flywheel is storing or releasing energy at the point described in the question.

    See it

    A flowchart with two parallel paths that meet at a final node. The first path starts with a node labelled 'Driving torque exceeds demand', which leads to 'Flywheel speeds up', then to 'Energy stored as rotational kinetic energy'. The second path starts with 'Demand exceeds supply', which leads to 'Flywheel slows down', then to 'Stored energy released to the machine'. Both the storage node and the release node lead to a final node labelled 'Smooths variations in speed or torque'.
    It shows how a flywheel stores energy when it speeds up and releases it when it slows down, smoothing variations in speed or torque.

    Key words

    Say what each word means before you turn the card.

    Energy storage

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    Rotational kinetic energy

    Try answering aloud or in your head before turning the card.

    Smoothing of motion

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    Engineering applications

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    See every definition
    Energy storage
    A flywheel absorbs energy when the driving torque exceeds demand and releases it when demand exceeds supply.
    Rotational kinetic energy
    A rotating mass stores this, given by E = ½Iω², where I is its moment of inertia and ω its angular velocity.
    Smoothing of motion
    A flywheel reduces speed fluctuations during each cycle, keeping the crankshaft turning between power strokes in a vehicle.
    Engineering applications
    Flywheels are used in machines such as a vehicle, a press or a wind turbine.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart with two parallel paths that meet at a final node. The first path starts with a node labelled 'Driving torque exceeds demand', which leads to 'Flywheel speeds up', then to 'Energy stored as rotational kinetic energy'. The second path starts with 'Demand exceeds supply', which leads to 'Flywheel slows down', then to 'Stored energy released to the machine'. Both the storage node and the release node lead to a final node labelled 'Smooths variations in speed or torque'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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