AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Calculations will be limited to two vectors at right angles.

    Full specification wording

    Scalars and vectors: Calculations will be limited to two vectors at right angles.

    This statement defines the scope of vector calculations for perpendicular vectors.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 4 of 10
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    This statement defines the scope of vector calculations for perpendicular vectors. When combining two vectors at 90° to each other, you draw a right-angled triangle with the vectors placed tip-to-tail. You then use Pythagoras' theorem to find the magnitude of the resultant and an inverse tangent to find its direction. For example, a 3.0 N force north and a 4.0 N force east give a resultant of 5.0 N at 37° from the 4.0 N force. Resolving a single vector into two perpendicular components is the reverse process, using sine and cosine. While equilibrium problems can involve three coplanar forces, calculations to resolve them will rely on breaking them down into two perpendicular axes or using a closed vector triangle.

    What earns the marks

    • State that the two vectors must be perpendicular to form a right-angled triangle.
    • Use Pythagoras' theorem to calculate the magnitude of the resultant from two perpendicular vectors.
    • Use an inverse tangent ratio to calculate the angle giving the direction of the resultant relative to one of the vectors.
    • Resolve a single vector into two perpendicular components using sine and cosine.
    • For three coplanar forces in equilibrium, resolve them into two perpendicular axes to simplify calculations.

    Common mistakes and how to put them right

    • Adding the two magnitudes arithmetically instead of combining them as perpendicular vectors.

      Put it right by using Pythagoras' theorem so the resultant is larger than either vector but smaller than their sum.

    • Using the wrong trigonometric ratio when finding the angle.

      Put it right by identifying which sides are opposite and adjacent to the required angle before choosing tangent.

    • Forgetting to state the direction of the resultant.

      Put it right by giving the angle relative to a named vector or a compass direction.

    Exam tips

    • Sketch the two vectors tip-to-tail and mark the right angle before substituting numbers.
    • Check that the resultant magnitude lies between the larger vector and the arithmetic sum of the two vectors.

    Try the lesson

    The start of the Scalars and vectors: Calculations will be limited to two vectors at right angles. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A student walks 3 m due east and then 4 m due north. What is the magnitude of the resultant displacement?

    Listen

    This statement defines the scope of vector calculations for perpendicular vectors. When combining two vectors at 90° to each other, you draw a right-angled triangle with the vectors placed tip-to-tail. You then use Pythagoras' theorem to find the magnitude of the resultant and an inverse tangent to find its direction. For example, a 3.0 N force north and a 4.0 N force east give a resultant of 5.0 N at 37° from the 4.0 N force. Resolving a single vector into two perpendicular components is the reverse process, using sine and cosine. While equilibrium problems can involve three coplanar forces, calculations to resolve them will rely on breaking them down into two perpendicular axes or using a closed vector triangle. A strong answer earns marks for these points. State that the two vectors must be perpendicular to form a right-angled triangle. Use Pythagoras' theorem to calculate the magnitude of the resultant from two perpendicular vectors. Use an inverse tangent ratio to calculate the angle giving the direction of the resultant relative to one of the vectors. Resolve a single vector into two perpendicular components using sine and cosine. A common slip: Adding the two magnitudes arithmetically instead of combining them as perpendicular vectors. Instead, using Pythagoras' theorem so the resultant is larger than either vector but smaller than their sum. Exam tip: Sketch the two vectors tip-to-tail and mark the right angle before substituting numbers.

    See it

    A top-down flowchart. The top node reads 'Two perpendicular vectors' and branches to three paths. The first path goes to 'Draw right-angled triangle, vectors tip-to-tail', then to 'Pythagoras' theorem: magnitude of resultant', then to 'Inverse tangent: direction of resultant', then to 'State direction relative to a named vector'. The second path goes to 'Resolving a single vector', then to 'Two perpendicular components using sine and cosine'. The third path goes to 'Three coplanar forces in equilibrium', then to 'Resolve into two perpendicular axes'.
    It shows the steps for combining two perpendicular vectors into a resultant and the reverse process of resolving a vector into perpendicular components.

    Key words

    Say what each word means before you turn the card.

    Vector addition

    Try answering aloud or in your head before turning the card.

    Resultant magnitude and direction

    Try answering aloud or in your head before turning the card.

    Resolution of vectors

    Try answering aloud or in your head before turning the card.

    See every definition
    Vector addition
    Combining two vectors at 90° by drawing a right-angled triangle with the vectors placed tip-to-tail.
    Resultant magnitude and direction
    The size found using Pythagoras' theorem and the angle found using an inverse tangent.
    Resolution of vectors
    The reverse process of resolving a single vector into two perpendicular components using sine and cosine.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Two perpendicular vectors' and branches to three paths. The first path goes to 'Draw right-angled triangle, vectors tip-to-tail', then to 'Pythagoras' theorem: magnitude of resultant', then to 'Inverse tangent: direction of resultant', then to 'State direction relative to a named vector'. The second path goes to 'Resolving a single vector', then to 'Two perpendicular components using sine and cosine'. The third path goes to 'Three coplanar forces in equilibrium', then to 'Resolve into two perpendicular axes'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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