AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Impossibility of an engine working only by the First Law.

    Full specification wording

    Second Law and engines (A-level only): Impossibility of an engine working only by the First Law.

    The first law is an energy audit: it says energy is conserved, not which way a process may run.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 1 of 2
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    The first law is an energy audit: it says energy is conserved, not which way a process may run. A device could, in principle, take heat Q from a hot reservoir and convert it entirely into work W with ΔU = 0, satisfying ΔU = Q − W. The second law forbids this in a cyclic engine: no engine operating between two reservoirs can convert all absorbed heat into work, so efficiency is always below 1. The Kelvin–Planck statement captures this. A real engine must reject some heat Q_c to a cold sink, so W = Q_h − Q_c and efficiency = W/Q_h. This is why a single reservoir cannot drive a cyclic engine, and why 100% efficiency is unattainable.

    What earns the marks

    • State that the first law expresses conservation of energy and does not restrict the direction of energy transfer.
    • Explain that a cyclic engine with one reservoir would need Q_c = 0, giving efficiency 1, which the second law forbids.
    • Quote or apply the Kelvin–Planck statement: no cyclic device converts all absorbed heat into work.
    • Use W = Q_h − Q_c and efficiency = W/Q_h to show that efficiency is always less than 1 when Q_c is positive.
    • Distinguish a cyclic engine from a single one-off expansion, where all the heat could in principle become work.
    • Recognise that the second law is an independent principle, not derivable from the first law alone.

    Common mistakes and how to put them right

    • Claiming the first law alone forbids a 100% efficient engine.

      Put it right: The first law permits it and the second law forbids it.

    • Confusing efficiency with the fraction of heat rejected.

      Put it right: Efficiency is useful work divided by heat absorbed.

    • Applying the Kelvin–Planck restriction to a non-cyclic process.

      Put it right: It applies to devices operating in a cycle.

    • Omitting the cold reservoir when describing a heat engine.

      Put it right: A hot source, a cold sink and work output are all required.

    Exam tips

    • Name the law you are invoking explicitly, since questions often test whether you can separate the roles of the first and second laws.
    • Write the energy balance W = Q_h − Q_c before substituting numbers, then form efficiency as W/Q_h.
    • When asked why an engine cannot be 100% efficient, refer to the need to reject heat to a cold sink, not just to friction.
    • Use clear reservoir labels (hot and cold) in diagrams so the direction of each heat transfer is unambiguous.

    Try the lesson

    The start of the Second Law and engines (A-level only): Impossibility of an engine working only by the First Law. lesson, made from checked teaching notes for this specification point.

    Have a go first

    Why is it impossible for a heat engine to operate using only the First Law of thermodynamics?

    Listen

    The first law is an energy audit: it says energy is conserved, not which way a process may run. A device could, in principle, take heat Q from a hot reservoir and convert it entirely into work W with ΔU = 0, satisfying ΔU = Q − W. The second law forbids this in a cyclic engine: no engine operating between two reservoirs can convert all absorbed heat into work, so efficiency is always below 1. The Kelvin–Planck statement captures this. A real engine must reject some heat Q_c to a cold sink, so W = Q_h − Q_c and efficiency = W/Q_h. This is why a single reservoir cannot drive a cyclic engine, and why 100% efficiency is unattainable. A strong answer earns marks for these points. State that the first law expresses conservation of energy and does not restrict the direction of energy transfer. Explain that a cyclic engine with one reservoir would need Q_c = 0, giving efficiency 1, which the second law forbids. Quote or apply the Kelvin–Planck statement: no cyclic device converts all absorbed heat into work. Use W = Q_h − Q_c and efficiency = W/Q_h to show that efficiency is always less than 1 when Q_c is positive. A common slip: Claiming the first law alone forbids a 100% efficient engine. Instead, the first law permits it and the second law forbids it. Exam tip: Name the law you are invoking explicitly, since questions often test whether you can separate the roles of the first and second laws.

    Key words

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    Second law of thermodynamics

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    Kelvin–Planck statement

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    Heat engine efficiency

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    Hot and cold reservoirs

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    See every definition
    Second law of thermodynamics
    Forbids a cyclic engine from converting all absorbed heat into work, so efficiency is always below 1.
    Kelvin–Planck statement
    No cyclic device converts all absorbed heat into work.
    Heat engine efficiency
    Useful work divided by heat absorbed, given as W/Q_h, and always less than 1 when Q_c is positive.
    Hot and cold reservoirs
    A hot source and a cold sink, both required by a real engine, which rejects some heat Q_c to the cold sink.

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