AQA · A-Level · Physics

    Course version: 7408 · Version from Sept 2016

    Second Law of Thermodynamics expressed as the need for a heat engine to…

    Full specification wording

    Second Law and engines (A-level only): Second Law of Thermodynamics expressed as the need for a heat engine to operate between a source and a sink.

    A heat engine converts thermal energy into useful work, but only if thermal energy flows from a hot source to a cold sink.

    Checked against the AQA 7408 specification (opens in a new tab) on .

    • Point 2 of 2
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A heat engine converts thermal energy into useful work, but only if thermal energy flows from a hot source to a cold sink. The source supplies energy Q_H at temperature T_H; the engine extracts work W; the sink receives Q_C at lower temperature T_C. The Second Law forbids a device that converts a single thermal reservoir entirely into work with no sink, so efficiency is always below 1.

    For example: A steam turbine takes energy from steam at about 800 K and rejects energy to cooling water at about 300 K. The maximum theoretical efficiency is 1 − T_C/T_H, showing that a larger temperature difference gives greater efficiency.

    What earns the marks

    • State that a heat engine absorbs thermal energy from a hot source and rejects some thermal energy to a cold sink.
    • Explain that the Second Law requires a temperature difference between source and sink for continuous conversion of thermal energy into work.
    • Apply the energy balance W = Q_H − Q_C to a heat engine operating between a source and a sink.
    • Use the Kelvin temperatures of source and sink to compare maximum theoretical efficiencies of different engines.
    • Recognise that no real engine can be 100% efficient because some energy must be rejected to the sink.

    Common mistakes and how to put them right

    • Thinking that a heat engine can convert all absorbed thermal energy into work.

      Put it right by stating that some energy must be rejected to a cold sink.

    • Using Celsius temperatures in efficiency calculations.

      Put it right by converting all temperatures to kelvin first.

    • Confusing the source with the sink.

      Put it right by identifying the source as the hot reservoir that supplies energy and the sink as the cold reservoir that receives rejected energy.

    Exam tips

    • Sketch a simple energy flow diagram labelling source, engine, work output and sink before calculating.
    • When comparing engines, calculate the maximum theoretical efficiency for each using source and sink temperatures in kelvin.
    • Explain the Second Law in terms of the direction of spontaneous energy transfer from hot to cold, not just energy conservation.

    Try the lesson

    The start of the Second Law and engines (A-level only): Second Law of Thermodynamics expressed as the need for a heat engine to operate between a source and a sink. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A heat engine takes in energy from a hot source and delivers some of it as useful work. According to the Second Law of Thermodynamics, what must the engine also have in order to keep operating?

    Listen

    A heat engine converts thermal energy into useful work, but only if thermal energy flows from a hot source to a cold sink. The source supplies energy Q_H at temperature T_H; the engine extracts work W; the sink receives Q_C at lower temperature T_C. The Second Law forbids a device that converts a single thermal reservoir entirely into work with no sink, so efficiency is always below 1. For example, a steam turbine takes energy from steam at about 800 K and rejects energy to cooling water at about 300 K. The maximum theoretical efficiency is 1 − T_C/T_H, showing that a larger temperature difference gives greater efficiency. A strong answer earns marks for these points. State that a heat engine absorbs thermal energy from a hot source and rejects some thermal energy to a cold sink. Explain that the Second Law requires a temperature difference between source and sink for continuous conversion of thermal energy into work. Apply the energy balance W = Q_H − Q_C to a heat engine operating between a source and a sink. Use the Kelvin temperatures of source and sink to compare maximum theoretical efficiencies of different engines. A common slip: Thinking that a heat engine can convert all absorbed thermal energy into work. Instead, stating that some energy must be rejected to a cold sink. Exam tip: Sketch a simple energy flow diagram labelling source, engine, work output and sink before calculating.

    See it

    A left-to-right flow diagram with four nodes. The hot source at T_H points to the heat engine, labelled Q_H. The heat engine points to useful work, labelled W, and also points to the cold sink at T_C, labelled Q_C. This shows that the engine receives thermal energy from the hot source, produces work, and rejects some thermal energy to the cold sink.
    It shows a heat engine taking energy Q_H from a hot source, delivering work W and rejecting energy Q_C to a cold sink.

    Key words

    Say what each word means before you turn the card.

    Second Law of Thermodynamics

    Try answering aloud or in your head before turning the card.

    Heat engine

    Try answering aloud or in your head before turning the card.

    Source

    Try answering aloud or in your head before turning the card.

    Sink

    Try answering aloud or in your head before turning the card.

    See every definition
    Second Law of Thermodynamics
    It forbids a device that converts a single thermal reservoir entirely into work with no sink, so efficiency is always below 1.
    Heat engine
    It converts thermal energy into useful work, but only if thermal energy flows from a hot source to a cold sink.
    Source
    The hot reservoir that supplies energy Q_H at temperature T_H to the engine.
    Sink
    The cold reservoir that receives rejected energy Q_C at lower temperature T_C.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 2 boxes numbered instead of named. A left-to-right flow diagram with four nodes. The hot source at T_H points to the heat engine, labelled Q_H. The heat engine points to useful work, labelled W, and also points to the cold sink at T_C, labelled Q_C. This shows that the engine receives thermal energy from the hot source, produces work, and rejects some thermal energy to the cold sink.
    • 1Box 1

    • 2Box 2

    0 of 2 labelled

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