AQA · GCSE · Physics

    Course version: 8463 · Version from Sept 2016

    (HT only) The distance travelled by an object (or displacement of an…

    Full specification wording

    Acceleration: (HT only) The distance travelled by an object (or displacement of an object) can be calculated from the area under a velocity–time graph.

    Multiply a velocity by a time and you get a distance, which is why the area between the line and the time axis on a velocity-time graph is the distance travelled.

    Checked against the AQA 8463 specification (opens in a new tab) on .

    • Point 17 of 23
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    Multiply a velocity by a time and you get a distance, which is why the area between the line and the time axis on a velocity-time graph is the distance travelled. For straight-line sections, split the area into rectangles and triangles: a rectangle is velocity multiplied by time, and a triangle is half the base multiplied by the height. An object accelerating uniformly from rest to 12 m/s in 6.0 s covers 36 m. Where the line curves, count squares instead: work out what one square represents by multiplying the value of one square on each axis, count the squares under the line, counting a part square if more than half of it lies underneath, then multiply. An area below the time axis represents motion in the opposite direction.

    What earns the marks

    • Identifying the area under the line as the distance travelled.
    • Splitting that area into rectangles and triangles, or for a stated value of one square.
    • The separate areas calculated and added.
    • The total distance with its unit.

    Common mistakes and how to put them right

    • Using the gradient when the question asks for a distance.

    • Finding the area of the triangle only and ignoring the rectangle beneath it.

    • Counting squares without working out what one square represents.

    • Forgetting the half in the area of a triangle.

    Exam tips

    • Divide the shape with a vertical line and label each part before calculating.
    • State the value of one square explicitly, because it is a mark on its own.

    Try the lesson

    The start of the Acceleration: (HT only) The distance travelled by an object (or displacement of an object) can be calculated from the area under a velocity–time graph. lesson, made from checked teaching notes for this specification point.

    Have a go first

    A velocity–time graph shows a straight line from (0 s, 0 m/s) to (4 s, 8 m/s). What distance does the object travel in the 4 s?

    Listen

    Multiply a velocity by a time and you get a distance, which is why the area between the line and the time axis on a velocity-time graph is the distance travelled. For straight-line sections, split the area into rectangles and triangles: a rectangle is velocity multiplied by time, and a triangle is half the base multiplied by the height. An object accelerating uniformly from rest to 12 m/s in 6.0 s covers 36 m. Where the line curves, count squares instead: work out what one square represents by multiplying the value of one square on each axis, count the squares under the line, counting a part square if more than half of it lies underneath, then multiply. An area below the time axis represents motion in the opposite direction. A strong answer earns marks for these points. identifying the area under the line as the distance travelled. splitting that area into rectangles and triangles, or for a stated value of one square. the separate areas calculated and added. the total distance with its unit. Exam tip: Divide the shape with a vertical line and label each part before calculating.

    See it

    A top-down flowchart. The top node reads 'Velocity–time graph' and points down to 'Area under the line = distance travelled'. This branches into two nodes: 'Straight-line sections' and 'Curved line'. From 'Straight-line sections' a node reads 'Split into rectangles and triangles', which branches into 'Rectangle: velocity × time' and 'Triangle: ½ × base × height'; both of these lead to 'Add the separate areas'. From 'Curved line' the chain runs 'Work out what one square represents', then 'Count the squares under the line', then 'Multiply by the value of one square'.
    It shows how the area under a velocity–time graph gives the distance travelled, split into rectangles and triangles for straight-line sections or counted in squares for a curved line.

    Key words

    Say what each word means before you turn the card.

    area under a graph

    Try answering aloud or in your head before turning the card.

    distance travelled

    Try answering aloud or in your head before turning the card.

    rectangles and triangles

    Try answering aloud or in your head before turning the card.

    See every definition
    area under a graph
    The region between the line and the time axis on a velocity–time graph, from which the distance travelled can be calculated.
    distance travelled
    The quantity calculated from the area under a velocity–time graph, or from the area below the time axis for motion in the opposite direction.
    rectangles and triangles
    The shapes into which the area under straight-line sections is split, a rectangle being velocity multiplied by time and a triangle half the base multiplied by the height.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A top-down flowchart. The top node reads 'Velocity–time graph' and points down to 'Area under the line = distance travelled'. This branches into two nodes: 'Straight-line sections' and 'Curved line'. From 'Straight-line sections' a node reads 'Split into rectangles and triangles', which branches into 'Rectangle: velocity × time' and 'Triangle: ½ × base × height'; both of these lead to 'Add the separate areas'. From 'Curved line' the chain runs 'Work out what one square represents', then 'Count the squares under the line', then 'Multiply by the value of one square'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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