OCR · A-Level · Physics
Course version: H556 · Version from Sept 2015
Capacitors: (a) capacitance; C = Q/V; the unit farad
A capacitor stores charge on two conductors separated by an insulator.
Checked against the OCR H556 specification (opens in a new tab) on .
- Point 1 of 6
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
A capacitor stores charge on two conductors separated by an insulator. Its capacitance C is defined as the charge stored per unit potential difference: C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor. The unit of capacitance is the farad (F); one farad is one coulomb per volt, so 1 F = 1 C V⁻¹. Typical capacitors have values in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F). Rearranged, Q = CV and V = Q/C.
What earns the marks
- Defines capacitance as charge stored per unit potential difference: C = Q/V.
- States that the unit of capacitance is the farad, where 1 F = 1 C V⁻¹.
- Uses the rearrangements Q = CV and V = Q/C correctly in calculations.
- Converts between farads and submultiples such as μF, nF and pF using powers of ten.
Common mistakes and how to put them right
Using the total charge on both plates in C = Q/V.
Put it right: Q is the magnitude of charge on one plate.
Treating the farad as a base unit.
Put it right: It is defined as one coulomb per volt.
Mixing up microfarads and nanofarads, for example writing 1 μF = 1 × 10⁻⁹ F instead of 1 × 10⁻⁶ F.
Substituting the potential difference across the whole circuit for the potential difference across the capacitor.
Exam tips
- Write the defining equation C = Q/V before substituting values so the quantities are clear.
- Convert all capacitance values to farads before calculating, then convert the answer back if needed.
- Check units: charge in coulombs, potential difference in volts and capacitance in farads.
Try the lesson
The start of the Capacitors: (a) capacitance; C = Q/V; the unit farad lesson, made from checked teaching notes for this specification point.
Listen
A capacitor stores charge on two conductors separated by an insulator. Its capacitance C is defined as the charge stored per unit potential difference: C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor. The unit of capacitance is the farad (F); one farad is one coulomb per volt, so 1 F = 1 C V⁻¹. Typical capacitors have values in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F). Rearranged, Q = CV and V = Q/C. A strong answer earns marks for these points. Defines capacitance as charge stored per unit potential difference: C = Q/V. States that the unit of capacitance is the farad, where 1 F = 1 C V⁻¹. Uses the rearrangements Q = CV and V = Q/C correctly in calculations. Converts between farads and submultiples such as μF, nF and pF using powers of ten. Exam tip: Write the defining equation C = Q/V before substituting values so the quantities are clear.
See it
Key words
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Capacitance
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Farad
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Rearranging C = Q/V
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Unit prefixes and conversions
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See every definition
- Capacitance
- The charge stored per unit potential difference, given by C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor.
- Farad
- The unit of capacitance, where one farad is one coulomb per volt, so 1 F = 1 C V⁻¹.
- Rearranging C = Q/V
- The defining equation can be rearranged to Q = CV and V = Q/C to find charge or potential difference.
- Unit prefixes and conversions
- Capacitance values may be given in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F).
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