OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    Capacitors: (a) capacitance; C = Q/V; the unit farad

    A capacitor stores charge on two conductors separated by an insulator.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 1 of 6
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    A capacitor stores charge on two conductors separated by an insulator. Its capacitance C is defined as the charge stored per unit potential difference: C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor. The unit of capacitance is the farad (F); one farad is one coulomb per volt, so 1 F = 1 C V⁻¹. Typical capacitors have values in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F). Rearranged, Q = CV and V = Q/C.

    What earns the marks

    • Defines capacitance as charge stored per unit potential difference: C = Q/V.
    • States that the unit of capacitance is the farad, where 1 F = 1 C V⁻¹.
    • Uses the rearrangements Q = CV and V = Q/C correctly in calculations.
    • Converts between farads and submultiples such as μF, nF and pF using powers of ten.

    Common mistakes and how to put them right

    • Using the total charge on both plates in C = Q/V.

      Put it right: Q is the magnitude of charge on one plate.

    • Treating the farad as a base unit.

      Put it right: It is defined as one coulomb per volt.

    • Mixing up microfarads and nanofarads, for example writing 1 μF = 1 × 10⁻⁹ F instead of 1 × 10⁻⁶ F.

    • Substituting the potential difference across the whole circuit for the potential difference across the capacitor.

    Exam tips

    • Write the defining equation C = Q/V before substituting values so the quantities are clear.
    • Convert all capacitance values to farads before calculating, then convert the answer back if needed.
    • Check units: charge in coulombs, potential difference in volts and capacitance in farads.

    Try the lesson

    The start of the Capacitors: (a) capacitance; C = Q/V; the unit farad lesson, made from checked teaching notes for this specification point.

    Listen

    A capacitor stores charge on two conductors separated by an insulator. Its capacitance C is defined as the charge stored per unit potential difference: C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor. The unit of capacitance is the farad (F); one farad is one coulomb per volt, so 1 F = 1 C V⁻¹. Typical capacitors have values in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F). Rearranged, Q = CV and V = Q/C. A strong answer earns marks for these points. Defines capacitance as charge stored per unit potential difference: C = Q/V. States that the unit of capacitance is the farad, where 1 F = 1 C V⁻¹. Uses the rearrangements Q = CV and V = Q/C correctly in calculations. Converts between farads and submultiples such as μF, nF and pF using powers of ten. Exam tip: Write the defining equation C = Q/V before substituting values so the quantities are clear.

    See it

    A flowchart starting from a top node labelled 'Capacitance C = Q/V'. From it, branches lead to four nodes: 'Q is magnitude of charge on one plate', 'V is potential difference across the capacitor', 'Unit: farad (F)', and two rearrangement nodes 'Rearranged: Q = CV' and 'Rearranged: V = Q/C'. The 'Unit: farad (F)' node leads to '1 F = 1 C V⁻¹' and to 'Submultiples: μF, nF, pF'.
    It shows the definition C = Q/V with its quantities, the farad as the unit, the two rearrangements and the submultiple units.

    Key words

    Say what each word means before you turn the card.

    Capacitance

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    Farad

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    Rearranging C = Q/V

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    Unit prefixes and conversions

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    See every definition
    Capacitance
    The charge stored per unit potential difference, given by C = Q/V, where Q is the magnitude of charge on one plate and V is the potential difference across the capacitor.
    Farad
    The unit of capacitance, where one farad is one coulomb per volt, so 1 F = 1 C V⁻¹.
    Rearranging C = Q/V
    The defining equation can be rearranged to Q = CV and V = Q/C to find charge or potential difference.
    Unit prefixes and conversions
    Capacitance values may be given in microfarads (1 μF = 1 × 10⁻⁶ F), nanofarads (1 nF = 1 × 10⁻⁹ F) or picofarads (1 pF = 1 × 10⁻¹² F).

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart starting from a top node labelled 'Capacitance C = Q/V'. From it, branches lead to four nodes: 'Q is magnitude of charge on one plate', 'V is potential difference across the capacitor', 'Unit: farad (F)', and two rearrangement nodes 'Rearranged: Q = CV' and 'Rearranged: V = Q/C'. The 'Unit: farad (F)' node leads to '1 F = 1 C V⁻¹' and to 'Submultiples: μF, nF, pF'.
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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