OCR · A-Level · Physics
Course version: H556 · Version from Sept 2015
(d) total capacitance of two or more capacitors in parallel; C = C₁ + C₂ +…
Full specification wording
Capacitors: (d) total capacitance of two or more capacitors in parallel; C = C₁ + C₂ + ...
When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances: C = C₁ + C₂ + ... .
Checked against the OCR H556 specification (opens in a new tab) on .
- Point 4 of 6
- 4 key terms
Study notes
From the checked teaching notes for this specification point.
The idea
When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances: C = C₁ + C₂ + ... . This means the total capacitance is always greater than the largest individual capacitance. For example, two 10 μF capacitors in parallel give C = 10 + 10 = 20 μF. In a parallel arrangement, each capacitor has the same potential difference across it, and the total charge stored is the sum of the charges on the individual capacitors. The formula is used directly without taking reciprocals.
What earns the marks
- The formula for capacitors in parallel is C = C₁ + C₂ + ... .
- The total capacitance in parallel is greater than the largest individual capacitance.
- Each capacitor in parallel has the same potential difference across it.
- The total charge stored is the sum of the charges on the individual capacitors.
- The formula is applied by direct addition of the capacitance values.
Common mistakes and how to put them right
Using reciprocals for parallel capacitors, as if they were in series.
Put it right: Parallel uses direct addition.
Assuming the total capacitance is less than the largest individual capacitance.
Put it right: In parallel it is always greater.
Forgetting that the potential difference is the same across each parallel branch.
Adding charges instead of capacitances when the question asks for total capacitance.
Exam tips
- Write down the formula C = C₁ + C₂ + ... before substituting values.
- Check that your answer is larger than the largest individual capacitance as a quick sanity check.
- Keep units consistent, for example all capacitances in μF or all in F.
- Remember that in parallel the potential difference across each capacitor is the same.
Try the lesson
The start of the Capacitors: (d) total capacitance of two or more capacitors in parallel; C = C₁ + C₂ + ... lesson, made from checked teaching notes for this specification point.
Listen
When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitances: C = C₁ + C₂ + ... This means the total capacitance is always greater than the largest individual capacitance. For example, two 10 μF capacitors in parallel give C = 10 + 10 = 20 μF. In a parallel arrangement, each capacitor has the same potential difference across it, and the total charge stored is the sum of the charges on the individual capacitors. The formula is used directly without taking reciprocals. A strong answer earns marks for these points. The formula for capacitors in parallel is C = C₁ + C₂ + ... The total capacitance in parallel is greater than the largest individual capacitance. Each capacitor in parallel has the same potential difference across it. The total charge stored is the sum of the charges on the individual capacitors. Exam tip: Write down the formula C = C₁ + C₂ + ... before substituting values.
See it
Key words
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Parallel combination of capacitors
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Direct addition of capacitance
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Conservation of charge in parallel
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Equal potential difference in parallel
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See every definition
- Parallel combination of capacitors
- A connection in which the total capacitance is the sum of the individual capacitances, C = C₁ + C₂ + ... .
- Direct addition of capacitance
- The formula is applied by adding the capacitance values directly, without taking reciprocals.
- Conservation of charge in parallel
- The total charge stored is the sum of the charges on the individual capacitors.
- Equal potential difference in parallel
- Each capacitor in a parallel arrangement has the same potential difference across it.
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