OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    (a) interchange between kinetic and potential energy during simple…

    Full specification wording

    Energy of a simple harmonic oscillator: (a) interchange between kinetic and potential energy during simple harmonic motion

    In an undamped simple harmonic oscillator, total energy is conserved while kinetic and potential energy interchange continuously.

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 1 of 2
    • 4 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    In an undamped simple harmonic oscillator, total energy is conserved while kinetic and potential energy interchange continuously. Kinetic energy is maximum at the equilibrium position, where speed is greatest, and zero at maximum displacement, where the oscillator momentarily stops. Potential energy is zero at equilibrium and maximum at maximum displacement. For a mass–spring system, potential energy is elastic, stored in the spring; for a pendulum, it is gravitational. The total energy E = ½kA² = ½mω²A² remains constant, where A is amplitude. At any displacement x, kinetic energy is ½mω²(A² − x²) and potential energy is ½mω²x², so their sum is constant.

    What earns the marks

    • Total energy of an undamped simple harmonic oscillator is constant and equals ½mω²A².
    • Kinetic energy is maximum at equilibrium (x = 0) and zero at maximum displacement (x = ±A).
    • Potential energy is zero at equilibrium and maximum at maximum displacement.
    • Kinetic energy at displacement x is ½mω²(A² − x²) and potential energy is ½mω²x².
    • The interchange is continuous, with kinetic energy converting to potential energy and back each cycle.
    • For a mass–spring oscillator the potential energy is elastic; for a pendulum it is gravitational.

    Common mistakes and how to put them right

    • Thinking total energy changes during the cycle.

      Put it right: Total energy is constant when damping is negligible.

    • Believing kinetic energy is maximum at maximum displacement.

      Put it right: Speed is zero there, so kinetic energy is zero.

    • Assuming potential energy is maximum at equilibrium.

      Put it right: Potential energy is zero at equilibrium and maximum at the extremes.

    • Using E = ½mv² with v as the maximum speed at all positions instead of using the displacement-dependent expression.

    Exam tips

    • Write the total energy as ½mω²A² and subtract the potential energy to find kinetic energy at any displacement.
    • Check the position first: equilibrium means maximum kinetic energy, extremes mean maximum potential energy.
    • Keep amplitude A distinct from displacement x in every expression.

    Try the lesson

    The start of the Energy of a simple harmonic oscillator: (a) interchange between kinetic and potential energy during simple harmonic motion lesson, made from checked teaching notes for this specification point.

    Listen

    In an undamped simple harmonic oscillator, total energy is conserved while kinetic and potential energy interchange continuously. Kinetic energy is maximum at the equilibrium position, where speed is greatest, and zero at maximum displacement, where the oscillator momentarily stops. Potential energy is zero at equilibrium and maximum at maximum displacement. For a mass–spring system, potential energy is elastic, stored in the spring; for a pendulum, it is gravitational. The total energy E = ½kA² = ½mω²A² remains constant, where A is amplitude. At any displacement x, kinetic energy is ½mω²(A² − x²) and potential energy is ½mω²x², so their sum is constant. A strong answer earns marks for these points. Total energy of an undamped simple harmonic oscillator is constant and equals ½mω²A². Kinetic energy is maximum at equilibrium (x = 0) and zero at maximum displacement (x = ±A). Potential energy is zero at equilibrium and maximum at maximum displacement. Kinetic energy at displacement x is ½mω²(A² − x²) and potential energy is ½mω²x². Exam tip: Write the total energy as ½mω²A² and subtract the potential energy to find kinetic energy at any displacement.

    See it

    A flowchart in a loop. It starts at the oscillator at maximum displacement x = ±A, where kinetic energy is zero and potential energy is maximum. The oscillator then moves towards equilibrium, so kinetic energy increases and potential energy decreases. At equilibrium x = 0, kinetic energy is maximum and potential energy is zero. The oscillator then moves towards maximum displacement, so kinetic energy decreases and potential energy increases, returning to the start. Two side nodes connect to the maximum-displacement and equilibrium stages: one states that total energy is constant and equals ½mω²A², and the other gives kinetic energy as ½mω²(A² − x²) and potential energy as ½mω²x².
    Shows the continuous interchange between kinetic and potential energy through one cycle of simple harmonic motion, with total energy remaining constant.

    Key words

    Say what each word means before you turn the card.

    Conservation of energy in simple harmonic motion

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    Kinetic and potential energy interchange

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    Energy–displacement relationships

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    Amplitude and total energy

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    See every definition
    Conservation of energy in simple harmonic motion
    In an undamped simple harmonic oscillator, total energy is conserved while kinetic and potential energy interchange continuously.
    Kinetic and potential energy interchange
    The interchange is continuous, with kinetic energy converting to potential energy and back each cycle.
    Energy–displacement relationships
    At any displacement x, kinetic energy is ½mω²(A² − x²) and potential energy is ½mω²x², so their sum is constant.
    Amplitude and total energy
    The total energy E = ½kA² = ½mω²A² remains constant, where A is amplitude.

    Label the diagram

    Some boxes have lost their names. Pick the right name for each number.

    The diagram again, with 3 boxes numbered instead of named. A flowchart in a loop. It starts at the oscillator at maximum displacement x = ±A, where kinetic energy is zero and potential energy is maximum. The oscillator then moves towards equilibrium, so kinetic energy increases and potential energy decreases. At equilibrium x = 0, kinetic energy is maximum and potential energy is zero. The oscillator then moves towards maximum displacement, so kinetic energy decreases and potential energy increases, returning to the start. Two side nodes connect to the maximum-displacement and equilibrium stages: one states that total energy is constant and equals ½mω²A², and the other gives kinetic energy as ½mω²(A² − x²) and potential energy as ½mω²x².
    • 1Box 1

    • 2Box 2

    • 3Box 3

    0 of 3 labelled

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