OCR · A-Level · Physics

    Course version: H556 · Version from Sept 2015

    Ideal gases: (h) pV = NkT; 1/2 mc² = 3/2 kT

    These two equations describe an ideal gas at the particle level. pV = NkT relates pressure p, volume V, number of molecules N, Boltzmann constant k and thermodynamic temperature T; it is the…

    Checked against the OCR H556 specification (opens in a new tab) on .

    • Point 9 of 10
    • 3 key terms

    Study notes

    From the checked teaching notes for this specification point.

    The idea

    These two equations describe an ideal gas at the particle level. pV = NkT relates pressure p, volume V, number of molecules N, Boltzmann constant k and thermodynamic temperature T; it is the per-particle form of pV = nRT. The second, ½mc² = 3/2 kT, gives the mean translational kinetic energy of a molecule of mass m and mean-square speed c². The factor 3/2 arises because a molecule can move in three independent directions. Combining them shows that temperature alone fixes mean kinetic energy, so at a given T all gas molecules have the same average translational energy regardless of mass, while lighter molecules have higher mean-square speeds.

    What earns the marks

    • States pV = NkT and identifies each symbol: p pressure, V volume, N number of molecules, k Boltzmann constant, T temperature in kelvin.
    • States ½mc² = 3/2 kT as the mean translational kinetic energy of a molecule, with c² the mean-square speed.
    • Explains that the 3/2 factor comes from three translational degrees of freedom.
    • Uses the two equations together, for example to show that mean kinetic energy depends only on T.
    • Keeps temperature in kelvin and uses consistent SI units for p, V, m and c.

    Common mistakes and how to put them right

    • Using nRT with N, or NkT with n.

      Put it right: Pair N with k and n with R.

    • Treating c² as the square of the average speed.

      Put it right: c² is the mean of the squared speeds, which is larger.

    • Forgetting to convert temperature to kelvin.

      Put it right: Add 273 to a Celsius value before substituting.

    • Omitting the 3/2 factor or replacing it with 1/2.

      Put it right: The mean translational kinetic energy is 3/2 kT.

    Exam tips

    • List the known quantities with units before choosing between pV = NkT and pV = nRT.
    • When finding mean-square speed, rearrange ½mc² = 3/2 kT to c² = 3kT/m before substituting.
    • Check that mass is in kilograms and volume in cubic metres so that the pascal is consistent.
    • Use the kelvin scale throughout and state the conversion if a temperature is given in degrees Celsius.

    Try the lesson

    The start of the Ideal gases: (h) pV = NkT; 1/2 mc² = 3/2 kT lesson, made from checked teaching notes for this specification point.

    Listen

    These two equations describe an ideal gas at the particle level. pV = NkT relates pressure p, volume V, number of molecules N, Boltzmann constant k and thermodynamic temperature T; it is the per-particle form of pV = nRT. The second, ½mc² = 3/2 kT, gives the mean translational kinetic energy of a molecule of mass m and mean-square speed c². The factor 3/2 arises because a molecule can move in three independent directions. Combining them shows that temperature alone fixes mean kinetic energy, so at a given T all gas molecules have the same average translational energy regardless of mass, while lighter molecules have higher mean-square speeds. A strong answer earns marks for these points. States pV = NkT and identifies each symbol: p pressure, V volume, N number of molecules, k Boltzmann constant, T temperature in kelvin. States ½mc² = 3/2 kT as the mean translational kinetic energy of a molecule, with c² the mean-square speed. Explains that the 3/2 factor comes from three translational degrees of freedom. Uses the two equations together, for example to show that mean kinetic energy depends only on T. A common slip: Using nRT with N, or NkT with n. Instead, pair N with k and n with R. Exam tip: List the known quantities with units before choosing between pV = NkT and pV = nRT.

    Key words

    Say what each word means before you turn the card.

    pV = NkT

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    ½mc² = 3/2 kT

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    Microscopic interpretation of temperature

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    See every definition
    pV = NkT
    Relates pressure p, volume V, number of molecules N, Boltzmann constant k and thermodynamic temperature T, and is the per-particle form of pV = nRT.
    ½mc² = 3/2 kT
    Gives the mean translational kinetic energy of a molecule of mass m and mean-square speed c².
    Microscopic interpretation of temperature
    Temperature alone fixes mean kinetic energy, so at a given T all gas molecules have the same average translational energy regardless of mass.

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