Distance-time graphs — OCR GCSE Study Guide

 ## Overview Distance-time graphs are a fundamental tool in physics for visually representing an object's journey. For your OCR GCSE exam, they are a gift of marks if you understand the core principles. This topic, specification reference 1.6, is all about the relationship between distance, time, and speed. A significant portion of your exam (60% AO2) is focused on applying your knowledge, and these graphs are a prime testing ground for that skill. You will be expected to interpret the shape of the graph to describe motion and perform calculations to determine speed. Higher tier candidates will also need to demonstrate the ability to find instantaneous speed from a curve by drawing a tangent. This guide will equip you with the techniques to confidently analyse any distance-time graph an examiner throws at you.  ## Key Concepts ### Concept 1: Interpreting the Gradient The single most important concept is that **the gradient (steepness) of a distance-time graph represents the speed of the object**. A steeper line means a faster speed, and a less steep line means a slower speed. This is because the gradient is calculated as the change in the y-axis (distance) divided by the change in the x-axis (time), which is the definition of speed.  * **Horizontal Line**: If the line is flat, the distance is not changing. The object is **stationary**. The gradient is zero, so the speed is 0 m/s. This is a common 1-mark question. * **Straight, Diagonal Line**: This shows the object is travelling at a **constant speed**. The gradient is constant, so the speed is unchanging. * **Curved Line**: A curve indicates that the speed is changing. This is **acceleration** (if the line gets steeper) or **deceleration** (if the line becomes less steep). ### Concept 2: Calculating Speed (Constant) For any straight-line section of the graph, you can calculate the constant speed using the formula: **Speed = Gradient = Change in Distance / Change in Time** To do this, you pick two points on the straight line, read their coordinates, and substitute them into the formula. It is crucial to select points as far apart as possible to minimise measurement errors and improve accuracy.  **Example**: A car travels from a distance of 20m to 80m in the time interval from 2s to 8s. * Change in Distance = 80m - 20m = 60m * Change in Time = 8s - 2s = 6s * Speed = 60m / 6s = 10 m/s ### Concept 3: Instantaneous Speed (Higher Tier Only) When an object is accelerating, its speed is different at every moment. To find the speed at a specific instant (e.g., at t=4s), you cannot simply use the formula above. You must find the **instantaneous speed**. To do this, you must draw a **tangent** to the curve at that specific point in time. A tangent is a straight line that just touches the curve at that one point without crossing it. Once you have accurately drawn the tangent with a ruler, you then calculate the gradient of that tangent. The gradient of the tangent is equal to the instantaneous speed at that point.  ## Mathematical/Scientific Relationships * **Speed, Distance, Time Formula**: `Speed = Distance / Time`. This is the fundamental relationship. It can be rearranged to find distance (`Distance = Speed x Time`) or time (`Time = Distance / Speed`). This formula is given on the formula sheet. * **Gradient Formula**: `Gradient = (y2 - y1) / (x2 - x1)`. In the context of a distance-time graph, this becomes `Speed = (change in distance) / (change in time)`. You **must memorise** how to apply this to the graph. ## Unit Conversions Examiners often try to catch students out with unit conversions. Be vigilant! * **Time**: If time is given in minutes, you must convert it to seconds to get speed in m/s. (1 minute = 60 seconds). * **Distance**: If distance is in kilometres (km), you may need to convert it to metres (m). (1 km = 1000 m). * **Speed**: To convert from km/h to m/s, you divide by 3.6. To convert from m/s to km/h, you multiply by 3.6. This is a useful shortcut but showing the full conversion is safer in an exam.