OCR · GCSE · Physics

    Latent Heat

    Latent heat is the 'hidden' energy transferred during a change of state — melting, freezing, boiling, or condensing — where temperature remains constant despite energy being continuously supplied or released. Mastering this topic means understanding precisely why temperature stays flat on a heating curve, applying the formula E = mL with correct unit conversions, and articulating the particle-level explanation that distinguishes potential energy from kinetic energy. OCR examiners consistently reward candidates who can move fluently between quantitative calculation and qualitative particle-model explanation.

    • 8 min read
    • 4 worked examples
    • 5 practice questions
    • 8 key terms
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    Latent Heat
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    Study Notes

    Latent Heat — OCR GCSE Physics Topic 6.5

    Overview

    Latent heat sits at the heart of OCR GCSE Physics Topic 6.5 and represents one of the most conceptually rich areas of the thermal physics unit. The word 'latent' derives from the Latin latere, meaning 'to lie hidden' — and that etymology captures the central puzzle perfectly: energy is being transferred into or out of a substance, yet the thermometer reading refuses to budge. For candidates who understand the particle model, this is not mysterious at all; it is a precise and elegant consequence of how intermolecular forces work.

    This topic connects directly to the particle model of matter, internal energy, and specific heat capacity — all of which appear elsewhere in the OCR specification. Examiners frequently set synoptic questions that require candidates to distinguish between latent heat and specific heat capacity, or to interpret a full heating curve that spans both concepts. The assessment objective breakdown for this topic is AO1 (30%), AO2 (40%), and AO3 (30%), meaning that application and analysis questions dominate — candidates must be able to use knowledge, not merely recall it.

    Typical exam question styles include: (1) describe and explain a labelled section of a heating curve (2–4 marks); (2) calculate energy using E = mL with a unit conversion trap (3–4 marks); (3) explain in terms of particles why temperature is constant during a state change (3 marks); and (4) required practical questions about measuring specific latent heat using electrical methods (4–6 marks). Candidates who can answer all four styles fluently are well-positioned to achieve top marks.

    The Heating Curve for Water — annotated with particle model diagrams and energy type labels

    Key Concepts

    Concept 1: What is Latent Heat?

    Latent heat is the energy transferred to or from a substance during a change of state, at constant temperature. It is 'latent' — hidden — because it does not manifest as a measurable temperature change. When a solid melts, energy is absorbed from the surroundings; when a liquid freezes, energy is released to the surroundings. In both cases, the temperature of the substance remains constant throughout the entire state change.

    There are two distinct types of specific latent heat that candidates must know:

    • Specific Latent Heat of Fusion (L_f): The energy required to change 1 kg of a substance from solid to liquid (or released when 1 kg changes from liquid to solid) at constant temperature. The term fusion refers to the solid–liquid transition. For water, L_f = 334,000 J/kg.
    • Specific Latent Heat of Vaporisation (L_v): The energy required to change 1 kg of a substance from liquid to gas (or released when 1 kg changes from gas to liquid) at constant temperature. The term vaporisation refers to the liquid–gas transition. For water, L_v = 2,260,000 J/kg.

    Note that the specific latent heat of vaporisation for water is approximately 6.8 times larger than the specific latent heat of fusion. This is because vaporisation requires completely overcoming all intermolecular forces so that particles can escape the liquid entirely, whereas fusion only partially weakens those forces.

    Concept 2: The Particle Model Explanation

    The particle model provides the essential mechanistic explanation that earns marks in 'explain' questions. In a solid, particles are held in fixed positions by strong intermolecular forces (forces of attraction between particles). They vibrate about fixed points but cannot move freely. The temperature of a substance is a measure of the average kinetic energy of its particles — higher temperature means faster-moving particles.

    When a solid is heated to its melting point and energy continues to be supplied, that energy is used to break the intermolecular bonds — to work against the forces of attraction and pull particles further apart. This process increases the potential energy of the particles (they are being separated against an attractive force, analogous to stretching a spring). Crucially, the kinetic energy of the particles does not increase during this process — the particles are not moving faster. Since temperature is determined by kinetic energy, the temperature remains constant.

    Once all intermolecular bonds have been sufficiently weakened and the substance has fully changed state, further energy input once again increases kinetic energy, and the temperature rises.

    The examiner's key distinction: During a state change, internal energy increases because potential energy increases, while kinetic energy remains constant. Temperature does not change because temperature reflects kinetic energy only.

    Particle Model: Three States of Matter and Latent Heat

    Concept 3: Heating and Cooling Curves

    A heating curve plots temperature (y-axis) against time or energy supplied (x-axis) as a substance is heated from below its melting point to above its boiling point. For water, the five distinct sections are:

    SectionTemperature RangeProcessEnergy Change
    1−20°C → 0°CIce heating (solid)KE increases, temperature rises
    20°C (flat)MeltingPE increases, KE constant, temperature constant
    30°C → 100°CWater heating (liquid)KE increases, temperature rises
    4100°C (flat)BoilingPE increases, KE constant, temperature constant
    5>100°CSteam heating (gas)KE increases, temperature rises

    The horizontal (flat) sections are the latent heat regions. The length of the plateau at 100°C is longer than at 0°C because the specific latent heat of vaporisation is much greater than that of fusion — more energy must be supplied before all the liquid has converted to gas.

    A cooling curve is the reverse: a substance cools from gas to solid. The flat sections appear at the same temperatures (100°C and 0°C for water) but now represent energy being released to the surroundings as bonds form.

    Concept 4: The Formula E = mL

    The quantitative relationship for latent heat is:

    E = mLWhere:

    • E = energy transferred (J)
    • m = mass of substance (kg) — must be in kilograms when L is in J/kg
    • L = specific latent heat (J/kg)

    This formula can be rearranged to find any unknown:

    • To find L: L = E ÷ m
    • To find m: m = E ÷ L

    Critical unit conversion: If mass is given in grams, divide by 1000 to convert to kilograms. This is the most frequently penalised error in OCR mark schemes. Always write the conversion as an explicit step in your working.

    Formula status: E = mL must be memorised — it is not provided on the OCR formula sheet.

    Mathematical/Scientific Relationships

    FormulaVariablesWhen to UseStatus
    E = mLE (J), m (kg), L (J/kg)Change of state (constant temperature)Must memorise
    E = mcΔTE (J), m (kg), c (J/kg°C), ΔT (°C)Temperature change (no state change)Given on formula sheet

    Unit Conversions Candidates Commonly Get Wrong:

    • Grams to kilograms: divide by 1000 (e.g., 500 g = 0.5 kg)
    • Kilojoules to joules: multiply by 1000 (e.g., 167 kJ = 167,000 J)
    • If L is given in J/g (rare), keep mass in grams — do NOT convert

    Practical Applications

    Required Practical: Measuring Specific Latent Heat of Fusion of IceThis required practical is a favourite for OCR exam questions. Candidates must know the method, expected results, and sources of error.

    Apparatus: Crushed ice, beaker, immersion heater (or heating coil), joulemeter (or ammeter and voltmeter and stopwatch), balance, thermometer.

    Method: (1) Weigh a known mass of crushed ice in a beaker. (2) Record the initial mass. (3) Connect the immersion heater and record the energy supplied using a joulemeter, or calculate E = IVt using ammeter, voltmeter, and stopwatch. (4) Allow the ice to melt completely. (5) Record the mass of water remaining. (6) Calculate the mass of ice melted (m = final mass − mass of water that was already liquid). (7) Calculate L = E ÷ m.

    Expected result: L_f ≈ 334,000 J/kg for water.

    Common errors: Not accounting for ice that melted before the heater was switched on (control experiment needed); heat losses to surroundings causing an overestimate of E; not ensuring all ice has melted before taking the final mass reading.

    How examiners test it: Questions may ask candidates to identify a source of error and explain how it affects the calculated value of L, or to suggest an improvement to the method.

    Real-World Applications of Latent Heat:

    • Sweating: evaporation of sweat from skin absorbs latent heat of vaporisation, cooling the body
    • Refrigerators: refrigerant fluid evaporates inside the fridge (absorbing latent heat, cooling the interior) and condenses outside (releasing latent heat)
    • Ice packs in sports medicine: melting ice absorbs large amounts of energy from an injury site
    • Steam burns: steam at 100°C releases latent heat of vaporisation when it condenses on skin, causing more severe burns than liquid water at 100°C

    Visual Resources

    2 diagrams and illustrations

    The Heating Curve for Water — annotated with particle model diagrams and energy type labels
    The Heating Curve for Water — annotated with particle model diagrams and energy type labels
    Particle Model: Three States of Matter and Latent Heat
    Particle Model: Three States of Matter and Latent Heat

    Interactive Diagrams

    3 interactive diagrams to visualise key concepts

    Conceptual Flow Outline

    🔵 SOLID\nParticles in fixed positions\nVibrating only
    ➔"Energy supplied → breaks intermolecular bonds\nLatent Heat of FUSION absorbed\nTemperature stays constant at melting point"🟢 LIQUID\nParticles close but mobile\nCan flow
    🟢 LIQUID\nParticles close but mobile\nCan flow
    ➔"Energy supplied → overcomes all intermolecular forces\nLatent Heat of VAPORISATION absorbed\nTemperature stays constant at boiling point"🟠 GAS\nParticles far apart\nMove freely at high speed
    ➔"Energy released → intermolecular bonds reform\nLatent Heat of FUSION released\nFreezing"🔵 SOLID\nParticles in fixed positions\nVibrating only
    🟠 GAS\nParticles far apart\nMove freely at high speed
    ➔"Energy released → intermolecular forces reform\nLatent Heat of VAPORISATION released\nCondensation"🟢 LIQUID\nParticles close but mobile\nCan flow

    State change diagram showing the transitions between solid, liquid, and gas, with the type of latent heat involved and the direction of energy transfer for each transition. Arrows going right (solid→liquid→gas) represent energy absorption; arrows going left (gas→liquid→solid) represent energy release.

    Conceptual Flow Outline

    ["Question involves thermal energy"]
    ➔Is there a\nchange of state?
    Is there a\nchange of state?
    ➔"YES — melting, boiling,\nfreezing, condensing"Use E = mL\nCheck: is mass in kg?\nIs L in J/kg?
    ➔"NO — temperature\nis changing"Use E = mcΔT\nCheck: is ΔT in °C or K?
    Use E = mL\nCheck: is mass in kg?\nIs L in J/kg?
    ➔Mass in grams?
    Use E = mcΔT\nCheck: is ΔT in °C or K?
    ➔Substitute into E = mcΔT\nCalculate E in Joules
    Mass in grams?
    ➔"YES"Divide by 1000\nto get kg
    ➔"NO"Substitute into E = mL\nCalculate E in Joules
    Divide by 1000\nto get kg
    ➔Substitute into E = mL\nCalculate E in Joules
    Substitute into E = mL\nCalculate E in Joules
    ➔State answer with units (J or kJ)
    Substitute into E = mcΔT\nCalculate E in Joules
    ➔State answer with units (J or kJ)

    Decision flowchart for choosing between E = mL and E = mcΔT, including the critical unit conversion check. Use this as a mental checklist before every thermal energy calculation.

    Conceptual Flow Outline

    Section 1\nSolid ice heating\n−20°C → 0°C\nKE increases
    ➔Section 2 — FLAT\nMelting at 0°C\nPE increases\nKE constant
    Section 2 — FLAT\nMelting at 0°C\nPE increases\nKE constant
    ➔Section 3\nLiquid water heating\n0°C → 100°C\nKE increases
    Section 3\nLiquid water heating\n0°C → 100°C\nKE increases
    ➔Section 4 — FLAT\nBoiling at 100°C\nPE increases\nKE constant
    Section 4 — FLAT\nBoiling at 100°C\nPE increases\nKE constant
    ➔Section 5\nSteam heating\n>100°C\nKE increases

    Annotated heating curve sections for water, showing which sections involve kinetic energy (KE) increases (temperature rising) and which involve potential energy (PE) increases (temperature constant). Red sections = latent heat regions.

    Worked Examples

    4 worked examples — open one to explore the question and available guidance.

    Practice Questions

    Test your understanding — click to reveal model answers

    Q1

    State what is meant by the term 'specific latent heat of fusion.' [2 marks]

    2 marks
    foundation

    Hint: Think about what 'specific' means (per kilogram) and what 'fusion' refers to (which state change).

    Q2

    A student heats 0.50 kg of water from 20°C to 100°C and then continues heating until all the water has turned to steam. The specific heat capacity of water is 4,200 J/kg°C and the specific latent heat of vaporisation of water is 2,260,000 J/kg. Calculate the total energy required. [5 marks]

    5 marks
    standard

    Hint: This question has two parts: heating the water (use E = mcΔT) and then boiling it (use E = mL). Calculate each separately, then add them together.

    Q3

    Explain, using the particle model, why the temperature of water remains constant at 100°C while it is boiling, even though energy is continuously being supplied. [3 marks]

    3 marks
    standard

    Hint: Think about what happens to the intermolecular forces during boiling, and how this relates to kinetic energy and potential energy.

    Q4

    A 1.5 kW heater is used to melt a block of a metal. The metal has a melting point of 232°C and is already at 232°C when the heater is switched on. After 6 minutes and 40 seconds, 0.80 kg of the metal has melted. Calculate the specific latent heat of fusion of the metal. [4 marks]

    4 marks
    challenging

    Hint: First calculate the total energy supplied by the heater (E = Pt, but convert time to seconds first). Then rearrange E = mL to find L.

    Q5

    A student claims: 'When ice melts, the internal energy of the water increases because the kinetic energy of the particles increases.' Evaluate this claim. [3 marks]

    3 marks
    challenging

    Hint: Consider whether the claim is correct, partially correct, or incorrect. Think about what actually happens to kinetic energy and potential energy during melting, and what 'internal energy' consists of.

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